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5.3 Equilibria

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Question 72
F

Calcium carbonate breaks down when it is heated.

CaCO3(s)⇌CaO(s)+CO2(g) \mathrm{CaCO_{3}(s) \rightleftharpoons CaO(s) + CO_{2}(g)} CaCO3​(s)⇌CaO(s)+CO2​(g)

A student heats calcium carbonate strongly in an open crucible. The reaction does not reach equilibrium.

Why does the reaction not reach equilibrium?

[1]
A

Calcium oxide is a solid, so the reverse reaction cannot happen.

B

Strong heating stops the forward reaction from happening.

C

The crucible acts as a catalyst for the forward reaction.

D

Carbon dioxide escapes, so the reverse reaction cannot happen.

Markscheme

5.3 Equilibria Questions

  1. GCSE
  2. /Chemistry
  3. /5.3 Equilibria

124 exam-style questions on OCR GCSE Chemistry 5.3 Equilibria, covering 5.3.1 Reversible reactions and dynamic equilibrium and 5.3.2 Changing the position of equilibrium. Each one has a worked solution and a mark scheme showing where the marks go.

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