Algebraic Fractions

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Question 46
Hard

Simplify fully 3x+3x+6÷x2−3x−42x2+17x+30\displaystyle \frac{3x+3}{x+6} \div \frac{x^2-3x-4}{2x^2+17x+30}x+63x+3​÷2x2+17x+30x2−3x−4​

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Algebraic Fractions Questions

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