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solutions.","code":"A"}],"finalAnswers":["x = 2, y = 1 and x = -1, y = 3"],"generatedAt":"2026-05-06T11:36:41.739Z","modelVersion":"gemini-3-flash-preview"},"tableImages":[],"explanation":{"methods":[{"id":"substitute_for_y","label":"Substitute for y","steps":[{"type":"hyper_latex","block":{"nodes":[{"latex":"$$2x+3y=7$"},{"latex":"$$\\htmlData{anchor=three_y}{\\color{@orange}{3y}}=7-2x$"},{"latex":"$$\\htmlData{anchor=y_subject}{\\color{@sky}{y}}=\\dfrac{7-2x}{3}$"}],"highlights":[{"color":"orange","style":"text-color","anchor":"three_y"},{"color":"sky","style":"text-color-with-background","anchor":"y_subject"}]},"order":0,"title":"Make y the subject","description":"Start with the linear equation and isolate y. This rearrangement earns the first M1 mark."},{"type":"hyper_latex","block":{"nodes":[{"latex":"$$8x^2+3\\htmlData{anchor=y_squared}{\\color{@orange}{y^2}}=35$"},{"latex":"$$8x^2+3\\htmlData{anchor=substitution}{\\color{@sky}{\\left(\\dfrac{7-2x}{3}\\right)^2}}=35$"}],"highlights":[{"color":"orange","style":"text-color","anchor":"y_squared"},{"color":"sky","style":"text-color-with-background","anchor":"substitution"}]},"order":1,"title":"Substitute into quadratic","description":"Replace y in the quadratic equation with the expression just found. Writing this correct substitution earns the second M1 mark."},{"type":"hyper_latex","block":{"nodes":[{"latex":"$$8x^2+3\\left(\\dfrac{7-2x}{3}\\right)^2=35$"},{"latex":"$$24x^2+\\htmlData{anchor=square}{\\color{@orange}{(7-2x)^2}}=105$"},{"latex":"$$24x^2+\\htmlData{anchor=expanded}{\\color{@sky}{49-28x+4x^2}}=105$"},{"latex":"$$\\htmlData{anchor=collected}{\\color{@green}{28x^2-28x-56=0}}$"},{"latex":"$$\\htmlData{anchor=simplified}{\\color{@green}{x^2-x-2=0}}$"}],"highlights":[{"color":"orange","style":"text-color","anchor":"square"},{"color":"sky","style":"text-color-with-background","anchor":"expanded"},{"color":"green","style":"text-color","anchor":"collected"},{"color":"green","style":"text-color-with-background","anchor":"simplified"}]},"order":2,"title":"Form the quadratic","description":"Clear the fraction, expand the bracket and collect like terms. Reaching a quadratic in one variable earns the third M1 mark."},{"type":"hyper_latex","block":{"nodes":[{"latex":"$$x^2-x-2=0$"},{"latex":"$$\\htmlData{anchor=factors}{\\color{@sky}{(x-2)(x+1)}}=0$"},{"latex":"$$\\htmlData{anchor=roots}{\\color{@green}{x=2\\text{ or }x=-1}}$"}],"highlights":[{"color":"sky","style":"text-color-with-background","anchor":"factors"},{"color":"green","style":"text-color-with-background","anchor":"roots"}]},"order":3,"title":"Solve the quadratic","description":"Factorise by finding two numbers with product −2 and sum −1. Solving for both possible values of x earns the fourth M1 mark."},{"type":"hyper_latex","block":{"nodes":[{"latex":"$$y=\\dfrac{7-2x}{3}$"},{"latex":"$$x=2:\\quad y=\\dfrac{7-2(2)}{3}=1$"},{"latex":"$$x=-1:\\quad y=\\dfrac{7-2(-1)}{3}=3$"},{"latex":"$$\\htmlData{anchor=solutions}{\\color{@green}{(x,y)=(2,1)\\text{ or }(-1,3)}}$"}],"highlights":[{"color":"green","style":"text-color-with-background","anchor":"solutions"}]},"order":4,"title":"Find both y-values","description":"Substitute each x-value into the linear rearrangement. Keep each y-value paired with the x-value that produced it; both correct pairs earn A1."}]}],"generatedAt":"2026-07-19T19:10:37.804Z","modelVersion":"gpt-5.6-sol","explanationVersion":"v3"},"options":[]}],"options":[],"explanation":{"methods":[{"id":"476193a9-863b-4866-ab1d-a5d8bb6ec74c:substitute_y","label":"Substitution for y","steps":[{"type":"text","order":0,"title":"Rearrange the linear equation","content":"To use the method of **substitution for $y$**, we first need to rearrange the linear equation to express $y$ in terms of $x$.\n\nThe given linear equation is:\n$$2x + 3y = 7$$\n\nSubtract $2x$ from both sides:\n$$3y = 7 - 2x$$\n\nDivide by $3$:\n$$y = \\frac{7 - 2x}{3}$$"},{"type":"text","order":1,"title":"Substitute into the quadratic","content":"Now we substitute this expression for $y$ into our quadratic equation:\n$$8x^2 + 3y^2 = 35$$\n\nSubstituting $y = \\frac{7 - 2x}{3}$:\n$$8x^2 + 3\\left(\\frac{7 - 2x}{3}\\right)^2 = 35$$"},{"type":"text","order":2,"title":"Simplify the equation","content":"Let's expand and simplify the equation to form a standard quadratic equation. \n\nFirst, square the fraction:\n$$\\left(\\frac{7 - 2x}{3}\\right)^2 = \\frac{(7 - 2x)^2}{3^2} = \\frac{49 - 28x + 4x^2}{9}$$\n\nNow substitute this back into the equation:\n$$8x^2 + 3\\left(\\frac{49 - 28x + 4x^2}{9}\\right) = 35$$\n\nSimplify the fraction by dividing $3$ and $9$:\n$$8x^2 + \\frac{49 - 28x + 4x^2}{3} = 35$$\n\nMultiply the entire equation by $3$ to eliminate the fraction:\n$$24x^2 + (49 - 28x + 4x^2) = 105$$\n\nGroup the terms together:\n$$28x^2 - 28x + 49 = 105$$\n\nSubtract $105$ from both sides to set the quadratic to $0$:\n$$28x^2 - 28x - 56 = 0$$"},{"type":"text","order":3,"title":"Solve for x","content":"We can make our quadratic equation much easier to solve by dividing every term by the common factor of $28$:\n$$x^2 - x - 2 = 0$$\n\nNow we factorise this quadratic. We look for two numbers that multiply to $-2$ and add to $-1$. These numbers are $-2$ and $+1$:\n$$(x - 2)(x + 1) = 0$$\n\nThis gives two solutions for $x$:\n$$x = 2 \\quad \\text{or} \\quad x = -1$$"},{"type":"text","order":4,"title":"Find the corresponding y values","content":"Now substitute each value of $x$ back into our linear expression for $y$:\n\n**When $x = 2$:**\n$$y = \\frac{7 - 2(2)}{3} = \\frac{7 - 4}{3} = \\frac{3}{3} = 1$$\n\n**When $x = -1$:**\n$$y = \\frac{7 - 2(-1)}{3} = \\frac{7 + 2}{3} = \\frac{9}{3} = 3$$\n\nSo the solutions are:\n$$x = 2, y = 1 \\quad \\text{and} \\quad x = -1, y = 3$$"}]},{"id":"476193a9-863b-4866-ab1d-a5d8bb6ec74c:substitute_x","label":"Substitution for x","steps":[{"type":"hyper_latex","block":{"nodes":[{"latex":"$$2x + 3y = 7$"},{"latex":"$$\"2x\" = 7 - 3y$"},{"latex":"$$x = \\htmlData{anchor=x-expr}{\\frac{7 - 3y}{2}}$"}],"highlights":[{"color":"sky","style":"box","anchor":"x-expr"}],"connections":[]},"order":0,"title":"Rearrange for x","description":"We start by rearranging the linear equation $2x + 3y = 7$ to make $x$ the subject. Subtract $3y$ from both sides, then divide by $2$."},{"type":"hyper_latex","block":{"nodes":[{"latex":"$$8\\htmlData{anchor=x-pos}{x}^2 + 3y^2 = 35$"},{"latex":"$$8\\htmlData{anchor=x-sub}{\\left(\\frac{7 - 3y}{2}\\right)}^2 + 3y^2 = 35$"}],"highlights":[{"color":"sky","style":"box","anchor":"x-sub"}],"connections":[{"to":"x-sub","from":"x-pos","color":"sky","label":"substitute x","style":"solid"}]},"order":1,"title":"Substitute x into quadratic","description":"Next, substitute this expression for $x$ into the quadratic equation $8x^2 + 3y^2 = 35$."},{"type":"text","order":2,"title":"Simplify the equation","content":"Now we expand and simplify the equation:\n\n$$8\\left(\\frac{7 - 3y}{2}\\right)^2 + 3y^2 = 35$$\n\nFirst, square the fraction:\n\n$$\\left(\\frac{7 - 3y}{2}\\right)^2 = \\frac{(7 - 3y)^2}{4} = \\frac{49 - 42y + 9y^2}{4}$$\n\nMultiply by $8$:\n\n$$8 \\cdot \\left(\\frac{49 - 42y + 9y^2}{4}\\right) = 2(49 - 42y + 9y^2) = 98 - 84y + 18y^2$$\n\nSubstitute this back into our main equation:\n\n$$98 - 84y + 18y^2 + 3y^2 = 35$$\n\nCombine like terms:\n\n$$21y^2 - 84y + 98 = 35$$"},{"type":"text","order":3,"title":"Solve for y","content":"Subtract $35$ from both sides to form a standard quadratic equation:\n\n$$21y^2 - 84y + 63 = 0$$\n\nDivide every term by $21$ to simplify:\n\n$$y^2 - 4y + 3 = 0$$\n\nFactorise this quadratic equation:\n\n$$(y - 3)(y - 1) = 0$$\n\nThis gives two possible values for $y$:\n\n$$y = 3 \\quad \\text{or} \\quad y = 1$$"},{"type":"hyper_latex","block":{"nodes":[{"latex":"$$x = \\frac{7 - 3\\htmlData{anchor=y-val}{y}}{2}$"},{"latex":"$$\\text{If } \\htmlData{anchor=y1}{\\color{@pink}{y = 3}} \\implies x = \\frac{7 - 3(\\color{@pink}{3})}{2} = \\frac{7 - 9}{2} = \\htmlData{anchor=x1}{\\color{@pink}{-1}}$"},{"latex":"$$\\text{If } \\htmlData{anchor=y2}{\\color{@teal}{y = 1}} \\implies x = \\frac{7 - 3(\\color{@teal}{1})}{2} = \\frac{7 - 3}{2} = \\htmlData{anchor=x2}{\\color{@teal}{2}}$"}],"highlights":[{"color":"pink","style":"text-color","anchor":"y1"},{"color":"pink","style":"text-color","anchor":"x1"},{"color":"teal","style":"text-color","anchor":"y2"},{"color":"teal","style":"text-color","anchor":"x2"}],"connections":[]},"order":4,"title":"Find corresponding x-values","description":"Finally, substitute both values of $y$ back into our rearranged formula for $x$ to find the corresponding $x$-coordinates."},{"type":"text","order":5,"title":"State the solutions","content":"The pairs of solutions to the simultaneous equations are:\n\n$$x = -1, \\; y = 3$$\n\n$$x = 2, \\; y = 1$$"}]}],"generatedAt":"2026-06-13T01:03:50.020Z","modelVersion":"gemini-3.5-flash","explanationVersion":"v2"},"firstAttemptFullMarks":null,"walkthroughVideo":{"url":"https://assets.mathsgenie.co.uk/walkthroughs/review/618c994e-607e-486d-84cb-e55eeea09bfc.mp4","durationSeconds":179,"posterUrl":"https://assets.mathsgenie.co.uk/walkthroughs/review/618c994e-607e-486d-84cb-e55eeea09bfc.jpg"}},{"id":"c669142e-80fd-4605-9c62-20a8292778f0","revisionId":"357c2da4-aba5-4653-83d6-62525944986f","questionNumber":null,"questionType":"LA","specification":"","difficultyBand":"medium","tier":null,"totalMarks":5,"sourceTitle":null,"calculatorUse":"calc","isCalculation":true,"parts":[{"id":"c3ad9e7a-ef2e-424b-bb12-1f0d4960d6cd","label":"a","content":"Solve the simultaneous equations\nGive your answers to 3 significant figures\n\n$$x^2 + y^2 = 25$$\n\n$$3x + y = 4$$","markscheme":"- Rearranges linear equation to make $y$ the subject: $y = 4 - 3x$ M1\n- Substitutes linear expression into quadratic: $x^2 + (4 - 3x)^2 = 25$ M1\n- Simplifies to a standard quadratic form: $10x^2 - 24x - 9 = 0$ M1\n- Uses the quadratic formula or completing the square to solve for $x$: $x = \\frac{24 \\pm \\sqrt{(-24)^2 - 4(10)(-9)}}{20}$ M1\n- Final answers rounded to 3sf: $x = 2.73, y = -4.19$ and $x = -0.330, y = 4.99$ A1","marks":5,"order":0,"markingRubric":{"totalMarks":5,"points":[{"id":"p1","marks":1,"description":"Rearranges the linear equation to make $x$ or $y$ the subject.","code":"M"},{"id":"p2","marks":1,"description":"Substitutes the linear expression into the quadratic equation.","code":"M"},{"id":"p3","marks":1,"description":"Simplifies the resulting equation into a 3-term quadratic in standard form $ax^2 + bx + c = 0$.","code":"M"},{"id":"p4","marks":1,"description":"Applies a correct method to solve their 3-term quadratic equation (e.g., quadratic formula).","code":"M"},{"id":"p5","marks":1,"description":"Provides two pairs of values for $x$ and $y$ correct to 3 significant figures.","code":"A","acceptable":["x = 2.73, y = -4.19 and x = -0.330, y = 4.99"]}],"finalAnswers":["x = 2.73, y = -4.19 and x = -0.330, y = 4.99"],"generatedAt":"2026-05-06T11:36:26.407Z","modelVersion":"gemini-3-flash-preview"},"tableImages":[],"explanation":null,"options":[]}],"options":[],"explanation":{"methods":[{"id":"c3ad9e7a-ef2e-424b-bb12-1f0d4960d6cd:substitution_y","label":"Substitution making y the subject","steps":[{"type":"text","order":0,"title":"Rearrange the linear equation","content":"To solve these equations using substitution, we start with the linear equation because it is easier to isolate one of the variables. Let's make $y$ the subject of the equation:\n\n$$3x + y = 4$$\n\nSubtract $3x$ from both sides of the equation to isolate $y$:\n\n$$y = 4 - 3x$$"},{"type":"text","order":1,"title":"Substitute into the quadratic","content":"Now we substitute our expression for $y$ into the quadratic equation:\n\n$$x^2 + y^2 = 25$$\n\nReplacing $y$ with $(4 - 3x)$ gives:\n\n$$x^2 + (4 - 3x)^2 = 25$$"},{"type":"text","order":2,"title":"Expand and simplify","content":"Next, we expand the squared bracket $(4 - 3x)^2$:\n\n$$(4 - 3x)^2 = (4 - 3x)(4 - 3x) = 16 - 12x - 12x + 9x^2 = 16 - 24x + 9x^2$$\n\nNow substitute this expansion back into our main equation:\n\n$$x^2 + (16 - 24x + 9x^2) = 25$$\n\nCombine like terms:\n\n$$10x^2 - 24x + 16 = 25$$\n\nSubtract $25$ from both sides to form a standard quadratic equation equal to zero ($ax^2 + bx + c = 0$):\n\n$$10x^2 - 24x - 9 = 0$$"},{"type":"text","order":3,"title":"Apply the quadratic formula","content":"Since $10x^2 - 24x - 9 = 0$ does not factorise easily, we use the quadratic formula:\n\n$$x = \\frac{-b \\pm \\sqrt{b^2 - 4ac}}{2a}$$\n\nIdentifying our coefficients: $a = 10$, $b = -24$, and $c = -9$. Substituting these into the formula yields:\n\n$$x = \\frac{-(-24) \\pm \\sqrt{(-24)^2 - 4(10)(-9)}}{2(10)}$$\n\n$$x = \\frac{24 \\pm \\sqrt{576 + 360}}{20}$$\n\n$$x = \\frac{24 \\pm \\sqrt{936}}{20}$$"},{"type":"text","order":4,"title":"Calculate the values of x","content":"Now we calculate the two possible values for $x$:\n\n$$\\begin{aligned}\nx_1 &= \\frac{24 + \\sqrt{936}}{20} \\approx 2.7297... \\\\\nx_2 &= \\frac{24 - \\sqrt{936}}{20} \\approx -0.3297... \n\\end{aligned}$$\n\nRounding to 3 significant figures, we get:\n\n$$x = 2.73 \\quad \\text{or} \\quad x = -0.330$$","calculator":[{"gdc":{"instructions":"Go to the Equation/Solver menu, choose 'Polynomial' (F2), select '2nd Degree' (F1). Enter a = 10, b = -24, c = -9, and solve."},"ti84":{"instructions":"1. Press [APPS] and select 'PlySmlt2'.\n2. Choose '1: Polynomial Root Finder'.\n3. Set Order to '2' and press [NEXT] (GRAPH).\n4. Enter a2 = 10, a1 = -24, a0 = -9.\n5. Press [SOLVE] (GRAPH) to find the decimal approximations."},"desmos":{"expression":"y = 10x^2 - 24x - 9","instructions":"Type the equation y = 10x^2 - 24x - 9 and look at the x-intercepts of the parabola."},"description":"Calculate the roots of the quadratic equation using a graphing calculator."}]},{"type":"text","order":5,"title":"Calculate the values of y","content":"We now substitute our values of $x$ (using the unrounded values for accuracy) back into the rearranged linear equation $y = 4 - 3x$ to find the corresponding values of $y$.\n\n**For $x \\approx 2.7297$:**\n\n$$y = 4 - 3(2.7297) = 4 - 8.1891 = -4.1891$$\n\nRounding to 3 significant figures: $y = -4.19$\n\n**For $x \\approx -0.3297$:**\n\n$$y = 4 - 3(-0.3297) = 4 + 0.9891 = 4.9891$$\n\nRounding to 3 significant figures: $y = 4.99$\n\n**Final Solutions (to 3 sf):**\n\n$$x = 2.73, \\; y = -4.19 \\quad \\text{and} \\quad x = -0.330, \\; y = 4.99$$"}]},{"id":"c3ad9e7a-ef2e-424b-bb12-1f0d4960d6cd:substitution_x","label":"Substitution making x the subject","steps":[{"type":"text","order":0,"title":"Make x the subject","content":"To solve these simultaneous equations by making $x$ the subject, we start with the linear equation:\n\n$$3x + y = 4$$\n\nSubtract $y$ from both sides to isolate the term containing $x$:\n\n$$3x = 4 - y$$\n\nNow, divide both sides by $3$ to make $x$ the subject:\n\n$$x = \\frac{4 - y}{3}$$"},{"type":"text","order":1,"title":"Substitute into the quadratic","content":"Next, we substitute this expression for $x$ into our quadratic equation $x^2 + y^2 = 25$:\n\n$$\\left(\\frac{4 - y}{3}\\right)^2 + y^2 = 25$$\n\nWe expand the fractional term:\n\n$$\\frac{(4 - y)^2}{3^2} + y^2 = 25$$\n\n$$\\frac{16 - 8y + y^2}{9} + y^2 = 25$$"},{"type":"text","order":2,"title":"Form a standard quadratic","content":"To eliminate the fraction, multiply the entire equation by $9$:\n\n$$(16 - 8y + y^2) + 9y^2 = 225$$\n\nCombine like terms:\n\n$$10y^2 - 8y + 16 = 225$$\n\nSubtract $225$ from both sides to form a standard quadratic equation equal to zero ($ay^2 + by + c = 0$):\n\n$$10y^2 - 8y - 209 = 0$$"},{"type":"text","order":3,"title":"Solve for y","content":"Now, we use the quadratic formula to solve for $y$:\n\n$$y = \\frac{-b \\pm \\sqrt{b^2 - 4ac}}{2a}$$\n\nSubstituting $a = 10$, $b = -8$, and $c = -209$:\n\n$$y = \\frac{-(-8) \\pm \\sqrt{(-8)^2 - 4(10)(-209)}}{2(10)}$$\n\n$$y = \\frac{8 \\pm \\sqrt{64 + 8360}}{20}$$\n\n$$y = \\frac{8 \\pm \\sqrt{8424}}{20}$$\n\nCalculating the two possible values for $y$ to 3 significant figures:\n\n$$y_1 = \\frac{8 + 91.782}{20} \\approx 4.99$$\n\n$$y_2 = \\frac{8 - 91.782}{20} \\approx -4.19$$"},{"type":"text","order":4,"title":"Find the corresponding x-values","content":"We now substitute our $y$-values back into our equation for $x$, $x = \\frac{4 - y}{3}$:\n\n**For $y_1 = 4.9891$:**\n\n$$x_1 = \\frac{4 - 4.9891}{3} = \\frac{-0.9891}{3} \\approx -0.330$$\n\n**For $y_2 = -4.1891$:**\n\n$$x_2 = \\frac{4 - (-4.1891)}{3} = \\frac{8.1891}{3} \\approx 2.73$$"},{"type":"text","order":5,"title":"State final answers","content":"Rounding our answers to $3$ significant figures, we get:\n\n$$x = 2.73, \\; y = -4.19$$\n$$\\text{and}$$\n$$x = -0.330, \\; y = 4.99$$"}]}],"generatedAt":"2026-06-13T05:11:35.167Z","modelVersion":"gemini-3.5-flash","explanationVersion":"v2"},"firstAttemptFullMarks":null,"walkthroughVideo":{"url":"https://assets.mathsgenie.co.uk/walkthroughs/review/67c85ca1-6790-427d-b90a-1f42f5a5e14d.mp4","durationSeconds":246,"posterUrl":"https://assets.mathsgenie.co.uk/walkthroughs/review/67c85ca1-6790-427d-b90a-1f42f5a5e14d.jpg"}}],"subjectCode":"gcse_maths__ccea","summaries":[{"id":"7212abe4-9d9f-42ce-9fdd-8579125a4d9d","difficultyBand":"medium","calculatorUse":"non_calc","totalMarks":5,"questionType":"LA","isCalculation":true},{"id":"0680b32b-b3d1-44b4-abe0-df4c06c5f6ee","difficultyBand":"hard","calculatorUse":"calc","totalMarks":5,"questionType":"LA","isCalculation":true},{"id":"0ba0d46b-d87b-46ac-a5ec-7878d09a8849","difficultyBand":"hard","calculatorUse":null,"totalMarks":5,"questionType":"LA","isCalculation":true},{"id":"0ff0c9c1-2e86-4241-ba9e-d87ac6e80e0d","difficultyBand":"hard","calculatorUse":null,"totalMarks":5,"questionType":"LA","isCalculation":true},{"id":"11be48a7-bed0-4b02-addc-2ebcbe272fbc","difficultyBand":"hard","calculatorUse":"non_calc","totalMarks":5,"questionType":"LA","isCalculation":true},{"id":"138f77b6-2542-4b2d-b52d-1d094de432b9","difficultyBand":"hard","calculatorUse":"non_calc","totalMarks":5,"questionType":"LA","isCalculation":true},{"id":"1cf62487-8b73-4809-8e2f-9d6534316c82","difficultyBand":"hard","calculatorUse":null,"totalMarks":5,"questionType":"LA","isCalculation":true},{"id":"22015789-e381-4b4f-bbae-c078b906fcda","difficultyBand":"hard","calculatorUse":"non_calc","totalMarks":5,"questionType":"LA","isCalculation":true},{"id":"578e1398-9a05-4dd5-a4cf-e802cd858b76","difficultyBand":"hard","calculatorUse":"non_calc","totalMarks":5,"questionType":"LA","isCalculation":true},{"id":"5afa1d3e-b345-4245-b123-3231c57ce4d8","difficultyBand":"hard","calculatorUse":"non_calc","totalMarks":5,"questionType":"LA","isCalculation":true},{"id":"5b64e26f-c984-4b4f-a998-70eee47a327f","difficultyBand":"medium","calculatorUse":"non_calc","totalMarks":5,"questionType":"LA","isCalculation":true},{"id":"5e9e88ab-b405-442a-b038-baf7a7438a0c","difficultyBand":"hard","calculatorUse":"non_calc","totalMarks":5,"questionType":"LA","isCalculation":true},{"id":"694218c4-6fc6-40c4-9b0e-dc620e96e736","difficultyBand":"hard","calculatorUse":"non_calc","totalMarks":5,"questionType":"LA","isCalculation":true},{"id":"6a051e5d-1130-4612-9b39-cd388c35e097","difficultyBand":"medium","calculatorUse":"calc","totalMarks":5,"questionType":"LA","isCalculation":true},{"id":"70912a76-1f99-4b2e-af96-c9cfe2d51766","difficultyBand":"hard","calculatorUse":"calc","totalMarks":5,"questionType":"LA","isCalculation":true},{"id":"71a79447-d8d3-45a4-aa21-a8fe538a5530","difficultyBand":"hard","calculatorUse":"calc","totalMarks":5,"questionType":"LA","isCalculation":true},{"id":"72c14362-829c-4e25-9275-262a44d9c89b","difficultyBand":"hard","calculatorUse":"non_calc","totalMarks":5,"questionType":"LA","isCalculation":true},{"id":"7a6b6985-38bc-41be-818e-2673e2f2d760","difficultyBand":"hard","calculatorUse":"non_calc","totalMarks":5,"questionType":"LA","isCalculation":true},{"id":"7c341418-a80b-46cc-9f35-0da380b8a5ae","difficultyBand":"hard","calculatorUse":"non_calc","totalMarks":5,"questionType":"LA","isCalculation":true},{"id":"84bb9d09-1354-49bf-918d-4e4fa087f3a0","difficultyBand":"hard","calculatorUse":null,"totalMarks":5,"questionType":"LA","isCalculation":true},{"id":"869f4c48-0a7a-4564-90e3-d709e8b0e03d","difficultyBand":"hard","calculatorUse":null,"totalMarks":5,"questionType":"LA","isCalculation":true},{"id":"9312d566-1d8c-4634-b06e-3c683f8492d1","difficultyBand":"hard","calculatorUse":"non_calc","totalMarks":5,"questionType":"LA","isCalculation":true},{"id":"970da4ba-af59-4354-9e9c-2758ee45b405","difficultyBand":"hard","calculatorUse":"non_calc","totalMarks":5,"questionType":"LA","isCalculation":true},{"id":"9854e4cc-35da-431c-9450-f34ab3261782","difficultyBand":"hard","calculatorUse":null,"totalMarks":5,"questionType":"LA","isCalculation":true},{"id":"991ccd16-ac91-4f62-8f91-dfee476ce7ab","difficultyBand":"hard","calculatorUse":"non_calc","totalMarks":5,"questionType":"LA","isCalculation":true},{"id":"9d0ab159-7531-4fc5-b8a8-094cb630657a","difficultyBand":"hard","calculatorUse":"non_calc","totalMarks":5,"questionType":"LA","isCalculation":true},{"id":"a317aad3-9809-4660-a308-22d6850c0dec","difficultyBand":"hard","calculatorUse":"calc","totalMarks":5,"questionType":"LA","isCalculation":true},{"id":"a9581537-9df6-436d-bcce-675b994cb366","difficultyBand":"medium","calculatorUse":"non_calc","totalMarks":5,"questionType":"LA","isCalculation":true},{"id":"b0dcdab7-0093-44d0-b193-46e6690b1371","difficultyBand":"hard","calculatorUse":"calc","totalMarks":5,"questionType":"LA","isCalculation":true},{"id":"b14dde9e-11a5-405e-9ff7-e32c5a86bba6","difficultyBand":"hard","calculatorUse":"calc","totalMarks":5,"questionType":"LA","isCalculation":true},{"id":"ba64323a-522d-444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Quadratic Simultaneous Equations

Question 4

Quadratic Simultaneous Equations Questions

Quadratic Simultaneous Equations

Question 4

Quadratic Simultaneous Equations Questions