During the thermal cracking of one molecule of dodecane (C12H26\text{C}_{12}\text{H}_{26}C12H26), one molecule of butane (C4H10\text{C}_4\text{H}_{10}C4H10) and two molecules of a hydrocarbon Y Y\,Y are produced.
Which option correctly identifies the molecular formula of Y Y\,Y and its homologous series?
Molecular formula: C4H8\text{C}_4\text{H}_8C4H8; Homologous series: Alkene
Molecular formula: C4H10\text{C}_4\text{H}_{10}C4H10; Homologous series: Alkane
Molecular formula: C8H16\text{C}_8\text{H}_{16}C8H16; Homologous series: Alkene
Molecular formula: C4H8\text{C}_4\text{H}_8C4H8; Homologous series: Alkane