\vec{OA} = \mathbf{a}

\vec{OB} = \mathbf{b}

P is the point on $AB\,$ such that $A P : P B = 1 : 3$

\vec{OP} = k(3\mathbf{a} + \mathbf{b})

How is the vector $AB⃗\vec{AB}$ expressed using the position vectors $OA⃗\vec{OA}$ and $OB⃗\vec{OB}$ ?

1 of 5

The position vectors of A and B are $2 a$ and $5 b$ . What is the directed vector $AB\text{AB}$ ?

\vec{OA} = \mathbf{a}

\vec{OB} = \mathbf{b}

P is the point on $AB\,$ such that $A P : P B = 1 : 3$

\vec{OP} = k(3\mathbf{a} + \mathbf{b})

How is the vector $AB⃗\vec{AB}$ expressed using the position vectors $OA⃗\vec{OA}$ and $OB⃗\vec{OB}$ ?

The position vectors of A and B are $2 a$ and $5 b$ . What is the directed vector $AB\text{AB}$ ?

Vectors Proof Questions

Vectors Proof Questions Revision Guide