Solve 2x2−7x−5=02x^2 - 7x - 5 = 02x2−7x−5=0
Give your solutions correct to 3 significant figures.
Hence, solve 2(3x+1)2−7(3x+1)−5=02(3x+1)^2 - 7(3x+1) - 5 = 02(3x+1)2−7(3x+1)−5=0
156 exam-style questions on CCEA GCSE Maths Quadratic Formula. Each one has a worked solution and a mark scheme showing where the marks go.