For 2x2+4x−1=02x^2 + 4x - 1 = 02x2+4x−1=0, show that b2−4ac=24b^2-4ac=24b2−4ac=24.
Hence solve 2x2+4x−1=02x^2 + 4x - 1 = 02x2+4x−1=0
Give your solutions correct to 2 decimal places.
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