Two students heat some zinc carbonate, ZnCO3\text{ZnCO}_3ZnCO3.
Look at the equation for the reaction.
ZnCO3(s)⟶ZnO(s)+CO2(g)\text{ZnCO}_3\text{(s)} \longrightarrow \text{ZnO(s)} + \text{CO}_2\text{(g)}ZnCO3(s)⟶ZnO(s)+CO2(g) Zinc carbonate⟶Zinc oxide+Carbon dioxide\text{Zinc carbonate} \longrightarrow \text{Zinc oxide} + \text{Carbon dioxide}Zinc carbonate⟶Zinc oxide+Carbon dioxide
What is the meaning of (s) in the equation?
Look at their results.
| Mass of zinc carbonate (g) | Mass of zinc oxide (g) | Mass of carbon dioxide (g) |
|---|---|---|
| 2.51 | 1.63 | 0.88 |
| 5.02 | 3.26 | 1.76 |
| 7.53 | 4.89 | 2.64 |
| 10.04 | 6.52 | ................................... |
Complete the table.
Student A states:
"If I heat 25.1 g of zinc carbonate, I will make 8.8 g of zinc oxide and 16.3 g of carbon dioxide."
Is student A correct? Explain your answer.
Student B investigates another reaction.
Look at the equations.
2Mg(s)+O2(g)⟶2MgO(s)2\text{Mg(s)} + \text{O}_2\text{(g)} \longrightarrow 2\text{MgO(s)}2Mg(s)+O2(g)⟶2MgO(s) magnesium+oxygen⟶magnesium oxide\text{magnesium} + \text{oxygen} \longrightarrow \text{magnesium oxide}magnesium+oxygen⟶magnesium oxide
Calculate the relative formula mass of magnesium oxide, MgO\text{MgO}MgO. (Relative atomic masses: Mg=24.3\text{Mg} = 24.3Mg=24.3, O=16.0\text{O} = 16.0O=16.0)
Use the relative formula mass of magnesium oxide and the relative atomic masses of magnesium and oxygen to show if mass is conserved during this reaction.