y $m$ and the y-intercept is represented by $c$.","points":null},{"id":"17741f8b-ef6c-46ef-aae2-76c9a02d8153","cardType":"cloze","front":"In the straight-line equation $y=mx+c$, the gradient is represented by $m$ and the [ ] is represented by $c$.","back":"In the straight-line equation $y=mx+c$, the gradient is represented by $m$ and the y-intercept is represented by $c$.","points":null},{"id":"79d29c10-a9fc-4baa-adfe-dcedbcb2b136","cardType":"basic","front":"How do you find the gradient of a line given the equation $2x+5y=10$?","back":"Rearrange the equation to make $y$ the subject ($y=mx+c$) before reading the coefficient of $x$.","points":2},{"id":"c236471c-3f8b-4f5f-8763-59fe0651d8fd","cardType":"basic","front":"What is the gradient and y-intercept of the line $6y=3x-12$?","back":"

Gradient: $1/2$
y-intercept: $-2$

","points":2},{"id":"ad5ddfd5-f1ab-438b-a6f1-002667e247f9","cardType":"basic","front":"What is the relationship between the gradients of two parallel lines?","back":"They have the same gradient.","points":1},{"id":"ce501f26-e240-4ed1-8fec-c585f4a4fa49","cardType":"basic","front":"A line is parallel to $y=3x+1$ and has no specific point given. Give one possible equation.","back":"Any equation in the form $y=3x+c$ where $c \\neq 1$ (e.g. $y=3x-4$).","points":1},{"id":"e537bc58-079c-491a-8d9c-f03cd3041d31","cardType":"basic","front":"What is the relationship between the gradients $m_1$ and $m_2$ of two perpendicular lines?","back":"They are negative reciprocals ($m_1 \\times m_2 = -1$).","points":1},{"id":"c0a31420-9946-4b8e-8400-6da5e2c48f37","cardType":"basic","front":"What is the negative reciprocal of 4?","back":"$-1/4$","points":1},{"id":"0a1f86a9-b079-4682-837f-12c5d5f6c26b","cardType":"basic","front":"What is the negative reciprocal of $-2/3$?","back":"$3/2$","points":1},{"id":"fcab2999-9f6d-4583-85ad-b80ae37eba05","cardType":"cloze","front":"To find the gradient of a line perpendicular to $y=mx+c$, you must [ ] and change the sign.","back":"To find the gradient of a line perpendicular to $y=mx+c$, you must flip the fraction and change the sign.","points":null},{"id":"c620a9ee-bc09-46b4-a567-e29c3ee5f168","cardType":"cloze","front":"To find the gradient of a line perpendicular to $y=mx+c$, you must flip the fraction and [ ].","back":"To find the gradient of a line perpendicular to $y=mx+c$, you must flip the fraction and change the sign.","points":null},{"id":"b6d639cb-176d-4add-b46e-3ec9bbbbb1c4","cardType":"basic","front":"What type of line is perpendicular to the horizontal line $y=4$?","back":"A vertical line (e.g. $x=-1$).","points":1},{"id":"f74227d0-5abc-4a4d-a86b-7635a7c734cb","cardType":"basic","front":"State the formula for the gradient ($m$) between two points $(x_1, y_1)$ and $(x_2, y_2)$.","back":"$$m = \\frac{y_2 - y_1}{x_2 - x_1}$$","points":1},{"id":"00bfa38c-b2bb-461a-a28a-7647319cfd8b","cardType":"cloze","front":"When calculating gradient, the [ ] must be the numerator and the change in $x$ must be the denominator.","back":"When calculating gradient, the change in $y$ must be the numerator and the change in $x$ must be the denominator.","points":null},{"id":"c86ac74a-c2aa-4579-98a1-3d03a9302322","cardType":"cloze","front":"When calculating gradient, the change in $y$ must be the numerator and the [ ] must be the denominator.","back":"When calculating grad

Parallel and Perpendicular Lines Flashcards

Parallel and Perpendicular Lines Flashcards

Parallel and Perpendicular Lines Flashcards

Parallel and Perpendicular Lines Flashcards