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A1","marks":5,"order":0,"markingRubric":{"totalMarks":5,"points":[{"id":"p1","marks":1,"description":"Correctly completes the square to $(x + 5)^2 - 28 = 0$.","code":"M"},{"id":"p2","marks":1,"description":"Rearranges to $(x + 5)^2 = 28$.","code":"M"},{"id":"p3","marks":1,"description":"Takes the square root of both sides, including $\\pm$.","code":"M"},{"id":"p4","marks":1,"description":"Isolates $x$ to get $x = -5 \\pm \\sqrt{28}$.","code":"M"},{"id":"p5","marks":1,"description":"Simplifies the surd to $2\\sqrt{7}$ and gives final answers.","code":"A"}],"finalAnswers":["-5 + 2\\sqrt{7}","-5 - 2\\sqrt{7}"],"generatedAt":"2026-05-06T11:14:00.474Z","modelVersion":"gemini-3-flash-preview"},"tableImages":[],"explanation":{"methods":[{"id":"completing_the_square","label":"Complete the square","steps":[{"type":"hyper_latex","block":{"nodes":[{"latex":"$$x^2+10x-3=0$"},{"latex":"$$\\color{@sky}{\\htmlData{anchor=completed}{(x+5)^2-25}}-3=0$"}],"highlights":[{"color":"sky","style":"text-color","anchor":"completed"}]},"order":0,"title":"Complete the square","description":"Half the coefficient of x to get 5. Squaring x + 5 introduces an extra 25, so subtract 25 to keep the expression unchanged. This earns the first M1."},{"type":"hyper_latex","block":{"nodes":[{"latex":"$$(x+5)^2-28=0$"},{"latex":"$$(x+5)^2=\\color{@orange}{\\htmlData{anchor=isolated}{28}}$"}],"highlights":[{"color":"orange","style":"text-color","anchor":"isolated"}]},"order":1,"title":"Isolate the square","description":"Combine the two negative constants, then add 28 to both sides. Reaching the displayed equation earns the second M1."},{"type":"hyper_latex","block":{"nodes":[{"latex":"$$(x+5)^2=28$"},{"latex":"$$\\color{@purple}{\\htmlData{anchor=roots}{x+5=\\pm\\sqrt{28}}}$"}],"highlights":[{"color":"purple","style":"text-color","anchor":"roots"}]},"order":2,"title":"Take square roots","description":"A square has both a positive and a negative square root, so include the plus-or-minus sign. This earns the third M1."},{"type":"hyper_latex","block":{"nodes":[{"latex":"$$x+5=\\pm\\sqrt{28}$"},{"latex":"$$\\color{@green}{\\htmlData{anchor=subject}{x=-5\\pm\\sqrt{28}}}$"}],"highlights":[{"color":"green","style":"text-color","anchor":"subject"}]},"order":3,"title":"Make x the subject","description":"Subtract 5 from both sides, keeping both signs. The resulting expression for x earns the fourth M1."},{"type":"hyper_latex","block":{"nodes":[{"latex":"$$x=-5\\pm\\sqrt{28}$"},{"latex":"$$x=-5\\pm\\sqrt{\\htmlData{anchor=factor}{4\\times7}}$"},{"latex":"$$\\color{@teal}{\\htmlData{anchor=answer}{x=-5\\pm2\\sqrt7}}$"}],"highlights":[{"color":"teal","style":"text-color","anchor":"factor"},{"color":"teal","style":"text-color-with-background","anchor":"answer"}]},"order":4,"title":"Simplify the surd","description":"Use the square factor 4 inside 28, then take its square root. The fully simplified surd answers earn the final A1."}]}],"generatedAt":"2026-07-19T15:35:00.021Z","modelVersion":"gpt-5.6-sol","explanationVersion":"v3"},"options":[]}],"options":[],"explanation":{"methods":[{"id":"984ccc77-e1ed-4440-87cd-0ae383c438d2:direct_completing_square","label":"Direct Completing the Square","steps":[{"type":"hyper_latex","block":{"nodes":[{"latex":"$$x^2 + \\htmlData{anchor=coeff}{\\color{@sky}{10}}x - 3 = 0$"},{"latex":"$$(x + \\htmlData{anchor=half-coeff}{\\color{@sky}{5}})^2 - \\htmlData{anchor=square-term}{\\color{@amber}{5^2}} - 3 = 0$"}],"highlights":[{"color":"sky","style":"text-color","anchor":"coeff"},{"color":"sky","style":"text-color","anchor":"half-coeff"},{"color":"amber","style":"text-color","anchor":"square-term"}],"connections":[{"to":"half-coeff","from":"coeff","color":"sky","label":"halve","style":"solid"},{"to":"square-term","from":"half-coeff","color":"amber","label":"square","style":"dashed"}]},"order":0,"title":"Form the squared term","description":"To complete the square for $x^2 + 10x$, we halve the coefficient of $x$, which is $10$, to get $5$. We write this as $(x + 5)^2$, then subtract $5^2$ to keep the expression balanced."},{"type":"text","order":1,"title":"Simplify the equation","content":"Now, simplify the constant terms in the equation:\n\n$$\\begin{aligned}\n(x+5)^2 - 25 - 3 &= 0 \\\\\n(x+5)^2 - 28 &= 0\n\\end{aligned}$$\n\nRearrange the equation to isolate the squared bracket on one side:\n\n$$(x+5)^2 = 28$$"},{"type":"text","order":2,"title":"Take the square root","content":"Take the square root of both sides to eliminate the square. Remember to include both the positive and negative square roots:\n\n$$x+5 = \\pm\\sqrt{28}$$"},{"type":"hyper_latex","block":{"nodes":[{"latex":"$$\\sqrt{\\htmlData{anchor=surd-val}{\\color{@teal}{28}}} = \\sqrt{\\htmlData{anchor=factor-four}{\\color{@purple}{4}} \\times \\htmlData{anchor=factor-seven}{\\color{@teal}{7}}}$"},{"latex":"$$= \\htmlData{anchor=sqrt-four}{\\color{@purple}{2}}\\sqrt{\\htmlData{anchor=sqrt-seven}{\\color{@teal}{7}}}$"}],"highlights":[{"color":"teal","style":"text-color","anchor":"surd-val"},{"color":"purple","style":"text-color","anchor":"factor-four"},{"color":"purple","style":"text-color","anchor":"sqrt-four"}],"connections":[{"to":"sqrt-four","from":"factor-four","color":"purple","label":"square root","style":"solid"}]},"order":3,"title":"Simplify the surd","description":"We can simplify $\\sqrt{28}$ by finding its largest square factor. Since $28 = 4 \\times 7$, and $4$ is a square number, we can rewrite it as $2\\sqrt{7}$."},{"type":"text","order":4,"title":"Solve for x","content":"Substitute the simplified surd back into our equation and solve for $x$ by subtracting $5$ from both sides:\n\n$$\\begin{aligned}\nx + 5 &= \\pm 2\\sqrt{7} \\\\\nx &= -5 \\pm 2\\sqrt{7}\n\\end{aligned}$$\n\nThus, our solutions in surd form are:\n\n$$x = -5 + 2\\sqrt{7} \\quad \\text{and} \\quad x = -5 - 2\\sqrt{7}$$","calculator":[{"gdc":{"expression":"x^2 + 10*x - 3","instructions":"1. Go to the Graph application.\n2. Enter the function f1(x) = x^2 + 10x - 3.\n3. Use the 'Analyze Graph' -> 'Zero' tool to find the roots."},"ti84":{"expression":"X^2 + 10*X - 3","instructions":"1. Press [Y=] and enter Y1 = X² + 10X - 3.\n2. Press [GRAPH].\n3. Press [2nd] [CALC] and select '2: zero' to find each x-intercept."},"desmos":{"expression":"y = x^2 + 10*x - 3","instructions":"1. Enter y = x^2 + 10x - 3 in the first input box.\n2. Click on the gray points where the curve crosses the x-axis to reveal the numerical root values: approximately 0.2915 and -10.2915 (which correspond to -5 + 2√7 and -5 - 2√7)."},"description":"You can verify your solutions on a calculator by graphing the function and finding its x-intercepts (roots)."}]}]},{"id":"984ccc77-e1ed-4440-87cd-0ae383c438d2:equating_coefficients","label":"Equating Coefficients","steps":[{"type":"text","order":0,"title":"Set up the identities","content":"We want to write the quadratic expression $x^2 + 10x - 3$ in the completed square form $(x+a)^2 + b$.\n\nLet's equate the two forms:\n$$x^2 + 10x - 3 = (x+a)^2 + b$$","highlights":[{"text":"x^2 + 10x - 3 = 0","location":"specification"}]},{"type":"hyper_latex","block":{"nodes":[{"latex":"$$\\(x+a)^2 + b = x^2 + \\htmlData{anchor=a-expanded}{\\color{@sky}{2a}}x + \\htmlData{anchor=const-expanded}{\\color{@amber}{a^2 + b}}$"},{"latex":"$$x^2 + \\htmlData{anchor=a-original}{\\color{@sky}{10}}x \\htmlData{anchor=const-original}{\\color{@amber}{- 3}}$"}],"highlights":[{"color":"sky","style":"text-color","anchor":"a-expanded"},{"color":"sky","style":"text-color","anchor":"a-original"},{"color":"amber","style":"text-color","anchor":"const-expanded"},{"color":"amber","style":"text-color","anchor":"const-original"}],"connections":[{"to":"a-original","from":"a-expanded","color":"sky","label":"Equate x terms","style":"solid"},{"to":"const-original","from":"const-expanded","color":"amber","label":"Equate constants","style":"solid"}]},"order":1,"title":"Expand and equate coefficients","description":"Expand $(x+a)^2 + b$ to get $x^2 + 2ax + a^2 + b$, and align it with our target expression."},{"type":"text","order":2,"title":"Solve for parameters","content":"By comparing the coefficients of the $x$ term, we have:\n$$2a = 10 \\implies a = 5$$\n\nNow, compare the constant terms:\n$$a^2 + b = -3$$\n\nSubstitute $a = 5$ into the equation to find $b$:\n$$\\begin{aligned} 5^2 + b &= -3 \\\\ 25 + b &= -3 \\\\ b &= -28 \\end{aligned}$$"},{"type":"text","order":3,"title":"Write completed square form","content":"Now we can rewrite our original quadratic equation $(x+a)^2 + b = 0$ using our values of $a = 5$ and $b = -28$:\n\n$$(x + 5)^2 - 28 = 0$$"},{"type":"text","order":4,"title":"Solve for x","content":"Rearrange the equation to isolate $x$:\n\n$$\\begin{aligned} (x + 5)^2 &= 28 \\\\ x + 5 &= \\pm\\sqrt{28} \\\\ x &= -5 \\pm \\sqrt{28} \\end{aligned}$$"},{"type":"text","order":5,"title":"Simplify the surd","content":"To get the final mark, simplify the surd $\\sqrt{28}$:\n\n$$\\sqrt{28} = \\sqrt{4 \\times 7} = 2\\sqrt{7}$$\n\nThus, our final solution is:\n$$x = -5 \\pm 2\\sqrt{7}$$"}]}],"generatedAt":"2026-06-12T15:39:17.524Z","modelVersion":"gemini-3.5-flash","explanationVersion":"v2"},"firstAttemptFullMarks":{"percent":47},"walkthroughVideo":{"url":"https://assets.mathsgenie.co.uk/walkthroughs/videos/4d59ecea-7a22-4add-b915-ad79b18324ec.mp4","durationSeconds":120,"posterUrl":"https://assets.mathsgenie.co.uk/walkthroughs/videos/4d59ecea-7a22-4add-b915-ad79b18324ec.jpg"}},{"id":"5bfacc19-89e1-44da-87d4-368dbaf773c1","revisionId":"8f376b8e-f1ad-45ae-88af-f88ed165aa18","questionNumber":"14","questionType":"LA","specification":"","difficulty":4,"difficultyBand":"hard","totalMarks":5,"sourceTitle":"Completing the Square","calculatorUse":"non_calc","isCalculation":true,"parts":[{"id":"83f2bba7-cb61-47d9-85e4-f86ee98688e6","label":"0","content":"By completing the square solve $x^2 + 5x + 4.25 = 0$\nGive your answers in surd form.","markscheme":"- $(x + 2.5)^2 - 6.25 + 4.25 = 0$ M1\n- $(x + 2.5)^2 = 2$ M1\n- $x + 2.5 = \\pm\\sqrt{2}$ M1\n- $x = -2.5 \\pm \\sqrt{2}$ A2","marks":5,"order":0,"markingRubric":{"totalMarks":5,"points":[{"id":"p1","marks":1,"description":"Correctly completes the square to $(x + 2.5)^2 - 2 = 0$.","code":"M"},{"id":"p2","marks":1,"description":"Rearranges to $(x + 2.5)^2 = 2$.","code":"M"},{"id":"p3","marks":1,"description":"Takes the square root of both sides.","code":"M"},{"id":"p4","marks":2,"description":"Final answers $x = -2.5 \\pm \\sqrt{2}$ or equivalent fractions.","code":"A"}],"finalAnswers":["-2.5 + \\sqrt{2}","-2.5 - \\sqrt{2}"],"generatedAt":"2026-05-06T11:14:00.474Z","modelVersion":"gemini-3-flash-preview"},"tableImages":[],"explanation":{"methods":[{"id":"completing_the_square","label":"Completing the square","steps":[{"type":"text","order":0,"title":"Balance the square","content":"Replace $x^2+5x$ with $(x+2.5)^2-6.25$, because adding $2.5^2=6.25$ must be balanced by subtracting $6.25$.","highlights":[{"text":"By completing the square solve","location":"specification"}]},{"type":"hyper_latex","block":{"nodes":[{"latex":"$$\\htmlData{anchor=start_eq}{x^2+5x+4.25=0}$"},{"latex":"$$\\htmlData{anchor=completed_eq}{\\color{@amber}{(x+2.5)^2-6.25+4.25=0}}$"}],"highlights":[{"color":"amber","style":"text-color-with-background","anchor":"completed_eq"}],"connections":[{"to":"completed_eq","from":"start_eq","color":"sky","label":"complete the square","style":"solid"}]},"order":1,"title":"Complete the square","description":"This equivalent completed-square line earns the first method mark."},{"type":"hyper_latex","block":{"nodes":[{"latex":"(x+2.5)^2-2=0"},{"latex":"\\htmlData{anchor=isolated}{\\color{@orange}{(x+2.5)^2=2}}"}],"highlights":[{"color":"orange","style":"text-color-with-background","anchor":"isolated"}]},"order":3,"title":"Isolate the square","description":"Add 2 to both sides, keeping the same operation on both sides. Isolating the squared expression earns the second method mark."},{"type":"hyper_latex","block":{"nodes":[{"latex":"(x+2.5)^2=2"},{"latex":"\\htmlData{anchor=roots}{\\color{@green}{x+2.5=\\pm\\sqrt{2}}}"}],"highlights":[{"color":"green","style":"text-color-with-background","anchor":"roots"}]},"order":5,"title":"Take the square root","description":"Taking both square roots gives the plus-or-minus result; including both signs earns the third method mark."},{"type":"hyper_latex","block":{"nodes":[{"latex":"x+2.5=\\pm\\sqrt{2}"},{"latex":"\\htmlData{anchor=answer}{\\color{@red}{x=-2.5\\pm\\sqrt{2}}}"}],"highlights":[{"color":"red","style":"text-color-with-background","anchor":"answer"}]},"order":6,"title":"Solve for x","description":"Subtract 2.5 from both sides. This gives the two surd-form solutions and earns both accuracy marks. Do not convert the square root of 2 to a decimal."}]}],"generatedAt":"2026-07-19T02:17:23.084Z","modelVersion":"gpt-5.6-sol","explanationVersion":"v3"},"options":[]}],"options":[],"explanation":{"methods":[{"id":"83f2bba7-cb61-47d9-85e4-f86ee98688e6:decimal_approach","label":"Decimal Completion of Square","steps":[{"type":"text","order":0,"title":"Halve the x-coefficient","content":"To complete the square for the expression $x^2 + 5x + 4.25$, we start by looking at the coefficient of the linear term, $5x$.\n\nHalve this coefficient to get the decimal value:\n$$\\frac{5}{2} = 2.5$$","highlights":[{"text":"x^2 + 5x + 4.25 = 0","location":"specification"}]},{"type":"hyper_latex","block":{"nodes":[{"latex":"$$\\text{Since } \\left(x + \\htmlData{anchor=half-val}{\\color{@sky}{2.5}}\\right)^2 = x^2 + 5x + \\htmlData{anchor=sq-val}{\\color{@amber}{6.25}}$"},{"latex":"$$\\text{we can write } x^2 + 5x = \\left(x + \\htmlData{anchor=half-ref}{\\color{@sky}{2.5}}\\right)^2 - \\htmlData{anchor=sq-ref}{\\color{@amber}{6.25}}$"}],"highlights":[{"color":"sky","style":"text-color","anchor":"half-val"},{"color":"amber","style":"text-color","anchor":"sq-val"}],"connections":[{"to":"half-ref","from":"half-val","color":"sky","label":null,"style":"solid"},{"to":"sq-ref","from":"sq-val","color":"amber","label":"squared","style":"solid"}]},"order":1,"title":"Complete the square","description":"Square $2.5$ to find the constant needed to complete the square: $2.5^2 = 6.25$. This allows us to rewrite the first two terms of our equation."},{"type":"text","order":2,"title":"Substitute into equation","content":"Now, substitute this expression back into the original quadratic equation:\n\n$$(x + 2.5)^2 - 6.25 + 4.25 = 0$$\n\nSimplify the constant terms on the left side:\n$$-6.25 + 4.25 = -2$$\n\nThis gives us:\n$$(x + 2.5)^2 - 2 = 0$$"},{"type":"text","order":3,"title":"Isolate the squared term","content":"Add $2$ to both sides of the equation to isolate the squared term:\n\n$$(x + 2.5)^2 = 2$$"},{"type":"text","order":4,"title":"Solve for x","content":"Take the square root of both sides to get:\n\n$$x + 2.5 = \\pm\\sqrt{2}$$\n\nFinally, subtract $2.5$ from both sides to find the solutions in surd form:\n\n$$x = -2.5 \\pm \\sqrt{2}$$"}]},{"id":"83f2bba7-cb61-47d9-85e4-f86ee98688e6:fraction_approach","label":"Fractional Completion of Square","steps":[{"type":"text","order":0,"title":"Convert decimal to fraction","content":"To solve the quadratic equation $x^2 + 5x + 4.25 = 0$ using the **Fractional Completion of Square** method, we first convert the decimal constant $4.25$ into an improper fraction.\n\n$$4.25 = 4 + \\frac{1}{4} = \\frac{17}{4}$$\n\nThis gives us the equation:\n\n$$x^2 + 5x + \\frac{17}{4} = 0$$","highlights":[{"text":"x^2 + 5x + 4.25 = 0","location":"specification"}]},{"type":"hyper_latex","block":{"nodes":[{"latex":"$$x^2 + \\htmlData{anchor=linear-coeff}{\\color{@sky}{5}}x + \\frac{17}{4} = 0$"},{"latex":"$$\\left(x + \\frac{\\htmlData{anchor=half-coeff}{\\color{@sky}{5}}}{2}\\right)^2 - \\left(\\frac{\\htmlData{anchor=square-coeff}{\\color{@sky}{5}}}{2}\\right)^2 + \\frac{17}{4} = 0$"},{"latex":"$$\\left(x + \\frac{5}{2}\\right)^2 - \\htmlData{anchor=square-val}{\\color{@amber}{\\frac{25}{4}}} + \\frac{17}{4} = 0$"}],"highlights":[{"color":"sky","style":"text-color","anchor":"linear-coeff"},{"color":"sky","style":"text-color","anchor":"half-coeff"},{"color":"sky","style":"text-color","anchor":"square-coeff"},{"color":"amber","style":"text-color","anchor":"square-val"}],"connections":[{"to":"half-coeff","from":"linear-coeff","color":"sky","label":"half","style":"solid"},{"to":"square-coeff","from":"half-coeff","color":"sky","label":"square","style":"dashed"},{"to":"square-val","from":"square-coeff","color":"amber","label":"evaluate","style":"solid"}]},"order":1,"title":"Complete the square","description":"To complete the square for $x^2 + 5x$, we take half of the $x$-coefficient, which is $\\frac{5}{2}$, place it in the bracket, and then subtract its square $\\left(\\frac{5}{2}\\right)^2 = \\frac{25}{4}$."},{"type":"text","order":2,"title":"Simplify the constants","content":"Now, we combine the two fractional constants:\n\n$$\\begin{aligned} -\\frac{25}{4} + \\frac{17}{4} &= \\frac{-25 + 17}{4} \\\\ &= \\frac{-8}{4} \\\\ &= -2 \\end{aligned}$$\n\nSubstituting this back into our equation gives:\n\n$$\\left(x + \\frac{5}{2}\\right)^2 - 2 = 0$$\n\n*(This earns the first **M1** mark on the markscheme, which shows $(x + 2.5)^2 - 6.25 + 4.25 = 0$ in decimal form)*."},{"type":"text","order":3,"title":"Isolate the squared term","content":"Add $2$ to both sides of the equation to isolate the squared bracket:\n\n$$\\left(x + \\frac{5}{2}\\right)^2 = 2$$\n\n*(This earns the second **M1** mark, corresponding to $(x + 2.5)^2 = 2$)*."},{"type":"text","order":4,"title":"Solve for x","content":"Take the square root of both sides to eliminate the square exponent, remembering to include both the positive and negative roots:\n\n$$x + \\frac{5}{2} = \\pm\\sqrt{2}$$ *(This earns the third **M1** mark)*\n\nSubtract $\\frac{5}{2}$ from both sides to find the solutions for $x$:\n\n$$x = -\\frac{5}{2} \\pm \\sqrt{2}$$\n\nConverting the fraction back to a decimal to match the final answers on the markscheme:\n\n$$x = -2.5 \\pm \\sqrt{2}$$\n\n*(This final step earns **A2** marks for both correct surd solutions)*.","highlights":[{"text":"Give your answers in surd form.","location":"specification"}]}]}],"generatedAt":"2026-06-12T17:18:10.318Z","modelVersion":"gemini-3.5-flash","explanationVersion":"v2"},"firstAttemptFullMarks":{"percent":60},"walkthroughVideo":{"url":"https://assets.mathsgenie.co.uk/walkthroughs/videos/5bfacc19-89e1-44da-87d4-368dbaf773c1.mp4","durationSeconds":113,"posterUrl":"https://assets.mathsgenie.co.uk/walkthroughs/videos/5bfacc19-89e1-44da-87d4-368dbaf773c1.jpg"}}],"subjectCode":"gcse_maths__aqa","summaries":[{"id":"7f40db69-ca7c-4285-8e09-34656d81ce60","difficultyBand":"medium","calculatorUse":"non_calc","totalMarks":3,"questionType":"LA","isCalculation":true},{"id":"21a3243d-e573-401b-8dc0-efbb15dce586","difficultyBand":"medium","calculatorUse":"non_calc","totalMarks":4,"questionType":"LA","isCalculation":true},{"id":"45e23f29-00b9-4784-a691-c37252ca769a","difficultyBand":"medium","calculatorUse":"non_calc","totalMarks":4,"questionType":"LA","isCalculation":true},{"id":"4bba162f-d121-4811-9834-bd02bdc79c72","difficultyBand":"medium","calculatorUse":"non_calc","totalMarks":4,"questionType":"LA","isCalculation":true},{"id":"57d14b80-8895-4ab3-9945-f85df87adcf7","difficultyBand":"medium","calculatorUse":"non_calc","totalMarks":3,"questionType":"LA","isCalculation":true},{"id":"72ea4483-d396-4e36-babe-dff7fc59edf0","difficultyBand":"medium","calculatorUse":"non_calc","totalMarks":3,"questionType":"LA","isCalculation":true},{"id":"8f3b2c7e-0db1-4544-b5f6-0958506eba55","difficultyBand":"medium","calculatorUse":"non_calc","totalMarks":4,"questionType":"LA","isCalculation":true},{"id":"92fa7c1c-24e6-44d8-9ee5-dc00117d9897","difficultyBand":"medium","calculatorUse":"non_calc","totalMarks":3,"questionType":"LA","isCalculation":true},{"id":"93d24245-b18f-40b3-9a32-cf4910080c1a","difficultyBand":"hard","calculatorUse":"non_calc","totalMarks":5,"questionType":"LA","isCalculation":true},{"id":"a9a73ed0-e1d6-4198-a9c0-b1c6575eba3f","difficultyBand":"medium","calculatorUse":"non_calc","totalMarks":3,"questionType":"LA","isCalculation":true},{"id":"b5046ff9-42b4-4eff-ae7a-612609e22512","difficultyBand":"medium","calculatorUse":"non_calc","totalMarks":3,"questionType":"LA","isCalculation":true},{"id":"baf0db88-ad54-4d69-b2cc-318e78918ad3","difficultyBand":"medium","calculatorUse":"non_calc","totalMarks":3,"questionType":"LA","isCalculation":true},{"id":"c2839e7e-1bc5-4a2e-972a-69fbda186abc","difficultyBand":"medium","calculatorUse":"non_calc","totalMarks":3,"questionType":"LA","isCalculation":true},{"id":"e1e3cbe8-237a-41a8-8f2d-0e135f09e424","difficultyBand":"hard","calculatorUse":"non_calc","totalMarks":5,"questionType":"LA","isCalculation":true},{"id":"fbe671f3-0591-4322-a71b-e8126e2b1d53","difficultyBand":"medium","calculatorUse":"non_calc","totalMarks":3,"questionType":"LA","isCalculation":true},{"id":"55526e85-0c25-45ef-95c8-9a6b4dcbed55","difficultyBand":"medium","calculatorUse":"non_calc","totalMarks":3,"questionType":"LA","isCalculation":true},{"id":"107e1b9e-5d8e-4e13-8fbe-790c772c3287","difficultyBand":"hard","calculatorUse":"non_calc","totalMarks":5,"questionType":"LA","isCalculation":true},{"id":"1b3db67d-ab4d-4d96-82c0-f3d48507bae5","difficultyBand":"medium","calculatorUse":"non_calc","totalMarks":4,"questionType":"LA","isCalculation":true},{"id":"29a74acf-02a7-4bcc-9f80-8a2fbbca1909","difficultyBand":"medium","calculatorUse":"non_calc","totalMarks":3,"questionType":"LA","isCalculation":true},{"id":"5fbf5e43-d5a9-4882-86e1-b637ad11aeb3","difficultyBand":"hard","calculatorUse":"non_calc","totalMarks":4,"questionType":"LA","isCalculation":true},{"id":"728a5558-597a-4731-a3bd-a81de23bdddb","difficultyBand":"medium","calculatorUse":"non_calc","totalMarks":3,"questionType":"LA","isCalculation":true},{"id":"815514e4-689e-41a2-80f6-fe424fe892e6","difficultyBand":"medium","calculatorUse":"non_calc","totalMarks":3,"questionType":"LA","isCalculation":true},{"id":"837260c4-26bf-46ad-a682-db9fd32252b2","difficultyBand":"medium","calculatorUse":"non_calc","totalMarks":4,"questionType":"LA","isCalculation":true},{"id":"9c7fb861-56b4-49c0-a030-4f732d65eeef","difficultyBand":"medium","calculatorUse":"non_calc","totalMarks":3,"questionType":"LA","isCalculation":true},{"id":"9dc22c24-570d-4743-9966-a248e666473d","difficultyBand":"medium","calculatorUse":"non_calc","totalMarks":3,"questionType":"LA","isCalculation":true},{"id":"b9b8c31b-60a5-4aac-a82f-32d5a29cf792","difficultyBand":"medium","calculatorUse":"non_calc","totalMarks":3,"questionType":"LA","isCalculation":true},{"id":"de1c1dc4-3f3d-4bf7-b1ff-42b209dd8441","difficultyBand":"hard","calculatorUse":"non_calc","totalMarks":5,"questionType":"LA","isCalculation":true},{"id":"e6ac7d87-563f-48f1-836d-f2de17a1e004","difficultyBand":"medium","calculatorUse":"non_calc","totalMarks":4,"questionType":"LA","isCalculation":true},{"id":"f07cdb42-421e-46ec-841a-9cbbb3689031","difficultyBand":"medium","calculatorUse":"non_calc","totalMarks":3,"questionType":"LA","isCalculation":true},{"id":"fb8fe8f6-dea3-47e3-9496-bcb0b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the Square","topicId":"34f41bde-d2a1-4bbb-9d93-2f5b999a8342","topicSidebar":"$L3b","topicSlug":"grade-8-9-8-4-completing-the-square","topicTitle":"Completing the Square"}]}],"$L3c","$L3d"]}]

Completing the Square

Question 8

Completing the Square Questions

Completing the Square

Question 8

Completing the Square Questions