A student titrated 20.0 cm320.0\text{ cm}^320.0 cm3 portions of dilute sulfuric acid with a 0.150 mol/dm30.150\text{ mol/dm}^30.150 mol/dm3 potassium hydroxide solution.
The student's results are shown below:
| Titration | 1 | 2 | 3 | 4 | 5 |
|---|---|---|---|---|---|
| Volume of potassium hydroxide solution (in cm3\text{cm}^3cm3) | 19.50 | 18.10 | 18.60 | 18.55 | 18.65 |
The equation for the reaction is: 2KOH+H2SO4→K2SO4+2H2O2\text{KOH} + \text{H}_2\text{SO}_4 \rightarrow \text{K}_2\text{SO}_4 + 2\text{H}_2\text{O}2KOH+H2SO4→K2SO4+2H2O
Calculate the concentration of the sulfuric acid in mol/dm3\text{mol/dm}^3mol/dm3.
Use only the student's concordant results. Concordant results are those within 0.10 cm30.10\text{ cm}^30.10 cm3 of each other.