A molten ionic compound splits into a metal and a non-metal
Molten
Heated until it has melted into a liquid.
Electrolysis
The decomposition of an ionic compound, when molten or in solution, by passing an electric current through it.
- Heating an ionic compound until it is molten frees its ions so it can be electrolysed.
- The metal forms at the cathode and the non-metal forms at the anode.
- A simple binary compound gives just these two elements.
- Metal to the cathode: positive metal ions gain electrons.
- Non-metal to the anode: negative ions lose electrons.
Molten lead bromide gives lead and bromine
Cathode
The negative electrode during electrolysis, where positively charged ions gain electrons.
Anode
The positive electrode during electrolysis, where negatively charged ions lose electrons.
- Molten lead bromide, PbBr2\text{PbBr}_2PbBr2, contains Pb2+\text{Pb}^{2+}Pb2+ ions and Br−\text{Br}^{-}Br− ions.
- At the cathode, lead ions are reduced to a bead of molten lead.
- Pb2++2e−→Pb\text{Pb}^{2+} + 2\text{e}^{-} \rightarrow \text{Pb}Pb2++2e−→Pb
- At the anode, bromide ions are oxidised to orange-brown bromine vapour.
- 2Br−→Br2+2e−2\text{Br}^{-} \rightarrow \text{Br}_2 + 2\text{e}^{-}2Br−→Br2+2e−
- A grey bead of molten lead collects under the cathode.
- Choking orange-brown bromine vapour is given off at the anode.
Predicting the products of any molten compound
Ion
An atom or group of atoms with an overall electrical charge because electrons have been lost or gained.
- Identify the metal ion and the non-metal ion in the compound.
- Send the metal to the cathode and the non-metal to the anode.
- For example, molten sodium chloride gives sodium at the cathode and chlorine at the anode.
- Write a half equation for each electrode to show the electron transfer.
- Why must an ionic compound be melted before this electrolysis?
- Which element forms at the cathode in molten lead bromide?
- Write the anode half equation for molten lead bromide.
- What are the two products of electrolysing molten sodium chloride?
- How do you decide which product forms at each electrode?