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Substitution

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Question 18

y=px+12qx2\displaystyle y = px + \frac{1}{2}qx^2y=px+21​qx2

p=7p = 7p=7 q=2q = 2q=2 x=4x = 4x=4

Work out the value of yyy.

[2]

Substitution Questions

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