Show that 7+332+3\displaystyle \frac{7 + 3\sqrt{3}}{2 + \sqrt{3}}2+37+33 can be written as 5−35 - \sqrt{3}5−3
Hence, show that (7+332+3)2\displaystyle \left(\frac{7 + 3\sqrt{3}}{2 + \sqrt{3}}\right)^2(2+37+33)2 can be written as 28−10328 - 10\sqrt{3}28−103
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