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3D line drawing of a cuboid ABCDEFGH.](https://assets.mathsgenie.co.uk/booklet/22a6497dc5246ebf26bea97859e04bd38ce72a9b00ea9b8a68be2608afc7d4d7.jpg)\n\nThe diagram shows a cuboid $ABCDEFGH$. $ABCD$ is a square with area $25 \\text{ cm}^2$. $CG = 12 \\text{ cm}$.","difficulty":1,"difficultyBand":"medium","totalMarks":2,"sourceTitle":"Volume of a Prism","calculatorUse":"non_calc","isCalculation":true,"parts":[{"id":"fe4d52ea-8a25-45f8-a27d-85e9608bdf78","label":"0","content":"Find the volume of the cuboid.","markscheme":"- Volume = $25 \\times 12$ M1\n- Final answer = $300 \\text{ cm}^3$ A1","marks":2,"order":0,"markingRubric":{"totalMarks":2,"points":[{"id":"p1","marks":1,"description":"Multiplies the base area (25) by the height (12).","code":"M"},{"id":"p2","marks":1,"description":"Final answer of 300.","code":"A"}],"finalAnswers":["300"],"generatedAt":"2026-05-06T11:03:31.583Z","modelVersion":"gemini-3-flash-preview"},"tableImages":[],"explanation":{"methods":[{"id":"base_area_times_length","label":"Base area × length","steps":[{"type":"text","order":0,"title":"Identify the measurements","content":"For a cuboid, use\n\n$$\\text{volume}=\\text{area of cross-section}\\times\\text{perpendicular length}.$$\n\nHere, the square $ABCD$ is the cross-section, with area $25\\text{ cm}^2$, and $CG$ is the perpendicular length, measuring $12\\text{ cm}$. There is no need to find the side length of the square.","highlights":[{"text":"$$ABCD$ is a square with area $25 \\text{ cm}^2$","location":"specification"},{"text":"$$CG = 12 \\text{ cm}$","location":"specification"}]},{"type":"hyper_latex","block":{"nodes":[{"latex":"$$V=\\color{@sky}{\\htmlData{anchor=base_area}{A}}\\times\\color{@orange}{\\htmlData{anchor=height}{h}}$"},{"latex":"$$V=\\color{@sky}{\\htmlData{anchor=area_value}{25}}\\times\\color{@orange}{\\htmlData{anchor=height_value}{12}}$"}],"highlights":[{"color":"sky","style":"text-color","anchor":"base_area"},{"color":"sky","style":"text-color","anchor":"area_value"},{"color":"orange","style":"text-color","anchor":"height"},{"color":"orange","style":"text-color","anchor":"height_value"}]},"order":1,"title":"Substitute the values","description":"Use the area of square ABCD as the base area and CG as the perpendicular height. This substitution earns M1."},{"type":"text","order":2,"title":"Calculate and state units","content":"Calculate the product:\n\n$$V=300\\text{ cm}^3.$$\n\nThe units are cubic centimetres because an area in $\\text{cm}^2$ is multiplied by a length in $\\text{cm}$. The correct value and unit earn A1."}]}],"generatedAt":"2026-07-20T10:42:26.708Z","modelVersion":"gpt-5.6-sol","explanationVersion":"v3"},"options":[]}],"options":[],"explanation":{"methods":[{"id":"fe4d52ea-8a25-45f8-a27d-85e9608bdf78:direct_formula","label":"Direct Formula","steps":[{"type":"text","order":0,"title":"Identify the formula","content":"To find the volume of a cuboid (or any prism), we can multiply its base area by its height:\n\n$$\\text{Volume} = \\text{Base Area} \\times \\text{Height}$$"},{"type":"text","order":1,"title":"Identify the given values","content":"From the question, we are given:\n- The base area of the square $ABCD = 25 \\text{ cm}^2$\n- The height of the cuboid $CG = 12 \\text{ cm}$","highlights":[{"text":"ABCD is a square with area 25 cm^2","location":"specification"},{"text":"CG = 12 cm","location":"specification"}]},{"type":"text","order":2,"title":"Calculate the volume","content":"Substitute these values into our volume formula:\n\n$$\\begin{aligned} \\text{Volume} &= 25 \\times 12 \\\\ &= 300 \\text{ cm}^3 \\end{aligned}$$\n\n*This calculation earns you the first mark (M1) for showing the correct method of multiplication, and the final mark (A1) for the correct answer.*"}]},{"id":"fe4d52ea-8a25-45f8-a27d-85e9608bdf78:side_lengths","label":"Using Side Lengths","steps":[{"type":"text","order":0,"title":"Identify given dimensions","content":"From the question, we are given:\n- The base $ABCD$ is a square with an area of $25 \\text{ cm}^2$.\n- The height of the cuboid ($CG$) is $12 \\text{ cm}$.\n\nTo find the volume of the cuboid, we will first find the side lengths of the square base.","highlights":[{"text":"ABCD is a square with area 25 cm^2","location":"specification"},{"text":"CG = 12 cm","location":"specification"}]},{"type":"hyper_latex","block":{"nodes":[{"latex":"$$s = \\sqrt{\\htmlData{anchor=area-val}{\\color{@sky}{25}}} = \\htmlData{anchor=side-val}{\\color{@amber}{5}} \\text{ cm}$"}],"highlights":[{"color":"sky","style":"text-color","anchor":"area-val"},{"color":"amber","style":"text-color","anchor":"side-val"}],"connections":[{"to":"side-val","from":"area-val","color":"amber","label":"square root","style":"solid"}]},"order":1,"title":"Find the side length","description":"Since the base $ABCD$ is a square, both its length and width are equal. We can find this side length, $s$, by taking the square root of its area:\n\n$$\\text{Side Length} = \\sqrt{25} = 5 \\text{ cm}$$"},{"type":"text","order":2,"title":"Calculate the volume","content":"Now we can calculate the volume of the cuboid using the formula:\n\n$$\\text{Volume} = \\text{length} \\times \\text{width} \\times \\text{height}$$\n\nSubstituting our values into the formula:\n\n$$\\text{Volume} = 5 \\times 5 \\times 12$$\n\n$$\\text{Volume} = 25 \\times 12 = 300 \\text{ cm}^3$$"}]}],"generatedAt":"2026-06-12T22:41:34.712Z","modelVersion":"gemini-3.5-flash","explanationVersion":"v2"},"firstAttemptFullMarks":null,"walkthroughVideo":null},{"id":"8eb01c1e-e245-446f-8781-ffb59904ab35","revisionId":"0828bc4d-0e4f-490d-a945-e2be4cc61e68","questionNumber":"7","questionType":"LA","specification":"![Diagram of a cuboid with dimensions 12 cm, 4 cm, and x cm.](https://assets.mathsgenie.co.uk/booklet/3753e5049a541a5581c9d456dcfbe54cbcb8dba6ff16ef58b9de5c554748e2b2.jpg)\n\nThe volume of the cuboid is $120 \\text{ cm}^3$.","difficulty":1,"difficultyBand":"medium","totalMarks":2,"sourceTitle":"Volume of a Prism","calculatorUse":"non_calc","isCalculation":true,"parts":[{"id":"4b9805af-5187-4a80-8566-298941777809","label":"0","content":"Calculate the value of $x$","markscheme":"- $4 \\times 12 \\times x = 120$ M1\n- $48x = 120 \\implies x = 2.5$ A1","marks":2,"order":0,"markingRubric":{"totalMarks":2,"points":[{"id":"p1","marks":1,"description":"Sets up an equation for volume: $4 \\times 12 \\times x = 120$.","code":"M"},{"id":"p2","marks":1,"description":"Solves for $x$ to get 2.5.","code":"A"}],"finalAnswers":["2.5"],"generatedAt":"2026-05-06T11:03:31.583Z","modelVersion":"gemini-3-flash-preview"},"tableImages":[],"explanation":{"methods":[{"id":"use_cuboid_volume","label":"Use the cuboid volume","steps":[{"type":"text","order":0,"title":"Recall the formula","content":"The volume of a cuboid is found by multiplying its three dimensions:\n\n$$\\text{volume}=\\text{length}\\times\\text{width}\\times\\text{height}$$\n\nHere, the dimensions are $12\\text{ cm}$, $4\\text{ cm}$ and $x\\text{ cm}$.","highlights":[{"text":"The volume of the cuboid is $120 \\text{ cm}^3$.","location":"specification"}]},{"type":"hyper_latex","block":{"nodes":[{"latex":"$$4\\times 12\\times x=120$"},{"latex":"$$48x=120$"}]},"order":1,"title":"Form the equation","description":"Substitute the three dimensions and the given volume into the cuboid formula. Writing this equation earns the method mark (M1). Multiply the known lengths to simplify it."},{"type":"hyper_latex","block":{"nodes":[{"latex":"$$48x=120$"},{"latex":"$$x=\\dfrac{120}{48}$"},{"latex":"$$x=2.5$"}]},"order":2,"title":"Divide to find x","description":"Divide both sides by 48, then calculate. Obtaining x = 2.5 earns the accuracy mark (A1). Therefore x = 2.5, so the missing length is 2.5 cm."}]}],"generatedAt":"2026-07-20T10:30:23.838Z","modelVersion":"gpt-5.6-sol","explanationVersion":"v3"},"options":[]}],"options":[],"explanation":{"methods":[{"id":"4b9805af-5187-4a80-8566-298941777809:algebraicequation","label":"Algebraic Equation Method","steps":[{"type":"text","order":0,"title":"Recall the volume formula","content":"To find the unknown length $x$, we start with the formula for the volume ($V$) of a cuboid:\n\n$$V = \\text{length} \\times \\text{width} \\times \\text{height}$$"},{"type":"hyper_latex","block":{"nodes":[{"latex":"$$\\text{length} = \\htmlData{anchor=l-val}{\\color{@sky}{12}} \\text{ cm}, \\quad \\text{width} = \\htmlData{anchor=w-val}{\\color{@amber}{4}} \\text{ cm}, \\quad \\text{height} = \\htmlData{anchor=h-val}{\\color{@purple}{x}} \\text{ cm}$"},{"latex":"$$\\text{Volume } (V) = \\htmlData{anchor=v-val}{\\color{@teal}{120}} \\text{ cm}^3$"},{"latex":"$$$\\htmlData{anchor=v-eq}{\\color{@teal}{120}} = \\htmlData{anchor=l-sub}{\\color{@sky}{12}} \\times \\htmlData{anchor=w-sub}{\\color{@amber}{4}} \\times \\htmlData{anchor=h-sub}{\\color{@purple}{x}}$$"}],"highlights":[{"color":"sky","style":"text-color","anchor":"l-val"},{"color":"amber","style":"text-color","anchor":"w-val"},{"color":"purple","style":"text-color","anchor":"h-val"},{"color":"teal","style":"text-color","anchor":"v-val"}],"connections":[{"to":"l-sub","from":"l-val","color":"sky","label":null,"style":"solid"},{"to":"w-sub","from":"w-val","color":"amber","label":null,"style":"solid"},{"to":"h-sub","from":"h-val","color":"purple","label":null,"style":"solid"},{"to":"v-eq","from":"v-val","color":"teal","label":null,"style":"solid"}]},"order":1,"title":"Substitute the given values","description":"Substitute the known dimensions and volume into our equation. This gives us the equation we need to solve to earn the first mark."},{"type":"text","order":2,"title":"Simplify the equation","content":"First, simplify the multiplication on the right-hand side of the equation:\n\n$$120 = 48x$$\n\n*(This step sets up the equation clearly for solving!)*"},{"type":"text","order":3,"title":"Solve for x","content":"To isolate $x$, divide both sides of the equation by $48$:\n\n$$\\begin{aligned} x &= \\frac{120}{48} \\\\ x &= 2.5 \\end{aligned}$$\n\nThus, the value of $x$ is $2.5\\text{ cm}$.","calculator":[{"gdc":{"expression":"120/48","instructions":"Type `120 / 48` on the calculation screen and press [ENTER]."},"ti84":{"expression":"120/48","instructions":"Type `120 / 48` on the home screen and press [ENTER]."},"desmos":{"expression":"120/48","instructions":"Type `120/48` in the expression box to see the result."},"description":"Calculate the division to find the exact decimal value of $x$."}]}]},{"id":"4b9805af-5187-4a80-8566-298941777809:crosssectionalarea","label":"Base Area Division Method","steps":[{"type":"text","order":0,"title":"Identify the given values","content":"From the problem, we are given the following information about the cuboid:\n- Volume = $120 \\text{ cm}^3$\n- Base length = $12 \\text{ cm}$\n- Base width = $4 \\text{ cm}$\n- Height = $x \\text{ cm}$\n\nWe will find $x$ by first calculating the area of the rectangular base, and then dividing the total volume by this base area."},{"type":"hyper_latex","block":{"nodes":[{"latex":"$$\\text{Base Area} = \\htmlData{anchor=length}{\\color{@sky}{12}} \\times \\htmlData{anchor=width}{\\color{@amber}{4}}$"},{"latex":"$$\\text{Base Area} = \\htmlData{anchor=area-val}{\\color{@purple}{48}} \\text{ cm}^2$"}],"highlights":[{"color":"sky","style":"text-color","anchor":"length"},{"color":"amber","style":"text-color","anchor":"width"},{"color":"purple","style":"text-color","anchor":"area-val"}],"connections":[{"to":"area-val","from":"length","color":"sky","label":null,"style":"solid"},{"to":"area-val","from":"width","color":"amber","label":null,"style":"solid"}]},"order":1,"title":"Calculate the base area","description":"We find the area of the rectangular base by multiplying the length by the width."},{"type":"hyper_latex","block":{"nodes":[{"latex":"$$x = \\frac{\\htmlData{anchor=vol-val}{\\color{@green}{120}}}{\\htmlData{anchor=area-sub}{\\color{@purple}{48}}}$"},{"latex":"$$x = \\htmlData{anchor=x-val}{\\color{@orange}{2.5}} \\text{ cm}$"}],"highlights":[{"color":"green","style":"text-color","anchor":"vol-val"},{"color":"purple","style":"text-color","anchor":"area-sub"},{"color":"orange","style":"text-color","anchor":"x-val"}],"connections":[{"to":"x-val","from":"area-sub","color":"purple","label":null,"style":"solid"},{"to":"x-val","from":"vol-val","color":"green","label":null,"style":"solid"}]},"order":2,"title":"Divide volume by base","description":"Since $\\text{Volume} = \\text{Base Area} \\times \\text{Height}$, we can find the height $x$ by dividing the volume of $120 \\text{ cm}^3$ by the base area of $48 \\text{ cm}^2$."},{"type":"text","order":3,"title":"State final answer","content":"The height of the cuboid is:\n\n$$x = 2.5 \\text{ cm}$$\n\nThis matches the markscheme requirement where setting up the equation earns the first mark (M1) and finding the correct answer of $2.5$ earns the second mark (A1)."}]}],"generatedAt":"2026-06-12T22:48:41.028Z","modelVersion":"gemini-3.5-flash","explanationVersion":"v2"},"firstAttemptFullMarks":null,"walkthroughVideo":null},{"id":"2763eb0d-5630-419f-906e-b5d2076d2775","revisionId":"2a4e141c-561f-4626-8abf-a5771c6f01bb","questionNumber":"9","questionType":"LA","specification":"![A 3D diagram of a cube with side lengths labeled 3 cm.](https://assets.mathsgenie.co.uk/booklet/09a93a52ea5cb3615e726921beb4423c42f123f163e29d6458bcaf1f6a7e5a1a.jpg)\n\nHere is a cube.","difficulty":1,"difficultyBand":"medium","totalMarks":2,"sourceTitle":"Volume of a Prism","calculatorUse":"non_calc","isCalculation":true,"parts":[{"id":"c9c2ecec-0958-4c0d-91de-3fb05295df25","label":"0","content":"Work out the volume of five of these cubes.","markscheme":"- Volume of one cube = $3 \\times 3 \\times 3 = 27 \\text{ cm}^3$ M1\n- Volume of five cubes = $27 \\times 5 = 135 \\text{ cm}^3$ A1","marks":2,"order":0,"markingRubric":{"totalMarks":2,"points":[{"id":"p1","marks":1,"description":"Calculates the volume of a single cube ($3^3$).","code":"M"},{"id":"p2","marks":1,"description":"Multiplies the single volume by 5 to get 135.","code":"A"}],"finalAnswers":["135"],"generatedAt":"2026-05-06T11:03:31.583Z","modelVersion":"gemini-3-flash-preview"},"tableImages":[],"explanation":{"methods":[{"id":"volume_then_multiply","label":"Find one, then five","steps":[{"type":"text","order":0,"title":"Identify every dimension","content":"A cube has equal length, width and height. The diagram gives a side length of $3\\text{ cm}$, so all three dimensions are $3\\text{ cm}$."},{"type":"hyper_latex","block":{"nodes":[{"latex":"$$V=\\color{@sky}{\\htmlData{anchor=one_calc}{3\\times3\\times3}}$"},{"latex":"$$V=\\color{@green}{\\htmlData{anchor=one_volume}{27\\text{ cm}^3}}$"}],"connections":[{"to":"one_volume","from":"one_calc","color":"green","label":"multiply"}]},"order":1,"title":"Find one cube","description":"Multiply length, width and height. Writing this calculation earns the M1 mark."},{"type":"hyper_latex","block":{"nodes":[{"latex":"$$V_{\\text{five}}=\\color{@sky}{\\htmlData{anchor=five_calc}{27\\times5}}$"},{"latex":"$$V_{\\text{five}}=\\color{@green}{\\htmlData{anchor=five_volume}{135\\text{ cm}^3}}$"}],"connections":[{"to":"five_volume","from":"five_calc","color":"green","label":"multiply"}]},"order":2,"title":"Find five cubes","description":"There are five identical cubes, so multiply the volume of one cube by five. The correct final value with cubic units earns the A1 mark."}]}],"generatedAt":"2026-07-19T06:59:06.299Z","modelVersion":"gpt-5.6-sol","explanationVersion":"v3"},"options":[]}],"options":[],"explanation":{"methods":[{"id":"c9c2ecec-0958-4c0d-91de-3fb05295df25:single_cube_first","label":"Volume of One Cube First","steps":[{"type":"text","order":0,"title":"Calculate volume of one cube","content":"To find the volume of a single cube, we multiply its length, width, and height. Since it is a cube, all its side lengths are equal to $3\\text{ cm}$:\n\n$$\\text{Volume of one cube} = 3\\text{ cm} \\times 3\\text{ cm} \\times 3\\text{ cm} = 27\\text{ cm}^3$$\n\nFinding the volume of one cube correctly awards you the first method mark (**M1**).","highlights":[{"text":"cube with side lengths labeled 3 cm","location":"specification"}]},{"type":"text","order":1,"title":"Multiply by five","content":"Now that we know one cube has a volume of $27\\text{ cm}^3$, we can find the total volume of five identical cubes by multiplying this value by $5$:\n\n$$\\text{Total Volume} = 27\\text{ cm}^3 \\times 5 = 135\\text{ cm}^3$$\n\nThis final step awards you the accuracy mark (**A1**).","highlights":[{"text":"five of these cubes","location":"specification"}]}]},{"id":"c9c2ecec-0958-4c0d-91de-3fb05295df25:combined_cuboid","label":"Combined Cuboid Method","steps":[{"type":"text","order":0,"title":"Visualize the combined cuboid","content":"Instead of finding the volume of one cube and multiplying by $5$, we can imagine placing all $5$ cubes side-by-side in a row.\n\nSince each cube has side lengths of $3\\text{ cm}$:\n- The height of the combined shape is $3\\text{ cm}$.\n- The width of the combined shape is $3\\text{ cm}$.\n- The total length of the $5$ cubes placed end-to-end is:\n $$3\\text{ cm} \\times 5 = 15\\text{ cm}$$\n\nThis forms one large cuboid with dimensions $15\\text{ cm} \\times 3\\text{ cm} \times 3\\text{ cm}$."},{"type":"hyper_latex","block":{"nodes":[{"latex":"$$V = \\htmlData{anchor=length}{\\color{@sky}{\\text{length}}} \\times \\htmlData{anchor=width}{\\color{@amber}{\\text{width}}} \\times \\htmlData{anchor=height}{\\color{@purple}{\\text{height}}}$"},{"latex":"$$V = \\htmlData{anchor=len-val}{\\color{@sky}{15}} \\times \\htmlData{anchor=wid-val}{\\color{@amber}{3}} \\times \\htmlData{anchor=hgt-val}{\\color{@purple}{3}}$"},{"latex":"$$V = 135\\text{ cm}^3$"}],"highlights":[{"color":"sky","style":"text-color","anchor":"length"},{"color":"amber","style":"text-color","anchor":"width"},{"color":"purple","style":"text-color","anchor":"height"}],"connections":[{"to":"len-val","from":"length","color":"sky","label":null,"style":"solid"},{"to":"wid-val","from":"width","color":"amber","label":null,"style":"solid"},{"to":"hgt-val","from":"height","color":"purple","label":null,"style":"solid"}]},"order":1,"title":"Calculate the total volume","description":"Now, we can find the volume ($V$) of this combined cuboid directly by multiplying its length, width, and height."},{"type":"text","order":2,"title":"State the final answer","content":"The total volume of the five cubes is:\n\n$$\\mathbf{135\\text{ cm}^3}$$\n\n*(Note: On the markscheme, you receive **1 method mark** for showing the equivalent dimensions/multiplication step, and **1 accuracy mark** for the correct final answer of $135$)*"}]}],"generatedAt":"2026-06-12T12:23:48.439Z","modelVersion":"gemini-3.5-flash","explanationVersion":"v2"},"firstAttemptFullMarks":null,"walkthroughVideo":null}],"subjectCode":"gcse_maths","summaries":[{"id":"2a3d6ef8-7586-4251-b376-479b6c5e2648","difficultyBand":"hard","calculatorUse":"non_calc","totalMarks":4,"questionType":"LA","isCalculation":true},{"id":"39d12c3d-1888-4b48-9f69-f3b6610e7922","difficultyBand":"medium","calculatorUse":"non_calc","totalMarks":2,"questionType":"LA","isCalculation":true},{"id":"4da8cb24-c090-43a7-b535-165a4c41fabd","difficultyBand":"hard","calculatorUse":"non_calc","totalMarks":3,"questionType":"LA","isCalculation":true},{"id":"55a41e1f-7543-4946-b6ab-75e7458be993","difficultyBand":"hard","calculatorUse":"non_calc","totalMarks":3,"questionType":"LA","isCalculation":true},{"id":"6c952b0d-2df7-424c-8086-875862299314","difficultyBand":"hard","calculatorUse":"non_calc","totalMarks":4,"questionType":"LA","isCalculation":true},{"id":"71b53c09-b0c8-4ea7-8626-33136bdd30dd","difficultyBand":"hard","calculatorUse":"non_calc","totalMarks":4,"questionType":"LA","isCalculation":true},{"id":"77033a42-e7d5-48fb-9a7c-ec235b856206","difficultyBand":"hard","calculatorUse":"non_calc","totalMarks":3,"questionType":"LA","isCalculation":true},{"id":"88de3212-895c-47eb-8f56-b2476b4a4401","difficultyBand":"medium","calculatorUse":"non_calc","totalMarks":2,"questionType":"LA","isCalculation":true},{"id":"c2393301-475b-4606-9953-c751685316a6","difficultyBand":"hard","calculatorUse":"non_calc","totalMarks":3,"questionType":"LA","isCalculation":true},{"id":"fe63963c-39f7-435f-9d1d-9313a8cb3f54","difficultyBand":"hard","calculatorUse":"non_calc","totalMarks":4,"questionType":"LA","isCalculation":true},{"id":"e3bdc9a3-7f6a-4b2d-af1a-f23591d50e83","difficultyBand":"medium","calculatorUse":"non_calc","totalMarks":3,"questionType":"LA","isCalculation":true},{"id":"1b9d49a6-4ae5-4317-b7b5-499f0bff966e","difficultyBand":"medium","calculatorUse":"non_calc","totalMarks":2,"questionType":"LA","isCalculation":true},{"id":"3152fde1-8c6f-4e83-be4e-fba0d6f2844a","difficultyBand":"hard","calculatorUse":"non_calc","totalMarks":4,"questionType":"LA","isCalculation":true},{"id":"50d2b4da-cd7b-4bce-8e2e-5abadb0e6c27","difficultyBand":"hard","calculatorUse":"non_calc","totalMarks":4,"questionType":"LA","isCalculation":true},{"id":"64368a2b-b3e9-4a32-89ca-c0e104f3e07d","difficultyBand":"hard","calculatorUse":"non_calc","totalMarks":3,"questionType":"LA","isCalculation":true},{"id":"680e47b5-142e-4334-bc42-fddef0fd28b5","difficultyBand":"medium","calculatorUse":"non_calc","totalMarks":2,"questionType":"LA","isCalculation":true},{"id":"847534f8-290a-4c7d-b4f4-166770d3de0f","difficultyBand":"hard","calculatorUse":"non_calc","totalMarks":3,"questionType":"LA","isCalculation":true},{"id":"9336bb0c-c7e5-48e7-b73d-e22714f98800","difficultyBand":"hard","calculatorUse":"non_calc","totalMarks":4,"questionType":"LA","isCalculation":true},{"id":"b96d6755-3297-417d-8be9-977ce421f624","difficultyBand":"hard","calculatorUse":"non_calc","totalMarks":4,"questionType":"LA","isCalculation":true},{"id":"bacb2956-7bcb-4c2d-8afd-5b95e5d69b87","difficultyBand":"hard","calculatorUse":"non_calc","totalMarks":3,"questionType":"LA","isCalculation":true},{"id":"c555987c-c080-4533-9961-96e80d57a281","difficultyBand":"medium","calculatorUse":"non_calc","totalMarks":3,"questionType":"LA","isCalculation":true},{"id":"cad3b5be-0f5a-4684-8348-ec032c77518f","difficultyBand":"hard","calculatorUse":"non_calc","totalMarks":3,"questionType":"LA","isCalculation":true},{"id":"cd1d4c6d-951d-43fc-af28-69810f56ed1e","difficultyBand":"hard","calculatorUse":"non_calc","totalMarks":5,"questionType":"LA","isCalculation":true},{"id":"80d48b64-4705-41c9-88b2-6a21087401ed","difficultyBand":"hard","calculatorUse":"non_calc","totalMarks":3,"questionType":"LA","isCalculation":true},{"id":"05b0e3ec-ddac-425c-b622-e848c7791d0a","difficultyBand":"hard","calculatorUse":"non_calc","totalMarks":3,"questionType":"LA","isCalculation":true},{"id":"091f0946-b5cf-4925-b259-060766025b7a","difficultyBand":"medium","calculatorUse":"non_calc","totalMarks":2,"questionType":"LA","isCalculation":true},{"id":"1e0e2d20-6ff2-4484-94df-487db19798c3","difficultyBand":"hard","calculatorUse":"non_calc","totalMarks":3,"questionType":"LA","isCalculation":true},{"id":"2be6ecf7-3406-4880-a8ac-36709b363713","difficultyBand":"hard","calculatorUse":"non_calc","totalMarks":4,"questionType":"LA","isCalculation":true},{"id":"556c525e-a528-4735-b563-f03b0f1dba34","difficultyBand":"hard","calculatorUse":"non_calc","totalMarks":3,"questionType":"LA","isCalculation":true},{"id":"99abcf9d-74b5-45bb-a99b-402fe9385611","difficultyBand":"hard","calculatorUse":"non_calc","totalMarks":3,"questionType":"LA","isCalculation":true},{"id":"a45f9077-1f07-4710-82cf-62eba64a99b3","difficultyBand":"hard","calculatorUse":"non_calc","totalMarks":4,"questionType":"LA","isCalculation":true},{"id":"a7a524d4-6f03-4011-ac45-84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of a Prism","topicId":"a2c45350-2311-4854-9d87-ef997348f7a0","topicSidebar":"$L3b","topicSlug":"grade-4-4-13-volume-of-a-prism","topicTitle":"Volume of a Prism"}]}],"$L3c","$L3d"]}]

Volume of a Prism

Question 10

Volume of a Prism Questions

Volume of a Prism

Question 10

Volume of a Prism Questions