Ethanoic acid has the molecular formula C2H4O2\mathrm{C_{2}H_{4}O_{2}}C2H4O2. Glucose has the molecular formula C6H12O6\mathrm{C_{6}H_{12}O_{6}}C6H12O6.
Relative atomic mass (ArA_{r}Ar): H = 1.0 C = 12.0 O = 16.0
Statement 1: The empirical formula of ethanoic acid is CH2O\mathrm{CH_{2}O}CH2O.
Statement 2: Ethanoic acid and glucose have the same empirical formula.
Statement 3: The relative formula mass of glucose is three times the relative formula mass of ethanoic acid.
Statement 4: The empirical formula of a molecule shows the actual number of each type of atom in the molecule.
Which statements are correct?
1 and 2 only
1, 2 and 3 only
2, 3 and 4 only
1, 3 and 4 only
51 exam-style questions on OCR GCSE Chemistry 2.1 Purity and separating mixtures, covering 2.1.1 Pure substances and melting point data, 2.1.2 Relative formula mass and empirical formula, 2.1.3 Formulations as useful mixtures, 2.1.4 Techniques for separating mixtures, and 2.1.5 Chromatography and Rf values. Each one has a worked solution and a mark scheme showing where the marks go.