Show that (4x−3)(2x+5)(3x−1)=24x3+34x2−59x+15(4x - 3)(2x + 5)(3x - 1) = 24x^3 + 34x^2 - 59x + 15(4x−3)(2x+5)(3x−1)=24x3+34x2−59x+15 for all values of xxx.
Hence solve 24x3+34x2−59x+15=024x^3 + 34x^2 - 59x + 15 = 024x3+34x2−59x+15=0.
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