V=18.30 V correct to 2 decimal places
V = 18.30 \text{ V correct to 2 decimal places}
V=18.30 V correct to 2 decimal placesR=3.65 Ω correct to 3 significant figures
R = 3.65 \text{ }\Omega \text{ correct to 3 significant figures}
R=3.65Ω correct to 3 significant figuresI=VR
I = \frac{V}{R}
I=RV
III = current, VVV = voltage, RRR = resistance
By considering bounds, work out the value of I I\,I to a suitable degree of accuracy.
Give a reason for your answer.