Show that (3x−1)(4x+3)(x−9)=12x3−103x2−48x+27(3x - 1)(4x + 3)(x - 9) = 12x^3 - 103x^2 - 48x + 27(3x−1)(4x+3)(x−9)=12x3−103x2−48x+27 for all values of xxx.
Hence, find the value of 12x3−103x2−48x+2712x^3 - 103x^2 - 48x + 2712x3−103x2−48x+27 when x=2x=2x=2.
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