33:I[196793,["/_next/static/chunks/15cw-f-h-kyfp.js?dpl=nogit-1791215249","/_next/static/chunks/2_6olli-sutu3.js?dpl=nogit-1791215249","/_next/static/chunks/0zcakt1-boe_f.js?dpl=nogit-1791215249","/_next/static/chunks/0yuh9obhrf6py.js?dpl=nogit-1791215249","/_next/static/chunks/3mz725-y91ph6.js?dpl=nogit-1791215249","/_next/static/chunks/2x_dbpl3b_l2r.js?dpl=nogit-1791215249","/_next/static/chunks/13_9hjun60hj-.js?dpl=nogit-1791215249","/_next/static/chunks/2bxmml65nu49g.js?dpl=nogit-1791215249","/_next/static/chunks/0zkcxwtbsqliz.js?dpl=nogit-1791215249","/_next/static/chunks/0d3f1nmeak_z5.js?dpl=nogit-1791215249","/_next/static/chunks/2gjyu-jrwu-fu.js?dpl=nogit-1791215249","/_next/static/chunks/38w1x0vrld4-w.js?dpl=nogit-1791215249","/_next/static/chunks/3jpl-42mbad5n.js?dpl=nogit-1791215249","/_next/static/chunks/3kzt2piec6aoa.js?dpl=nogit-1791215249","/_next/static/chunks/19ijf68pshdcn.js?dpl=nogit-1791215249","/_next/static/chunks/2os7nxouq91eq.js?dpl=nogit-1791215249","/_next/static/chunks/3ml3vooxhiupb.js?dpl=nogit-1791215249","/_next/static/chunks/04zr-wqafvwoa.js?dpl=nogit-1791215249","/_next/static/chunks/10rmxw_yiwj40.js?dpl=nogit-1791215249","/_next/static/chunks/40lyu17d590zu.js?dpl=nogit-1791215249","/_next/static/chunks/2g-t2n9ahs3tn.js?dpl=nogit-1791215249","/_next/static/chunks/1g1suj21ijg7y.js?dpl=nogit-1791215249","/_next/static/chunks/3lz9pr5v38m4h.js?dpl=nogit-1791215249","/_next/static/chunks/2mv9l1xl_aa4j.js?dpl=nogit-1791215249","/_next/static/chunks/0v4byuex1x38h.js?dpl=nogit-1791215249","/_next/static/chunks/2oijhb0tdir9b.js?dpl=nogit-1791215249","/_next/static/chunks/2eanemqjnv2vr.js?dpl=nogit-1791215249","/_next/static/chunks/44nm8-o05iplc.js?dpl=nogit-1791215249","/_next/static/chunks/0llqhg6-bxn_b.js?dpl=nogit-1791215249","/_next/static/chunks/1ku-vdy4ggo41.js?dpl=nogit-1791215249","/_next/static/chunks/2r29ujce72_54.js?dpl=nogit-1791215249","/_next/static/chunks/2dx-vzwyw9a3g.js?dpl=nogit-1791215249","/_next/static/chunks/1coblm1-go81_.js?dpl=nogit-1791215249","/_next/static/chunks/0jt4ynafgg-jc.js?dpl=nogit-1791215249","/_next/static/chunks/0k-y_4mcfub-p.js?dpl=nogit-1791215249","/_next/static/chunks/0iokk_o_t6q55.js?dpl=nogit-1791215249","/_next/static/chunks/2eycy5cqzjdqf.js?dpl=nogit-1791215249","/_next/static/chunks/33z1jiacs_jrz.js?dpl=nogit-1791215249","/_next/static/chunks/20_c60cgo1g9g.js?dpl=nogit-1791215249","/_next/static/chunks/3it1o0ex-l5qz.js?dpl=nogit-1791215249","/_next/static/chunks/1eyu-5752jh17.js?dpl=nogit-1791215249","/_next/static/chunks/28uw5fp_u1bnm.js?dpl=nogit-1791215249","/_next/static/chunks/3ybwgs28on6c8.js?dpl=nogit-1791215249","/_next/static/chunks/0w7ow4sfu0tl_.js?dpl=nogit-1791215249","/_next/static/chunks/24srd-xd1m5z8.js?dpl=nogit-1791215249","/_next/static/chunks/075i0tnxt4not.js?dpl=nogit-1791215249","/_next/static/chunks/2ryoj58czm802.js?dpl=nogit-1791215249","/_next/static/chunks/1ksyn9m68446d.js?dpl=nogit-1791215249","/_next/static/chunks/3v6lxgtmi9vqz.js?dpl=nogit-1791215249","/_next/static/chunks/13gj59kzq50t_.js?dpl=nogit-1791215249","/_next/static/chunks/0g8b6ke39i-ui.js?dpl=nogit-1791215249","/_next/static/chunks/0ixdj_i1afhld.js?dpl=nogit-1791215249","/_next/static/chunks/30w6c7jj-mxyi.js?dpl=nogit-1791215249","/_next/static/chunks/2qk8b2y5gyu_0.js?dpl=nogit-1791215249","/_next/static/chunks/12bb60zmzpft7.js?dpl=nogit-1791215249","/_next/static/chunks/1hnuhh5t7cfaj.js?dpl=nogit-1791215249","/_next/static/chunks/36nndwkz7iik3.js?dpl=nogit-1791215249","/_next/static/chunks/1d7tjnrc0fv5y.js?dpl=nogit-1791215249","/_next/static/chunks/0zg1om_k0m5zv.js?dpl=nogit-1791215249","/_next/static/chunks/1lsxkfxy262n-.js?dpl=nogit-1791215249"],"Gingerbread"] 35:I[647935,["/_next/static/chunks/15cw-f-h-kyfp.js?dpl=nogit-1791215249","/_next/static/chunks/2_6olli-sutu3.js?dpl=nogit-1791215249","/_next/static/chunks/0zcakt1-boe_f.js?dpl=nogit-1791215249","/_next/static/chunks/0yuh9obhrf6py.js?dpl=nogit-1791215249","/_next/static/chunks/3mz725-y91ph6.js?dpl=nogit-1791215249","/_next/static/chunks/2x_dbpl3b_l2r.js?dpl=nogit-1791215249","/_next/static/chunks/13_9hjun60hj-.js?dpl=nogit-1791215249","/_next/static/chunks/2bxmml65nu49g.js?dpl=nogit-1791215249","/_next/static/chunks/0zkcxwtbsqliz.js?dpl=nogit-1791215249","/_next/static/chunks/0d3f1nmeak_z5.js?dpl=nogit-1791215249","/_next/static/chunks/2gjyu-jrwu-fu.js?dpl=nogit-1791215249","/_next/static/chunks/38w1x0vrld4-w.js?dpl=nogit-1791215249","/_next/static/chunks/3jpl-42mbad5n.js?dpl=nogit-1791215249","/_next/static/chunks/3kzt2piec6aoa.js?dpl=nogit-1791215249","/_next/static/chunks/19ijf68pshdcn.js?dpl=nogit-1791215249","/_next/static/chunks/2os7nxouq91eq.js?dpl=nogit-1791215249","/_next/static/chunks/3ml3vooxhiupb.js?dpl=nogit-1791215249","/_next/static/chunks/04zr-wqafvwoa.js?dpl=nogit-1791215249","/_next/static/chunks/10rmxw_yiwj40.js?dpl=nogit-1791215249","/_next/static/chunks/40lyu17d590zu.js?dpl=nogit-1791215249","/_next/static/chunks/2g-t2n9ahs3tn.js?dpl=nogit-1791215249","/_next/static/chunks/1g1suj21ijg7y.js?dpl=nogit-1791215249","/_next/static/chunks/3lz9pr5v38m4h.js?dpl=nogit-1791215249","/_next/static/chunks/2mv9l1xl_aa4j.js?dpl=nogit-1791215249","/_next/static/chunks/0v4byuex1x38h.js?dpl=nogit-1791215249","/_next/static/chunks/2oijhb0tdir9b.js?dpl=nogit-1791215249","/_next/static/chunks/2eanemqjnv2vr.js?dpl=nogit-1791215249","/_next/static/chunks/44nm8-o05iplc.js?dpl=nogit-1791215249","/_next/static/chunks/0llqhg6-bxn_b.js?dpl=nogit-1791215249","/_next/static/chunks/1ku-vdy4ggo41.js?dpl=nogit-1791215249","/_next/static/chunks/2r29ujce72_54.js?dpl=nogit-1791215249","/_next/static/chunks/2dx-vzwyw9a3g.js?dpl=nogit-1791215249","/_next/static/chunks/1coblm1-go81_.js?dpl=nogit-1791215249","/_next/static/chunks/0jt4ynafgg-jc.js?dpl=nogit-1791215249","/_next/static/chunks/0k-y_4mcfub-p.js?dpl=nogit-1791215249","/_next/static/chunks/0iokk_o_t6q55.js?dpl=nogit-1791215249","/_next/static/chunks/2eycy5cqzjdqf.js?dpl=nogit-1791215249","/_next/static/chunks/33z1jiacs_jrz.js?dpl=nogit-1791215249","/_next/static/chunks/20_c60cgo1g9g.js?dpl=nogit-1791215249","/_next/static/chunks/3it1o0ex-l5qz.js?dpl=nogit-1791215249","/_next/static/chunks/1eyu-5752jh17.js?dpl=nogit-1791215249","/_next/static/chunks/28uw5fp_u1bnm.js?dpl=nogit-1791215249","/_next/static/chunks/3ybwgs28on6c8.js?dpl=nogit-1791215249","/_next/static/chunks/0w7ow4sfu0tl_.js?dpl=nogit-1791215249","/_next/static/chunks/24srd-xd1m5z8.js?dpl=nogit-1791215249","/_next/static/chunks/075i0tnxt4not.js?dpl=nogit-1791215249","/_next/static/chunks/2ryoj58czm802.js?dpl=nogit-1791215249","/_next/static/chunks/1ksyn9m68446d.js?dpl=nogit-1791215249","/_next/static/chunks/3v6lxgtmi9vqz.js?dpl=nogit-1791215249","/_next/static/chunks/13gj59kzq50t_.js?dpl=nogit-1791215249","/_next/static/chunks/0g8b6ke39i-ui.js?dpl=nogit-1791215249","/_next/static/chunks/0ixdj_i1afhld.js?dpl=nogit-1791215249","/_next/static/chunks/30w6c7jj-mxyi.js?dpl=nogit-1791215249","/_next/static/chunks/2qk8b2y5gyu_0.js?dpl=nogit-1791215249","/_next/static/chunks/12bb60zmzpft7.js?dpl=nogit-1791215249","/_next/static/chunks/1hnuhh5t7cfaj.js?dpl=nogit-1791215249","/_next/static/chunks/36nndwkz7iik3.js?dpl=nogit-1791215249","/_next/static/chunks/1d7tjnrc0fv5y.js?dpl=nogit-1791215249","/_next/static/chunks/0zg1om_k0m5zv.js?dpl=nogit-1791215249","/_next/static/chunks/1lsxkfxy262n-.js?dpl=nogit-1791215249"],"RecordResourceResume"] 36:I[830476,["/_next/static/chunks/15cw-f-h-kyfp.js?dpl=nogit-1791215249","/_next/static/chunks/2_6olli-sutu3.js?dpl=nogit-1791215249","/_next/static/chunks/0zcakt1-boe_f.js?dpl=nogit-1791215249","/_next/static/chunks/0yuh9obhrf6py.js?dpl=nogit-1791215249","/_next/static/chunks/3mz725-y91ph6.js?dpl=nogit-1791215249","/_next/static/chunks/2x_dbpl3b_l2r.js?dpl=nogit-1791215249","/_next/static/chunks/13_9hjun60hj-.js?dpl=nogit-1791215249","/_next/static/chunks/2bxmml65nu49g.js?dpl=nogit-1791215249","/_next/static/chunks/0zkcxwtbsqliz.js?dpl=nogit-1791215249","/_next/static/chunks/0d3f1nmeak_z5.js?dpl=nogit-1791215249","/_next/static/chunks/2gjyu-jrwu-fu.js?dpl=nogit-1791215249","/_next/static/chunks/38w1x0vrld4-w.js?dpl=nogit-1791215249","/_next/static/chunks/3jpl-42mbad5n.js?dpl=nogit-1791215249","/_next/static/chunks/3kzt2piec6aoa.js?dpl=nogit-1791215249","/_next/static/chunks/19ijf68pshdcn.js?dpl=nogit-1791215249","/_next/static/chunks/2os7nxouq91eq.js?dpl=nogit-1791215249","/_next/static/chunks/3ml3vooxhiupb.js?dpl=nogit-1791215249","/_next/static/chunks/04zr-wqafvwoa.js?dpl=nogit-1791215249","/_next/static/chunks/10rmxw_yiwj40.js?dpl=nogit-1791215249","/_next/static/chunks/40lyu17d590zu.js?dpl=nogit-1791215249","/_next/static/chunks/2g-t2n9ahs3tn.js?dpl=nogit-1791215249","/_next/static/chunks/1g1suj21ijg7y.js?dpl=nogit-1791215249","/_next/static/chunks/3lz9pr5v38m4h.js?dpl=nogit-1791215249","/_next/static/chunks/2mv9l1xl_aa4j.js?dpl=nogit-1791215249","/_next/static/chunks/0v4byuex1x38h.js?dpl=nogit-1791215249","/_next/static/chunks/2oijhb0tdir9b.js?dpl=nogit-1791215249","/_next/static/chunks/2eanemqjnv2vr.js?dpl=nogit-1791215249","/_next/static/chunks/44nm8-o05iplc.js?dpl=nogit-1791215249","/_next/static/chunks/0llqhg6-bxn_b.js?dpl=nogit-1791215249","/_next/static/chunks/1ku-vdy4ggo41.js?dpl=nogit-1791215249","/_next/static/chunks/2r29ujce72_54.js?dpl=nogit-1791215249","/_next/static/chunks/2dx-vzwyw9a3g.js?dpl=nogit-1791215249","/_next/static/chunks/1coblm1-go81_.js?dpl=nogit-1791215249","/_next/static/chunks/0jt4ynafgg-jc.js?dpl=nogit-1791215249","/_next/static/chunks/0k-y_4mcfub-p.js?dpl=nogit-1791215249","/_next/static/chunks/0iokk_o_t6q55.js?dpl=nogit-1791215249","/_next/static/chunks/2eycy5cqzjdqf.js?dpl=nogit-1791215249","/_next/static/chunks/33z1jiacs_jrz.js?dpl=nogit-1791215249","/_next/static/chunks/20_c60cgo1g9g.js?dpl=nogit-1791215249","/_next/static/chunks/3it1o0ex-l5qz.js?dpl=nogit-1791215249","/_next/static/chunks/1eyu-5752jh17.js?dpl=nogit-1791215249","/_next/static/chunks/28uw5fp_u1bnm.js?dpl=nogit-1791215249","/_next/static/chunks/3ybwgs28on6c8.js?dpl=nogit-1791215249","/_next/static/chunks/0w7ow4sfu0tl_.js?dpl=nogit-1791215249","/_next/static/chunks/24srd-xd1m5z8.js?dpl=nogit-1791215249","/_next/static/chunks/075i0tnxt4not.js?dpl=nogit-1791215249","/_next/static/chunks/2ryoj58czm802.js?dpl=nogit-1791215249","/_next/static/chunks/1ksyn9m68446d.js?dpl=nogit-1791215249","/_next/static/chunks/3v6lxgtmi9vqz.js?dpl=nogit-1791215249","/_next/static/chunks/13gj59kzq50t_.js?dpl=nogit-1791215249","/_next/static/chunks/0g8b6ke39i-ui.js?dpl=nogit-1791215249","/_next/static/chunks/0ixdj_i1afhld.js?dpl=nogit-1791215249","/_next/static/chunks/30w6c7jj-mxyi.js?dpl=nogit-1791215249","/_next/static/chunks/2qk8b2y5gyu_0.js?dpl=nogit-1791215249","/_next/static/chunks/12bb60zmzpft7.js?dpl=nogit-1791215249","/_next/static/chunks/1hnuhh5t7cfaj.js?dpl=nogit-1791215249","/_next/static/chunks/36nndwkz7iik3.js?dpl=nogit-1791215249","/_next/static/chunks/1d7tjnrc0fv5y.js?dpl=nogit-1791215249","/_next/static/chunks/0zg1om_k0m5zv.js?dpl=nogit-1791215249","/_next/static/chunks/1lsxkfxy262n-.js?dpl=nogit-1791215249"],"FlashcardAccessBranch"] 37:I[315438,["/_next/static/chunks/15cw-f-h-kyfp.js?dpl=nogit-1791215249","/_next/static/chunks/2_6olli-sutu3.js?dpl=nogit-1791215249","/_next/static/chunks/0zcakt1-boe_f.js?dpl=nogit-1791215249","/_next/static/chunks/0yuh9obhrf6py.js?dpl=nogit-1791215249","/_next/static/chunks/3mz725-y91ph6.js?dpl=nogit-1791215249","/_next/static/chunks/2x_dbpl3b_l2r.js?dpl=nogit-1791215249","/_next/static/chunks/13_9hjun60hj-.js?dpl=nogit-1791215249","/_next/static/chunks/2bxmml65nu49g.js?dpl=nogit-1791215249","/_next/static/chunks/0zkcxwtbsqliz.js?dpl=nogit-1791215249","/_next/static/chunks/0d3f1nmeak_z5.js?dpl=nogit-1791215249","/_next/static/chunks/2gjyu-jrwu-fu.js?dpl=nogit-1791215249","/_next/static/chunks/38w1x0vrld4-w.js?dpl=nogit-1791215249","/_next/static/chunks/3jpl-42mbad5n.js?dpl=nogit-1791215249","/_next/static/chunks/3kzt2piec6aoa.js?dpl=nogit-1791215249","/_next/static/chunks/19ijf68pshdcn.js?dpl=nogit-1791215249","/_next/static/chunks/2os7nxouq91eq.js?dpl=nogit-1791215249","/_next/static/chunks/3ml3vooxhiupb.js?dpl=nogit-1791215249","/_next/static/chunks/04zr-wqafvwoa.js?dpl=nogit-1791215249","/_next/static/chunks/10rmxw_yiwj40.js?dpl=nogit-1791215249","/_next/static/chunks/40lyu17d590zu.js?dpl=nogit-1791215249","/_next/static/chunks/2g-t2n9ahs3tn.js?dpl=nogit-1791215249","/_next/static/chunks/1g1suj21ijg7y.js?dpl=nogit-1791215249","/_next/static/chunks/3lz9pr5v38m4h.js?dpl=nogit-1791215249","/_next/static/chunks/2mv9l1xl_aa4j.js?dpl=nogit-1791215249","/_next/static/chunks/0v4byuex1x38h.js?dpl=nogit-1791215249","/_next/static/chunks/2oijhb0tdir9b.js?dpl=nogit-1791215249","/_next/static/chunks/2eanemqjnv2vr.js?dpl=nogit-1791215249","/_next/static/chunks/44nm8-o05iplc.js?dpl=nogit-1791215249","/_next/static/chunks/0llqhg6-bxn_b.js?dpl=nogit-1791215249","/_next/static/chunks/1ku-vdy4ggo41.js?dpl=nogit-1791215249","/_next/static/chunks/2r29ujce72_54.js?dpl=nogit-1791215249","/_next/static/chunks/2dx-vzwyw9a3g.js?dpl=nogit-1791215249","/_next/static/chunks/1coblm1-go81_.js?dpl=nogit-1791215249","/_next/static/chunks/0jt4ynafgg-jc.js?dpl=nogit-1791215249","/_next/static/chunks/0k-y_4mcfub-p.js?dpl=nogit-1791215249","/_next/static/chunks/0iokk_o_t6q55.js?dpl=nogit-1791215249","/_next/static/chunks/2eycy5cqzjdqf.js?dpl=nogit-1791215249","/_next/static/chunks/33z1jiacs_jrz.js?dpl=nogit-1791215249","/_next/static/chunks/20_c60cgo1g9g.js?dpl=nogit-1791215249","/_next/static/chunks/3it1o0ex-l5qz.js?dpl=nogit-1791215249","/_next/static/chunks/1eyu-5752jh17.js?dpl=nogit-1791215249","/_next/static/chunks/28uw5fp_u1bnm.js?dpl=nogit-1791215249","/_next/static/chunks/3ybwgs28on6c8.js?dpl=nogit-1791215249","/_next/static/chunks/0w7ow4sfu0tl_.js?dpl=nogit-1791215249","/_next/static/chunks/24srd-xd1m5z8.js?dpl=nogit-1791215249","/_next/static/chunks/075i0tnxt4not.js?dpl=nogit-1791215249","/_next/static/chunks/2ryoj58czm802.js?dpl=nogit-1791215249","/_next/static/chunks/1ksyn9m68446d.js?dpl=nogit-1791215249","/_next/static/chunks/3v6lxgtmi9vqz.js?dpl=nogit-1791215249","/_next/static/chunks/13gj59kzq50t_.js?dpl=nogit-1791215249","/_next/static/chunks/0g8b6ke39i-ui.js?dpl=nogit-1791215249","/_next/static/chunks/0ixdj_i1afhld.js?dpl=nogit-1791215249","/_next/static/chunks/30w6c7jj-mxyi.js?dpl=nogit-1791215249","/_next/static/chunks/2qk8b2y5gyu_0.js?dpl=nogit-1791215249","/_next/static/chunks/12bb60zmzpft7.js?dpl=nogit-1791215249","/_next/static/chunks/1hnuhh5t7cfaj.js?dpl=nogit-1791215249","/_next/static/chunks/36nndwkz7iik3.js?dpl=nogit-1791215249","/_next/static/chunks/1d7tjnrc0fv5y.js?dpl=nogit-1791215249","/_next/static/chunks/0zg1om_k0m5zv.js?dpl=nogit-1791215249","/_next/static/chunks/1lsxkfxy262n-.js?dpl=nogit-1791215249"],"TopicFlashcardRunner"] 24:[["$","$L33",null,{"feature":"flashcards"}],"$L34",["$","$L35",null,{"href":"/gcse/maths/aqa/grade-6-6-10-circle-theorems/flashcards","label":"Circle Theorems","subjectCode":"gcse_maths__aqa","surface":"flashcards"}],["$","$L36",null,{"runner":["$","div",null,{"className":"min-h-0 flex-1 overflow-hidden bg-background","children":["$","$L37",null,{"decks":[{"id":"26f2c4a0-4394-a0ef-1d59-a342b53a6399","title":"Circle Theorems Flashcards","topicId":"0e01ecae-68ef-4b64-b192-8309c79c252e","topicSlug":"grade-6-6-10-circle-theorems","cards":[{"id":"23341384-9c3e-7b78-97c0-d7c3e5dc893e","cardType":"cloze","points":null,"front":"A [ ] is a straight line joining two points on the circumference.","back":"A chord is a straight line joining two points on the circumference.","mcqOptions":[{"text":"chord","correct":true,"explanation":"A chord is a line segment whose two endpoints lie on the circumference of a circle."},{"text":"radius","correct":false,"explanation":"A radius joins the centre to the circumference, not two points on the circumference. The required line segment is a chord."},{"text":"diameter","correct":false,"explanation":"A diameter passes through the centre, which is not required here. A line segment joining any two points on the circumference is a chord."},{"text":"tangent","correct":false,"explanation":"A tangent meets the circle at exactly one point rather than joining two points on it. The correct term is chord."}]},{"id":"9a6fb2cb-2f96-aae4-e90e-efb99a6baf90","cardType":"cloze","points":null,"front":"A [ ] touches a circle at exactly one point.","back":"A tangent touches a circle at exactly one point.","mcqOptions":[{"text":"tangent","correct":true,"explanation":"A tangent is a straight line that meets a circle at exactly one point, called the point of contact."},{"text":"chord","correct":false,"explanation":"A chord is a line segment joining two points on the circumference. A line touching the circle at exactly one point is a tangent."},{"text":"secant","correct":false,"explanation":"A secant crosses the circle and meets its circumference at two points. A line meeting it at exactly one point is a tangent."},{"text":"radius","correct":false,"explanation":"A radius joins the centre of the circle to its circumference. The line that touches the circle at one point is a tangent."}]},{"id":"40d669cd-57fd-8448-6f57-dba8a6165b44","cardType":"basic","points":1,"front":"What fact lets you mark OA and OB equal when O is the centre and A and B lie on the circle?","back":"All radii in the same circle are equal.","mcqOptions":[{"text":"All radii in the same circle are equal.","correct":true,"explanation":"OA and OB both run from the centre O to the circumference, so both are radii of the same circle and must have equal lengths."},{"text":"All chords in the same circle are equal.","correct":false,"explanation":"Chords in the same circle can have different lengths depending on their distance from the centre. OA and OB are equal because they are radii."},{"text":"All radii in different circles are equal.","correct":false,"explanation":"Radii are equal only when they belong to the same circle; different circles may have different sizes. OA and OB are radii of one circle."},{"text":"All lines from the centre are equal.","correct":false,"explanation":"Only segments from the centre to the circumference are necessarily radii. OA and OB are equal specifically because both are radii of the same circle."}]},{"id":"8b196171-51a3-1a22-693f-e4d6ce00146a","cardType":"basic","points":1,"front":"If two sides of a triangle are radii of the same circle, what type of triangle is it?","back":"An isosceles triangle.","mcqOptions":[{"text":"An isosceles triangle.","correct":true,"explanation":"Two radii of the same circle have equal lengths, so the triangle has two equal sides and is therefore an isosceles triangle."},{"text":"An equilateral triangle.","correct":false,"explanation":"Two equal radii guarantee only two equal sides, not all three. The triangle must be isosceles, but it is not necessarily equilateral."},{"text":"A scalene triangle.","correct":false,"explanation":"A scalene triangle has three unequal sides, which contradicts the fact that the two radii are equal. The triangle is isosceles."},{"text":"A right-angled triangle.","correct":false,"explanation":"Equal radii do not guarantee a 90° angle. They create two equal sides, so the triangle is isosceles rather than necessarily right-angled."}]},{"id":"774ca779-04e2-1e9e-6a7f-3dc35e1dcfd7","cardType":"basic","points":1,"front":"In triangle AOB, OA=OB and ∠ABO=42°. What is ∠OAB?","back":"42°.","mcqOptions":[{"text":"42°.","correct":true,"explanation":"OA and OB are equal radii, making AOB isosceles. Its base angles at A and B are therefore equal, so ∠OAB is 42°."},{"text":"48°.","correct":false,"explanation":"Subtracting 42° from 90° incorrectly assumes the triangle is right-angled. Since OA and OB are equal, both base angles are 42°."},{"text":"84°.","correct":false,"explanation":"Doubling the given base angle does not find the other base angle. In an isosceles triangle the base angles are equal, so ∠OAB is 42°."},{"text":"96°.","correct":false,"explanation":"This is the angle at O after subtracting both 42° base angles from 180°. The requested base angle ∠OAB is 42°."}]},{"id":"1e62a45f-6edc-91c3-51ca-76b82a7ec63f","cardType":"basic","points":1,"front":"In triangle AOB, the base angles are 42° and 42°. What is ∠AOB?","back":"96°.","mcqOptions":[{"text":"96°.","correct":true,"explanation":"Angles in a triangle total 180°. Subtracting both base angles gives $180°-42°-42°=96°$, so ∠AOB is 96°."},{"text":"84°.","correct":false,"explanation":"Adding the two base angles gives 84°, but the question asks for the remaining angle. Subtracting 84° from 180° gives 96°."},{"text":"138°.","correct":false,"explanation":"Subtracting only one 42° angle overlooks the second base angle. Both must be removed from 180°, giving ∠AOB as 96°."},{"text":"42°.","correct":false,"explanation":"The equal base angles are each 42°, but the angle at O is different. Triangle angles total 180°, so ∠AOB is 96°."}]},{"id":"ff9cf4e6-c04e-4088-2eec-557281734286","cardType":"cloze","points":null,"front":"A tangent to a circle is [ ] to the radius at the point of contact.","back":"A tangent to a circle is perpendicular to the radius at the point of contact.","mcqOptions":[{"text":"perpendicular","correct":true,"explanation":"At the point of contact, a tangent and the radius drawn to that point meet at a right angle, so they are perpendicular."},{"text":"parallel","correct":false,"explanation":"A tangent cannot be parallel to the radius at their shared point of contact. They meet at 90°, so the correct relationship is perpendicular."},{"text":"oblique","correct":false,"explanation":"An oblique line meets another at an angle other than 90°. The tangent-radius theorem states that these lines are perpendicular at the contact point."},{"text":"equal in length","correct":false,"explanation":"The theorem concerns the angle between the tangent and radius, not their lengths. They are perpendicular at the point of contact."}]},{"id":"3f334149-82de-d62a-7737-af9505993ca2","cardType":"basic","points":1,"front":"A tangent touches the circle at A and OA is a radius. What is the angle between OA and the tangent?","back":"90°.","mcqOptions":[{"text":"90°.","correct":true,"explanation":"A tangent is perpendicular to the radius at the point of contact. Perpendicular lines meet at a right angle, which measures 90°."},{"text":"45°.","correct":false,"explanation":"An angle of 45° is half a right angle and does not satisfy the tangent-radius theorem. OA and the tangent meet at 90°."},{"text":"180°.","correct":false,"explanation":"An angle of 180° would place OA and the tangent on one straight line. A tangent is perpendicular to the radius, giving 90°."},{"text":"0°.","correct":false,"explanation":"An angle of 0° would mean OA and the tangent point in the same direction. They are perpendicular at A, so the angle is 90°."}]},{"id":"65c1e30d-ca98-12c4-4f0f-2d3ccf2012a3","cardType":"basic","points":1,"front":"A tangent touches the circle at A. Which radius makes the 90° angle with the tangent?","back":"The radius to the point of contact.","mcqOptions":[{"text":"The radius to the point of contact.","correct":true,"explanation":"A tangent is perpendicular to the radius drawn to the point where it touches the circle, so this radius forms the 90° angle."},{"text":"The radius to the opposite point.","correct":false,"explanation":"The radius to the opposite side lies on the same diameter, but it does not meet the tangent. The perpendicular radius ends at the point of contact."},{"text":"The radius parallel to the tangent.","correct":false,"explanation":"Parallel lines do not form a 90° angle. The radius drawn to the point of contact is perpendicular to the tangent."},{"text":"The radius to the centre of the chord.","correct":false,"explanation":"A radius may be perpendicular to a chord at its midpoint, but the stated line is a tangent. The relevant radius goes to the point of contact."}]},{"id":"12a3e659-ee04-9574-4c97-7bb5136a5895","cardType":"cloze","points":null,"front":"If two angles stand on the same chord or arc, the angle at the centre is [ ] the angle at the circumference.","back":"If two angles stand on the same chord or arc, the angle at the centre is twice the angle at the circumference.","mcqOptions":[{"text":"twice","correct":true,"explanation":"For angles subtended by the same chord or arc, the angle at the centre is twice the corresponding angle at the circumference."},{"text":"half","correct":false,"explanation":"This reverses the circle theorem. The circumference angle is half the centre angle, so the angle at the centre is twice the angle at the circumference."},{"text":"equal to","correct":false,"explanation":"Equal angles arise in the same segment, not when comparing centre and circumference angles. The centre angle is twice the corresponding circumference angle."},{"text":"three times","correct":false,"explanation":"The multiplier in the centre-angle theorem is 2, not 3. The angle at the centre is twice the angle at the circumference."}]},{"id":"d3d3fba6-8903-8b28-e9ef-03b780fb2dc1","cardType":"basic","points":1,"front":"∠BOC at the centre is 74°. ∠BAC at the circumference stands on the same chord BC. What is ∠BAC?","back":"37°.","mcqOptions":[{"text":"37°.","correct":true,"explanation":"The angle at the circumference is half the angle at the centre when both stand on chord BC, so $74° \\div 2 = 37°$."},{"text":"74°.","correct":false,"explanation":"This incorrectly treats the centre and circumference angles as equal. The circumference angle is half of 74°, giving the correct answer of 37°."},{"text":"148°.","correct":false,"explanation":"This doubles the centre angle instead of halving it. Since the circumference angle is half the 74° centre angle, the correct answer is 37°."},{"text":"53°.","correct":false,"explanation":"This results from subtracting from 180°, which is not the relevant theorem. Halving the 74° centre angle gives the circumference angle of 37°."}]},{"id":"596b21cd-593d-ba72-825e-cc888f65b91c","cardType":"basic","points":1,"front":"A reflex centre angle is 220°. What is the smaller centre angle?","back":"360° - 220° = 140°.","mcqOptions":[{"text":"360° - 220° = 140°.","correct":true,"explanation":"Angles around the centre total 360°. Subtracting the 220° reflex angle leaves the smaller centre angle: $360° - 220° = 140°$."},{"text":"220° - 180° = 40°.","correct":false,"explanation":"Subtracting a straight angle does not find the remaining angle around a point. The two centre angles total 360°, so the smaller angle is 140°."},{"text":"360° - 220° = 180°.","correct":false,"explanation":"The correct method is shown, but the subtraction is inaccurate. Since $360 - 220 = 140$, the smaller centre angle is 140°."},{"text":"360° - 140° = 220°.","correct":false,"explanation":"This calculation returns the given reflex angle rather than the requested smaller angle. Subtracting 220° from 360° gives the smaller angle of 140°."}]},{"id":"27c57f0d-8c9b-5204-a010-aba253113b36","cardType":"cloze","points":null,"front":"Angles in the [ ] are equal.","back":"Angles in the same segment are equal.","mcqOptions":[{"text":"same segment","correct":true,"explanation":"Angles subtended by the same chord at points on the same side of that chord are equal, which is the same-segment circle theorem."},{"text":"same sector","correct":false,"explanation":"Being within the same sector does not guarantee equal angles. The theorem applies to angles standing on the same chord in the same segment."},{"text":"same circle","correct":false,"explanation":"Angles located in the same circle can have many different sizes. They are equal when they stand on the same chord in the same segment."},{"text":"opposite segment","correct":false,"explanation":"Angles on opposite sides of a chord are generally supplementary rather than equal. The equal-angle theorem applies to angles in the same segment."}]},{"id":"aaf1ce7e-bb1f-2fa3-5b00-b9000dd957a8","cardType":"basic","points":1,"front":"Angles ADB and ACB both stand on chord AB in the same segment. If ∠ADB=47°, what is ∠ACB?","back":"47°.","mcqOptions":[{"text":"47°.","correct":true,"explanation":"Angles ADB and ACB stand on the same chord AB in the same segment, so the same-segment theorem makes them equal at 47°."},{"text":"133°.","correct":false,"explanation":"This supplements 47° to 180°, confusing the situation with opposite angles in a cyclic quadrilateral. Same-segment angles are equal, so ∠ACB is 47°."},{"text":"94°.","correct":false,"explanation":"This doubles 47° using the centre-angle theorem, but neither stated angle is at the centre. Same-segment angles are equal, so ∠ACB is 47°."},{"text":"23.5°.","correct":false,"explanation":"This halves 47° as though one angle were at the centre. Both angles are at the circumference in the same segment, so ∠ACB is 47°."}]},{"id":"df66e152-1cec-81a9-777b-1f9919495285","cardType":"cloze","points":null,"front":"Opposite angles in a cyclic quadrilateral add to [ ].","back":"Opposite angles in a cyclic quadrilateral add to 180°.","mcqOptions":[{"text":"180°","correct":true,"explanation":"A quadrilateral whose four vertices lie on a circle is cyclic, and each pair of opposite interior angles is supplementary, adding to 180°."},{"text":"360°","correct":false,"explanation":"The four interior angles of any quadrilateral total 360°, but one opposite pair in a cyclic quadrilateral adds to 180°."},{"text":"90°","correct":false,"explanation":"An angle in a semicircle is 90°, but that is a different circle theorem. Opposite angles in a cyclic quadrilateral add to 180°."},{"text":"270°","correct":false,"explanation":"This confuses the supplementary relationship with a reflex total. Each pair of opposite angles in a cyclic quadrilateral adds to 180°, not 270°."}]},{"id":"37a71dbc-6a56-9278-4dcb-4317773002ab","cardType":"basic","points":1,"front":"ABCD is cyclic and ∠ADC=78°. What is the opposite angle ∠ABC?","back":"102°.","mcqOptions":[{"text":"102°.","correct":true,"explanation":"Opposite angles in a cyclic quadrilateral add to 180°, so $\\angle ABC = 180° - 78° = 102°$."},{"text":"78°.","correct":false,"explanation":"This incorrectly treats opposite cyclic angles as equal. They are supplementary, so subtracting 78° from 180° gives ∠ABC as 102°."},{"text":"282°.","correct":false,"explanation":"This subtracts 78° from 360°, using the total around a point. Opposite cyclic-quadrilateral angles total 180°, giving ∠ABC as 102°."},{"text":"156°.","correct":false,"explanation":"This doubles 78°, confusing the problem with the centre-angle theorem. Opposite angles in a cyclic quadrilateral sum to 180°, so ∠ABC is 102°."}]},{"id":"3a794370-034f-12a3-0b51-d8d5f8e03f29","cardType":"cloze","points":null,"front":"The [ ] links a tangent-chord angle to the angle in the opposite segment.","back":"The alternate segment theorem links a tangent-chord angle to the angle in the opposite segment.","mcqOptions":[{"text":"alternate segment theorem","correct":true,"explanation":"The alternate segment theorem states that the angle between a tangent and a chord equals the angle subtended by that chord in the opposite segment."},{"text":"same segment theorem","correct":false,"explanation":"The same segment theorem compares two angles subtended by the same chord within a circle. The tangent-chord relationship is given by the alternate segment theorem."},{"text":"angle at the centre theorem","correct":false,"explanation":"The angle at the centre theorem relates central and circumferential angles subtended by the same arc. A tangent-chord angle uses the alternate segment theorem."},{"text":"cyclic quadrilateral theorem","correct":false,"explanation":"The cyclic quadrilateral theorem states that opposite angles in a cyclic quadrilateral sum to 180°. The tangent-chord relationship is the alternate segment theorem."}]},{"id":"c3afa58f-df69-cf54-d7e8-695f4ab2938f","cardType":"basic","points":1,"front":"In triangle ABC, ∠ABC=58° and ∠ACB=71°. What is ∠BAC?","back":"51°.","mcqOptions":[{"text":"51°.","correct":true,"explanation":"Angles in a triangle sum to 180°, so ∠BAC = 180° - 58° - 71° = 51°."},{"text":"49°.","correct":false,"explanation":"This results from an arithmetic slip when subtracting the two known angles. Since triangle angles total 180°, ∠BAC = 180° - 58° - 71° = 51°."},{"text":"109°.","correct":false,"explanation":"Adding 58° and 51° does not find the remaining interior angle. The two given angles total 129°, leaving ∠BAC = 51°."},{"text":"129°.","correct":false,"explanation":"This is the sum of the two given angles, not the third angle. Subtracting 129° from the triangle total of 180° gives ∠BAC = 51°."}]},{"id":"acc423e7-0cd3-0254-e621-5b2f0fe0cfd6","cardType":"basic","points":1,"front":"At C, a tangent angle uses chord CB. In triangle ABC, which angle is in the opposite segment?","back":"∠BAC.","mcqOptions":[{"text":"∠BAC.","correct":true,"explanation":"Chord CB subtends the angle at A on the opposite circumference, so the angle in the opposite segment is ∠BAC."},{"text":"∠ABC.","correct":false,"explanation":"This angle has vertex B, one endpoint of chord CB, so it is not subtended by chord CB. The opposite-segment angle has vertex A and is ∠BAC."},{"text":"∠ACB.","correct":false,"explanation":"This angle has vertex C, where the tangent meets the chord, rather than in the opposite segment. Chord CB subtends ∠BAC at A."},{"text":"∠BOC.","correct":false,"explanation":"This is a central angle rather than an angle at the circumference in the opposite segment. The angle subtended by chord CB at A is ∠BAC."}]},{"id":"a220ece3-a0d1-eb93-0dae-eaf082f0615d","cardType":"basic","points":1,"front":"A tangent makes angle x with chord CB, and the opposite-segment angle ∠BAC is 51°. What is x?","back":"51°.","mcqOptions":[{"text":"51°.","correct":true,"explanation":"By the alternate segment theorem, the angle between the tangent and chord CB equals the angle subtended by chord CB in the opposite segment, so x = 51°."},{"text":"39°.","correct":false,"explanation":"Subtracting from 90° wrongly assumes the tangent-chord angle is complementary to ∠BAC. The alternate segment theorem makes the two angles equal, so x = 51°."},{"text":"129°.","correct":false,"explanation":"Subtracting 51° from 180° gives the supplementary exterior angle, not the stated tangent-chord angle. The alternate segment theorem gives x = 51°."},{"text":"102°.","correct":false,"explanation":"Doubling 51° confuses this theorem with the rule that an angle at the centre is twice an angle at the circumference. Here, x = 51°."}]},{"id":"f72b2ddf-e00e-900c-cad9-8e210720dcc1","cardType":"basic","points":2,"front":"In right-angled triangle OAC, OA=6 cm and AC=8 cm. What is OC?","back":"10 cm.","mcqOptions":[{"text":"10 cm.","correct":true,"explanation":"OC is the hypotenuse, so Pythagoras’ theorem gives $OC=\\sqrt{6^2+8^2}=\\sqrt{100}=10$ cm."},{"text":"14 cm.","correct":false,"explanation":"Adding the two shorter sides directly does not calculate a hypotenuse. Pythagoras’ theorem gives $OC=\\sqrt{6^2+8^2}=10$ cm."},{"text":"7 cm.","correct":false,"explanation":"Averaging the two shorter sides is not valid for finding the hypotenuse. Using Pythagoras’ theorem gives $OC=\\sqrt{36+64}=10$ cm."},{"text":"12 cm.","correct":false,"explanation":"This can result from mishandling the squared side lengths. The correct calculation is $OC=\\sqrt{6^2+8^2}=\\sqrt{100}=10$ cm."}]},{"id":"d4dee18f-0191-7a47-f813-984e1aa42339","cardType":"basic","points":1,"front":"O, B and C are collinear, with OC=10 cm and OB=6 cm. What is BC?","back":"4 cm.","mcqOptions":[{"text":"4 cm.","correct":true,"explanation":"B lies between O and C, so $OC=OB+BC$. Therefore $BC=10-6=4$ cm."},{"text":"16 cm.","correct":false,"explanation":"Adding OC and OB ignores that OB is already part of the full distance OC. Since B lies between O and C, $BC=10-6=4$ cm."},{"text":"5 cm.","correct":false,"explanation":"Halving OC would only work if B were the midpoint, which is not stated and conflicts with $OB=6$ cm. Subtraction gives $BC=4$ cm."},{"text":"6 cm.","correct":false,"explanation":"This repeats the length OB rather than finding the remaining section of OC. Since $OC=OB+BC$, $BC=10-6=4$ cm."}]}]}],"examCountdown":{"examDate":"2027-05-14","paperLabel":"Paper 1"},"heading":"Circle Theorems","title":"Circle Theorems Flashcards","topbar":{"backHref":"/gcse/maths/aqa/flashcards"},"topicSidebar":"$L38"}]}],"topicId":"0e01ecae-68ef-4b64-b192-8309c79c252e","walled":"$L39"}],"$L3a","$L3b"]