An open crucible containing iron wool is heated in air. All the iron is converted into iron(III) oxide.
4Fe+3O2→2Fe2O3 \mathrm{4Fe + 3O_2 \rightarrow 2Fe_2O_3} 4Fe+3O2→2Fe2O3After cooling, the crucible and its contents have gained 0.480 g.
Relative atomic masses (ArA_rAr): O = 16.0 Fe = 55.8
What mass of iron was in the crucible before heating?
1.12 g
0.837 g
0.480 g
1.67 g
134 exam-style questions on OCR GCSE Chemistry 3.1 Introducing chemical reactions, covering 3.1.1 Writing formulae and balanced chemical equations, 3.1.2 Formulae of compounds from ions, and state symbols, 3.1.3 Conservation of mass and observed changes in mass, 3.1.4 Half equations and balanced ionic equations, 3.1.5 The mole and the Avogadro constant, and 3.1.6 Stoichiometry, limiting reactants and reacting masses. Each one has a worked solution and a mark scheme showing where the marks go.