Potassium sulfate solution, K2SO4(aq)\mathrm{K_{2}SO_{4}(aq)}K2SO4(aq), is electrolysed using inert electrodes.
Which half equation shows the reaction at the anode?
4OH−→O2+2H2O+4e−\mathrm{4OH^{-} \rightarrow O_{2} + 2H_{2}O + 4e^{-}}4OH−→O2+2H2O+4e−
4OH−+4e−→O2+2H2O\mathrm{4OH^{-} + 4e^{-} \rightarrow O_{2} + 2H_{2}O}4OH−+4e−→O2+2H2O
SO42−→SO4+2e−\mathrm{SO_{4}^{2-} \rightarrow SO_{4} + 2e^{-}}SO42−→SO4+2e−
2H++2e−→H2\mathrm{2H^{+} + 2e^{-} \rightarrow H_{2}}2H++2e−→H2
52 exam-style questions on OCR GCSE Chemistry 3.4 Electrolysis, covering 3.4.1 Products formed at the electrodes in electrolysis and 3.4.2 The technique of electrolysis. Each one has a worked solution and a mark scheme showing where the marks go.