Show that k3+33+3\displaystyle \frac{k\sqrt{3} + 3}{3 + \sqrt{3}}3+3k3+3 can be written as (k−1)3+3−k2\displaystyle \frac{(k - 1)\sqrt{3} + 3 - k}{2}2(k−1)3+3−k
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Surds Questions
217 exam-style questions on Eduqas GCSE Maths Surds. Each one has a worked solution and a mark scheme showing where the marks go.