Large hydrocarbon molecules produced by fractional distillation can be cracked to form smaller, more useful molecules. Decane, C10H22\text{C}_{10}\text{H}_{22}C10H22, is cracked to form propene, C3H6\text{C}_3\text{H}_6C3H6, and one other product. This reaction can be represented by the equation:
C10H22→C3H6+X \text{C}_{10}\text{H}_{22} \rightarrow \text{C}_3\text{H}_6 + \text{X} C10H22→C3H6+XWhat is the chemical formula of the other product, X\text{X}X?
C7H14\text{C}_7\text{H}_{14}C7H14
C7H16\text{C}_7\text{H}_{16}C7H16
C8H16\text{C}_8\text{H}_{16}C8H16
C8H18\text{C}_8\text{H}_{18}C8H18
83 exam-style questions on OCR GCSE Chemistry Organic chemistry. Each one has a worked solution and a mark scheme showing where the marks go.