Show that, after multiplying by the common denominator,
83x−2+6x+1=2 \frac{8}{3x - 2} + \frac{6}{x + 1} = 2 3x−28+x+16=2becomes
8(x+1)+6(3x−2)=2(3x−2)(x+1). 8(x+1) + 6(3x-2) = 2(3x-2)(x+1). 8(x+1)+6(3x−2)=2(3x−2)(x+1).Hence solve
83x−2+6x+1=2 \frac{8}{3x - 2} + \frac{6}{x + 1} = 2 3x−28+x+16=2255 exam-style questions on Edexcel GCSE Maths Algebraic Fractions. Each one has a worked solution and a mark scheme showing where the marks go.