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7.3 Synthetic and naturally occurring polymers

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Question 10

A laboratory has four compounds in stock.

CompoundStructural formula
KCH2=CHCH2CH3\text{CH}_2{=}\text{CHCH}_2\text{CH}_3CH2​=CHCH2​CH3​
LCH3CH2CH2CH3\text{CH}_3\text{CH}_2\text{CH}_2\text{CH}_3CH3​CH2​CH2​CH3​
MHO-CH2-CH2-CH2-OH\text{HO-CH}_2\text{-CH}_2\text{-CH}_2\text{-OH}HO-CH2​-CH2​-CH2​-OH
NHOOC-CH2-CH2-COOH\text{HOOC-CH}_2\text{-CH}_2\text{-COOH}HOOC-CH2​-CH2​-COOH

The laboratory uses some of these compounds to make two polymers.

Polymer 1 has the repeating unit [-CH2-CH(CH2CH3)-]n\left[\text{-CH}_2\text{-CH}(\text{CH}_2\text{CH}_3)\text{-}\right]_n[-CH2​-CH(CH2​CH3​)-]n​.

Polymer 2 is a polyester.

a.

State which compound is used to make polymer 1 by addition polymerisation.

[1]
b.

Give the molecular formula of one repeating unit of polymer 1.

[1]
c.

State which two compounds can react repeatedly to make polymer 2.

[1]
d.

Name the small molecule produced each time a new link forms in polymer 2.

[1]
Markscheme

7.3 Synthetic and naturally occurring polymers Questions

  1. GCSE
  2. /Chemistry
  3. /7.3 Synthetic and naturally occurring polymers

94 exam-style questions on AQA GCSE Chemistry 7.3 Synthetic and naturally occurring polymers, covering 7.3.1 Addition polymerisation, 7.3.2 Condensation polymerisation, 7.3.3 Amino acids, and 7.3.4 DNA (deoxyribonucleic acid) and other naturally occurring polymers. Each one has a worked solution and a mark scheme showing where the marks go.

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