Using xn+1=15xn2+4\displaystyle x_{n+1} = \frac{15}{x_n^2 + 4}xn+1=xn2+415 with x0=1x_0 = 1x0=1
Find the values of x1x_1x1, x2 x_2\,x2 and x3x_3x3.
Practise Edexcel GCSE Maths Iteration with exam-style questions for Foundation and Higher tier. 40 questions, matched to the Edexcel GCSE Maths (1MA1) specification and written in Paper 1, Paper 2 and Paper 3 style. Every question includes a full worked solution and mark scheme, so you can see where marks are awarded rather than just whether you got the answer right.