Show that (6x−5)(2x+3)(4x−1)=48x3+20x2−68x+15(6x - 5)(2x + 3)(4x - 1) = 48x^3 + 20x^2 - 68x + 15(6x−5)(2x+3)(4x−1)=48x3+20x2−68x+15 for all values of xxx.
225 exam-style questions on Eduqas GCSE Maths Expanding Triple Brackets. Each one has a worked solution and a mark scheme showing where the marks go.