A solution of sodium carbonate, Na2CO3\text{Na}_2\text{CO}_3Na2CO3, is diluted before it is analysed. A 10.0 cm3 sample of the original solution is diluted with water to make 50.0 cm3 of diluted solution. A 20.0 cm3 sample of the diluted solution is exactly neutralised by 18.0 cm3 of 0.0100 mol/dm3 hydrochloric acid.
The equation is:
Na2CO3+2HCl→2NaCl+H2O+CO2\text{Na}_2\text{CO}_3 + 2\text{HCl} \rightarrow 2\text{NaCl} + \text{H}_2\text{O} + \text{CO}_2Na2CO3+2HCl→2NaCl+H2O+CO2
Calculate the concentration of sodium carbonate in the original solution.
106 exam-style questions on AQA GCSE Chemistry 3.4 Using concentrations of solutions in mol/dm3, covering 3.4.1 Concentration in mol/dm3. Each one has a worked solution and a mark scheme showing where the marks go.