In a titration, 20.00 cm320.00\text{ cm}^320.00 cm3 of nitric acid (HNO3\text{HNO}_3HNO3) reacted with 24.00 cm324.00\text{ cm}^324.00 cm3 of 0.0500 mol/dm30.0500\text{ mol/dm}^30.0500 mol/dm3 barium hydroxide solution (Ba(OH)2\text{Ba(OH)}_2Ba(OH)2).
The equation for the reaction is:
2HNO3(aq)+Ba(OH)2(aq)→Ba(NO3)2(aq)+2H2O(l)2\text{HNO}_3(\text{aq}) + \text{Ba(OH)}_2(\text{aq}) \rightarrow \text{Ba(NO}_3)_2(\text{aq}) + 2\text{H}_2\text{O(l)}2HNO3(aq)+Ba(OH)2(aq)→Ba(NO3)2(aq)+2H2O(l)
Calculate the concentration of the nitric acid in mol/dm3\text{mol/dm}^3mol/dm3.