A diagram shows a triangle OABOABOAB.
OA→=5a \overrightarrow{OA} = 5\mathbf{a} OA=5a OB→=2b \overrightarrow{OB} = 2\mathbf{b} OB=2bP P\,P is the point on AB AB\,AB such that AP:PB=3:1AP:PB = 3:1AP:PB=3:1
OP→=k(5a+6b) \overrightarrow{OP} = k(5\mathbf{a} + 6\mathbf{b}) OP=k(5a+6b)
Find the value of kkk.
22 exam-style questions on AQA GCSE Maths Vectors Proof Questions. Each one has a worked solution and a mark scheme showing where the marks go.