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Bounds

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Question 31
v=wz v = \frac{\sqrt{w}}{z} v=zw​​

w=51.8w = 51.8w=51.8 correct to 3 significant figures

z=10.402z = 10.402z=10.402 correct to 3 decimal places

By considering bounds, work out the value of v v\,v to a suitable degree of accuracy. Give a reason for your answer.

[5]
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Bounds Questions

  1. GCSE
  2. /Maths
  3. /Bounds

52 exam-style questions on AQA GCSE Maths Bounds. Each one has a worked solution and a mark scheme showing where the marks go.

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