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6.3 Interpreting and interacting with earth systems

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Question 25
F

The table shows the energy needed to produce 1 m31\ \mathrm{m^{3}}1 m3 of potable water from three sources.

SourceTreatmentEnergy needed (kWh per m3\mathrm{m^{3}}m3)
River watersedimentation, filtration, chlorination0.4
Ground waterfiltration, chlorination0.6
Sea waterdistillation25

A town produces 1200 m31200\ \mathrm{m^{3}}1200 m3 of potable water from river water and 800 m3800\ \mathrm{m^{3}}800 m3 from sea water each day.

Statement 1: Producing potable water from sea water needs more than 50 times as much energy per m3\mathrm{m^{3}}m3 as producing it from river water.

Statement 2: More than 95% of the town's daily energy use for water treatment is for treating sea water.

Statement 3: Ground water does not need to be sterilised, because it has been filtered through rocks.

Which statements are correct?

[1]
A

1 only

B

1 and 2 only

C

2 and 3 only

D

1, 2 and 3

Markscheme

6.3 Interpreting and interacting with earth systems Questions

  1. GCSE
  2. /Chemistry
  3. /6.3 Interpreting and interacting with earth systems

51 exam-style questions on OCR GCSE Chemistry 6.3 Interpreting and interacting with earth systems, covering 6.3.1 Formation and evolution of the atmosphere, 6.3.2 The greenhouse effect and climate change, 6.3.3 Sources and problems of atmospheric pollutants, and 6.3.4 Producing potable water. Each one has a worked solution and a mark scheme showing where the marks go.

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