An atom of the transition metal isotope 2656Fe^{56}_{26}\text{Fe}2656Fe is ionized to form a 2656Fe2+^{56}_{26}\text{Fe}^{2+}2656Fe2+ ion.
Assuming the mass of the electrons is negligible compared to the nucleons, what is the ratio:
specific charge of the 2656Fe2+ ionspecific charge of the 2656Fe nucleus \frac{\text{specific charge of the }^{56}_{26}\text{Fe}^{2+}\text{ ion}}{\text{specific charge of the }^{56}_{26}\text{Fe}\text{ nucleus}} specific charge of the 2656Fe nucleusspecific charge of the 2656Fe2+ ion131313
128\frac{1}{28}281
113\frac{1}{13}131
1213\frac{12}{13}1312