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Question 9
m=50.42 kg correct to 2 decimal places m = 50.42 \text{ kg correct to 2 decimal places} m=50.42 kg correct to 2 decimal places ρ=6.25 kg/m3 correct to 3 significant figures \rho = 6.25 \text{ kg/m}^3 \text{ correct to 3 significant figures} ρ=6.25 kg/m3 correct to 3 significant figures ρ=mV \rho = \frac{m}{V} ρ=Vm​

ρ\rhoρ = density, mmm = mass, VVV = volume

By considering bounds, work out the value of V V\,V to a suitable degree of accuracy. Give a reason for your answer.

[3]

Bounds Questions

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