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In proof, checking a few examples is not enough. We use a letter such as nnn to stand for any allowed integer, so the argument works for every case.
Standard forms matter. Even numbers are 2n2n2n, odd numbers are 2n+12n+12n+1, and consecutive integers can be written as nnn and n+1n+1n+1.
Before you start, decide the target form you want to reach, such as 2k+12k+12k+1, 6k6k6k, k2k^2k2, or 8k+28k+28k+2. A good proof follows a clear chain: define the general number, substitute, simplify, factorise if needed, and conclude. The last sentence must explain why the remaining part is an integer.
Question 1
2 marksProve algebraically that the sum of any two consecutive integers is always an odd number.
What does a single letter (like nnn) represent in an algebraic proof?
Revision notes for CCEA GCSE Maths Proof: explanations and worked examples.
1 of 5
For integer nnn, simplify (3n+2)2−(3n−2)2(3n+2)^2-(3n-2)^2(3n+2)2−(3n−2)2. Which result proves that the expression is divisible by 121212?