Butanedioic acid is a solid at room temperature.
Calculate the mass of butanedioic acid (H2C4H4O4\text{H}_2\text{C}_4\text{H}_4\text{O}_4H2C4H4O4) needed to make 250 cm3250\text{ cm}^3250 cm3 of a solution with concentration 0.0500 mol/dm30.0500\text{ mol/dm}^30.0500 mol/dm3.
Relative formula mass (MrM_rMr): H2C4H4O4=118\text{H}_2\text{C}_4\text{H}_4\text{O}_4 = 118H2C4H4O4=118
A student found that 25.0 cm325.0\text{ cm}^325.0 cm3 of a sodium hydroxide solution was neutralised by 18.50 cm318.50\text{ cm}^318.50 cm3 of the 0.0500 mol/dm30.0500\text{ mol/dm}^30.0500 mol/dm3 butanedioic acid solution.
The equation for the reaction is:
H2C4H4O4+2NaOH→Na2C4H4O4+2H2O \text{H}_2\text{C}_4\text{H}_4\text{O}_4 + 2 \text{NaOH} \rightarrow \text{Na}_2\text{C}_4\text{H}_4\text{O}_4 + 2\text{H}_2\text{O} H2C4H4O4+2NaOH→Na2C4H4O4+2H2OCalculate the concentration of the sodium hydroxide solution in mol/dm3\text{mol/dm}^3mol/dm3.
40 exam-style questions on AQA GCSE Chemistry 4.2 Reactions of acids, covering 4.2.1 Reactions of acids with metals, 4.2.2 Neutralisation of acids and salt production, 4.2.3 Soluble salts, 4.2.4 The pH scale and neutralisation, 4.2.5 Titrations, and 4.2.6 Strong and weak acids (HT only). Each one has a worked solution and a mark scheme showing where the marks go.