Cube A is a nanoparticle with sides of length 5 nm.
Cube B is a coarse particle with sides of length 50 μm50\ \mathrm{\mu m}50 μm.
1 μm=1000 nm 1\ \mathrm{\mu m} = 1000\ \mathrm{nm} 1 μm=1000 nmFor a cube, surface area to volume ratio = 6 ÷ (side length).
How many times greater is the surface area to volume ratio of cube A than that of cube B?
10
1×1031\times10^{3}1×103
1×1041\times10^{4}1×104
1×10121\times10^{12}1×1012
60 exam-style questions on OCR GCSE Chemistry 2.3 Properties of materials, covering 2.3.1 Carbon bonding and the variety of organic compounds, 2.3.2 Diamond, graphite, fullerenes and graphene, 2.3.3 Bond strength, changes of state and predicting states, 2.3.4 Bulk properties and types of bonding, and 2.3.5 Nanoparticles: scale, surface area, uses and risks. Each one has a worked solution and a mark scheme showing where the marks go.