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5.1.3 Concentration of a solution in mol/dm3

Concentration measures solute per volume of solution

Definition

Concentration

The amount of solute dissolved in a stated volume of solution, measured in g/dm³ or mol/dm³.

Definition

Solute

The substance that dissolves in a solvent to make a solution.

  1. A solution forms when a solute dissolves in a solvent, such as salt dissolving in water.
  2. A concentrated solution has a lot of solute in a given volume, while a dilute solution has only a little.
  3. Concentration can be measured in grams per cubic decimetre, written g/dm3\text{g/dm}^3g/dm3.
    1. One cubic decimetre is 1000 cm31000\,\text{cm}^31000cm3, which is the same as one litre.
  4. The volume used is the volume of the whole solution, not the volume of water that was added.
  5. Concentration can also be given in mol/dm3\text{mol/dm}^3mol/dm3, which uses the amount in moles of solute instead of its mass.
Key Idea

Concentration depends on two things only: how much solute there is and how much solution it is spread through.

Concentration equals mass of solute over volume

  1. The relationship is: concentration (g/dm3)=mass of solute (g)volume of solution (dm3)\text{concentration (g/dm}^3\text{)} = \frac{\text{mass of solute (g)}}{\text{volume of solution (dm}^3\text{)}}concentration (g/dm3)=volume of solution (dm3)mass of solute (g)​
  2. Convert a volume in cm3\text{cm}^3cm3 into dm3\text{dm}^3dm3 by dividing by 1000 before using the equation.
    1. So 250 cm3250\,\text{cm}^3250cm3 is 0.250 dm30.250\,\text{dm}^30.250dm3.
  3. Rearranging gives mass of solute === concentration ×\times× volume, which tells you how much solid to weigh out.
    1. Making 2.00 dm32.00\,\text{dm}^32.00dm3 of a 15.0 g/dm315.0\,\text{g/dm}^315.0g/dm3 solution needs 15.0×2.00=30.0 g15.0 \times 2.00 = 30.0\,\text{g}15.0×2.00=30.0g of solute.
  4. Give every answer with its unit, because a number alone does not say whether it is a mass, a volume or a concentration.
Example
  • Calculate the concentration of a solution made by dissolving 5.00 g5.00\,\text{g}5.00g of sodium chloride in water to make 250 cm3250\,\text{cm}^3250cm3 of solution.
  • Convert the volume: 250 cm3÷1000=0.250 dm3250\,\text{cm}^3 \div 1000 = 0.250\,\text{dm}^3250cm3÷1000=0.250dm3.
  • Divide mass by volume: 5.00 g0.250 dm3=20.0 g/dm3\dfrac{5.00\,\text{g}}{0.250\,\text{dm}^3} = 20.0\,\text{g/dm}^30.250dm35.00g​=20.0g/dm3.

How solute mass and volume affect concentration

  1. At a fixed volume, concentration is directly proportional to the mass of solute.
    1. Dissolving twice the mass of solute in the same volume doubles the concentration.
  2. For a fixed mass of solute, a larger volume of solution gives a lower concentration.
    1. Spreading the same mass through twice the volume halves the concentration.
  3. Doubling both the mass and the volume leaves the concentration unchanged.
  4. A sample of any size taken from a well-mixed solution has the same concentration as the rest of it.
Example

Adding more squash to the same glass of water makes a stronger drink, while topping the glass up with water makes it weaker, although the amount of squash in the glass has not changed.

Diluting a solution lowers its concentration

  1. When water is added, the mass of solute stays the same.
  2. The volume of solution increases, so the concentration falls.
  3. Evaporating some of the water has the opposite effect, raising the concentration because the volume decreases while the solute stays.
  4. To find a new concentration, first work out the mass of solute present, then divide it by the new volume.
Example
  • Water is added to 50.0 cm350.0\,\text{cm}^350.0cm3 of a 40.0 g/dm340.0\,\text{g/dm}^340.0g/dm3 solution until its volume is 200 cm3200\,\text{cm}^3200cm3; find the new concentration.
  • Mass of solute =40.0 g/dm3×0.0500 dm3=2.00 g= 40.0\,\text{g/dm}^3 \times 0.0500\,\text{dm}^3 = 2.00\,\text{g}=40.0g/dm3×0.0500dm3=2.00g.
  • New concentration =2.00 g0.200 dm3=10.0 g/dm3= \dfrac{2.00\,\text{g}}{0.200\,\text{dm}^3} = 10.0\,\text{g/dm}^3=0.200dm32.00g​=10.0g/dm3.

Making a solution of known concentration

  1. Weigh the solid accurately on a balance in a weighing boat or small beaker.
  2. Dissolve it in a small volume of distilled water in a beaker, stirring until no solid remains.
  3. Pour the solution into a volumetric flask and rinse the beaker and stirring rod into the flask, so no solute is left behind.
  4. Add distilled water until the bottom of the meniscus sits on the line, then stopper and invert the flask to mix.
  5. Divide the mass weighed by the volume of the flask in dm3\text{dm}^3dm3 to find the concentration.
Exam technique

When a question asks how a change affects concentration, say what happens to the mass of solute and what happens to the volume of solution, then state the effect.

Self review
  • What does a concentration of 20.0 g/dm320.0\,\text{g/dm}^320.0g/dm3 mean?
  • What is the concentration of 3.00 g3.00\,\text{g}3.00g of solute in 150 cm3150\,\text{cm}^3150cm3 of solution?
  • What happens to the concentration if the same mass of solute is dissolved in twice the volume?
  • Why does adding water lower the concentration of a solution?
  • What mass of solute is needed to make 500 cm3500\,\text{cm}^3500cm3 of a 12.0 g/dm312.0\,\text{g/dm}^312.0g/dm3 solution?
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Concentration describes how much solute is dissolved in a stated volume of solution. For molar concentration, the amount of solute is measured in moles and the volume is measured in cubic decimetres.

The formula is:

c=nV c = \frac{n}{V} c=Vn​

Here, ccc is concentration in mol/dm3\text{mol/dm}^3mol/dm3, nnn is amount of solute in mol, and VVV is volume of solution in dm3\text{dm}^3dm3. The volume is the volume of the whole solution, not just the volume of water added.

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What does a concentration of 20.0 g/dm³ mean?

5.1.3 Concentration of a solution in mol/dm3 Revision Guide

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Revision notes for OCR GCSE Chemistry 5.1.3 Concentration of a solution in mol/dm3: explanations and worked examples.

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