The reversible reaction shown reaches equilibrium in a closed container.
CO(g)+H2O(g)⇌CO2(g)+H2(g)\text{CO(g)} + \text{H}_2\text{O(g)} \rightleftharpoons \text{CO}_2\text{(g)} + \text{H}_2\text{(g)}CO(g)+H2O(g)⇌CO2(g)+H2(g)
Carbon dioxide is added at constant temperature.
What is the effect on the equilibrium amount of carbon monoxide?
The amount stays the same because the forward and reverse reactions regain equal rates
The amount increases because the equilibrium moves left to use some of the added carbon dioxide
The amount decreases because the equilibrium moves right to use some of the added carbon dioxide
The amount decreases because adding a product makes more products form at equilibrium
109 exam-style questions on AQA GCSE Chemistry 6.2 Reversible reactions and dynamic equilibrium, covering 6.2.1 Reversible reactions, 6.2.2 Energy changes and reversible reactions, 6.2.3 Equilibrium, 6.2.4 The effect of changing conditions on equilibrium, 6.2.5 The effect of changing concentration, 6.2.6 The effect of temperature changes on equilibrium, and 6.2.7 The effect of pressure changes on equilibrium. Each one has a worked solution and a mark scheme showing where the marks go.