32:I[196793,["/_next/static/chunks/04dz0xqjvyj1r.js?dpl=nogit-1790430181","/_next/static/chunks/0p4rexedanx97.js?dpl=nogit-1790430181","/_next/static/chunks/2epfhfe5im7r6.js?dpl=nogit-1790430181","/_next/static/chunks/176p1wltq5_f6.js?dpl=nogit-1790430181","/_next/static/chunks/1f95q9c4h-8pl.js?dpl=nogit-1790430181","/_next/static/chunks/0u008gt6051u7.js?dpl=nogit-1790430181","/_next/static/chunks/1odwrcl12kfnl.js?dpl=nogit-1790430181","/_next/static/chunks/0zkcxwtbsqliz.js?dpl=nogit-1790430181","/_next/static/chunks/2u46tugibrk1v.js?dpl=nogit-1790430181","/_next/static/chunks/3ao1re0xmmur_.js?dpl=nogit-1790430181","/_next/static/chunks/03q735zs9dbpu.js?dpl=nogit-1790430181","/_next/static/chunks/3r5hh4t0jf4es.js?dpl=nogit-1790430181","/_next/static/chunks/3ht89vb0p09bm.js?dpl=nogit-1790430181","/_next/static/chunks/3ml3vooxhiupb.js?dpl=nogit-1790430181","/_next/static/chunks/12xoy6h_w_le6.js?dpl=nogit-1790430181","/_next/static/chunks/3jpl-42mbad5n.js?dpl=nogit-1790430181","/_next/static/chunks/2os7nxouq91eq.js?dpl=nogit-1790430181","/_next/static/chunks/3ocoqwe4aht_u.js?dpl=nogit-1790430181","/_next/static/chunks/330aj5rw-3o2w.js?dpl=nogit-1790430181","/_next/static/chunks/1h4wccj42vygd.js?dpl=nogit-1790430181","/_next/static/chunks/3xa2z7fbv2riw.js?dpl=nogit-1790430181","/_next/static/chunks/14kf-an-d2n-e.js?dpl=nogit-1790430181","/_next/static/chunks/381o-754ev9ia.js?dpl=nogit-1790430181","/_next/static/chunks/2th820ily21xq.js?dpl=nogit-1790430181","/_next/static/chunks/0v4byuex1x38h.js?dpl=nogit-1790430181","/_next/static/chunks/3kom3ps_bn2q6.js?dpl=nogit-1790430181","/_next/static/chunks/1x_yxljsdq0vl.js?dpl=nogit-1790430181","/_next/static/chunks/1xkpwfqqdrdio.js?dpl=nogit-1790430181","/_next/static/chunks/0k-y_4mcfub-p.js?dpl=nogit-1790430181","/_next/static/chunks/2dx-vzwyw9a3g.js?dpl=nogit-1790430181","/_next/static/chunks/2mv9l1xl_aa4j.js?dpl=nogit-1790430181","/_next/static/chunks/3dcuhw7_p-nlv.js?dpl=nogit-1790430181","/_next/static/chunks/04zr-wqafvwoa.js?dpl=nogit-1790430181","/_next/static/chunks/1ku-vdy4ggo41.js?dpl=nogit-1790430181","/_next/static/chunks/2a4uxh-kqx1wo.js?dpl=nogit-1790430181","/_next/static/chunks/2-3hvjs177r4z.js?dpl=nogit-1790430181","/_next/static/chunks/0llqhg6-bxn_b.js?dpl=nogit-1790430181","/_next/static/chunks/1l2yee13s4kff.js?dpl=nogit-1790430181","/_next/static/chunks/1pp_uf_jx5j9r.js?dpl=nogit-1790430181","/_next/static/chunks/1s6j_7_p0ugo9.js?dpl=nogit-1790430181","/_next/static/chunks/2vg15qyptj-oc.js?dpl=nogit-1790430181","/_next/static/chunks/2b6r02yb2zswo.js?dpl=nogit-1790430181","/_next/static/chunks/12mv6p8rwcl5o.js?dpl=nogit-1790430181","/_next/static/chunks/422ba61wql3d7.js?dpl=nogit-1790430181","/_next/static/chunks/2opkuzmjw8cxb.js?dpl=nogit-1790430181","/_next/static/chunks/34ux0fo6f-rm8.js?dpl=nogit-1790430181","/_next/static/chunks/3h4suq-9gmzwh.js?dpl=nogit-1790430181","/_next/static/chunks/0rt2_go1it43r.js?dpl=nogit-1790430181","/_next/static/chunks/0v5zhouho0zlq.js?dpl=nogit-1790430181","/_next/static/chunks/1gtlwpzgzi12z.js?dpl=nogit-1790430181","/_next/static/chunks/2zwoemojbdlmi.js?dpl=nogit-1790430181","/_next/static/chunks/2y341-r8ncizo.js?dpl=nogit-1790430181","/_next/static/chunks/3jzaxe43n3e1e.js?dpl=nogit-1790430181","/_next/static/chunks/3xz_lj7nwz2k-.js?dpl=nogit-1790430181","/_next/static/chunks/0zg1om_k0m5zv.js?dpl=nogit-1790430181","/_next/static/chunks/1lsxkfxy262n-.js?dpl=nogit-1790430181","/_next/static/chunks/1ksyn9m68446d.js?dpl=nogit-1790430181","/_next/static/chunks/2tgvlfspjb-j8.js?dpl=nogit-1790430181","/_next/static/chunks/0pdzmybpnr872.js?dpl=nogit-1790430181","/_next/static/chunks/1zt4k83kx3bkw.js?dpl=nogit-1790430181","/_next/static/chunks/200x0be4hbjpj.js?dpl=nogit-1790430181","/_next/static/chunks/35bn8r0ao86_s.js?dpl=nogit-1790430181","/_next/static/chunks/3wqp-h5xnebw9.js?dpl=nogit-1790430181","/_next/static/chunks/120-bka6zq5lp.js?dpl=nogit-1790430181","/_next/static/chunks/30dopbgd1dkf9.js?dpl=nogit-1790430181","/_next/static/chunks/43ajf4ofaeu5y.js?dpl=nogit-1790430181"],"Gingerbread"] 34:I[647935,["/_next/static/chunks/04dz0xqjvyj1r.js?dpl=nogit-1790430181","/_next/static/chunks/0p4rexedanx97.js?dpl=nogit-1790430181","/_next/static/chunks/2epfhfe5im7r6.js?dpl=nogit-1790430181","/_next/static/chunks/176p1wltq5_f6.js?dpl=nogit-1790430181","/_next/static/chunks/1f95q9c4h-8pl.js?dpl=nogit-1790430181","/_next/static/chunks/0u008gt6051u7.js?dpl=nogit-1790430181","/_next/static/chunks/1odwrcl12kfnl.js?dpl=nogit-1790430181","/_next/static/chunks/0zkcxwtbsqliz.js?dpl=nogit-1790430181","/_next/static/chunks/2u46tugibrk1v.js?dpl=nogit-1790430181","/_next/static/chunks/3ao1re0xmmur_.js?dpl=nogit-1790430181","/_next/static/chunks/03q735zs9dbpu.js?dpl=nogit-1790430181","/_next/static/chunks/3r5hh4t0jf4es.js?dpl=nogit-1790430181","/_next/static/chunks/3ht89vb0p09bm.js?dpl=nogit-1790430181","/_next/static/chunks/3ml3vooxhiupb.js?dpl=nogit-1790430181","/_next/static/chunks/12xoy6h_w_le6.js?dpl=nogit-1790430181","/_next/static/chunks/3jpl-42mbad5n.js?dpl=nogit-1790430181","/_next/static/chunks/2os7nxouq91eq.js?dpl=nogit-1790430181","/_next/static/chunks/3ocoqwe4aht_u.js?dpl=nogit-1790430181","/_next/static/chunks/330aj5rw-3o2w.js?dpl=nogit-1790430181","/_next/static/chunks/1h4wccj42vygd.js?dpl=nogit-1790430181","/_next/static/chunks/3xa2z7fbv2riw.js?dpl=nogit-1790430181","/_next/static/chunks/14kf-an-d2n-e.js?dpl=nogit-1790430181","/_next/static/chunks/381o-754ev9ia.js?dpl=nogit-1790430181","/_next/static/chunks/2th820ily21xq.js?dpl=nogit-1790430181","/_next/static/chunks/0v4byuex1x38h.js?dpl=nogit-1790430181","/_next/static/chunks/3kom3ps_bn2q6.js?dpl=nogit-1790430181","/_next/static/chunks/1x_yxljsdq0vl.js?dpl=nogit-1790430181","/_next/static/chunks/1xkpwfqqdrdio.js?dpl=nogit-1790430181","/_next/static/chunks/0k-y_4mcfub-p.js?dpl=nogit-1790430181","/_next/static/chunks/2dx-vzwyw9a3g.js?dpl=nogit-1790430181","/_next/static/chunks/2mv9l1xl_aa4j.js?dpl=nogit-1790430181","/_next/static/chunks/3dcuhw7_p-nlv.js?dpl=nogit-1790430181","/_next/static/chunks/04zr-wqafvwoa.js?dpl=nogit-1790430181","/_next/static/chunks/1ku-vdy4ggo41.js?dpl=nogit-1790430181","/_next/static/chunks/2a4uxh-kqx1wo.js?dpl=nogit-1790430181","/_next/static/chunks/2-3hvjs177r4z.js?dpl=nogit-1790430181","/_next/static/chunks/0llqhg6-bxn_b.js?dpl=nogit-1790430181","/_next/static/chunks/1l2yee13s4kff.js?dpl=nogit-1790430181","/_next/static/chunks/1pp_uf_jx5j9r.js?dpl=nogit-1790430181","/_next/static/chunks/1s6j_7_p0ugo9.js?dpl=nogit-1790430181","/_next/static/chunks/2vg15qyptj-oc.js?dpl=nogit-1790430181","/_next/static/chunks/2b6r02yb2zswo.js?dpl=nogit-1790430181","/_next/static/chunks/12mv6p8rwcl5o.js?dpl=nogit-1790430181","/_next/static/chunks/422ba61wql3d7.js?dpl=nogit-1790430181","/_next/static/chunks/2opkuzmjw8cxb.js?dpl=nogit-1790430181","/_next/static/chunks/34ux0fo6f-rm8.js?dpl=nogit-1790430181","/_next/static/chunks/3h4suq-9gmzwh.js?dpl=nogit-1790430181","/_next/static/chunks/0rt2_go1it43r.js?dpl=nogit-1790430181","/_next/static/chunks/0v5zhouho0zlq.js?dpl=nogit-1790430181","/_next/static/chunks/1gtlwpzgzi12z.js?dpl=nogit-1790430181","/_next/static/chunks/2zwoemojbdlmi.js?dpl=nogit-1790430181","/_next/static/chunks/2y341-r8ncizo.js?dpl=nogit-1790430181","/_next/static/chunks/3jzaxe43n3e1e.js?dpl=nogit-1790430181","/_next/static/chunks/3xz_lj7nwz2k-.js?dpl=nogit-1790430181","/_next/static/chunks/0zg1om_k0m5zv.js?dpl=nogit-1790430181","/_next/static/chunks/1lsxkfxy262n-.js?dpl=nogit-1790430181","/_next/static/chunks/1ksyn9m68446d.js?dpl=nogit-1790430181","/_next/static/chunks/2tgvlfspjb-j8.js?dpl=nogit-1790430181","/_next/static/chunks/0pdzmybpnr872.js?dpl=nogit-1790430181","/_next/static/chunks/1zt4k83kx3bkw.js?dpl=nogit-1790430181","/_next/static/chunks/200x0be4hbjpj.js?dpl=nogit-1790430181","/_next/static/chunks/35bn8r0ao86_s.js?dpl=nogit-1790430181","/_next/static/chunks/3wqp-h5xnebw9.js?dpl=nogit-1790430181","/_next/static/chunks/120-bka6zq5lp.js?dpl=nogit-1790430181","/_next/static/chunks/30dopbgd1dkf9.js?dpl=nogit-1790430181","/_next/static/chunks/43ajf4ofaeu5y.js?dpl=nogit-1790430181"],"RecordResourceResume"] 35:I[830476,["/_next/static/chunks/04dz0xqjvyj1r.js?dpl=nogit-1790430181","/_next/static/chunks/0p4rexedanx97.js?dpl=nogit-1790430181","/_next/static/chunks/2epfhfe5im7r6.js?dpl=nogit-1790430181","/_next/static/chunks/176p1wltq5_f6.js?dpl=nogit-1790430181","/_next/static/chunks/1f95q9c4h-8pl.js?dpl=nogit-1790430181","/_next/static/chunks/0u008gt6051u7.js?dpl=nogit-1790430181","/_next/static/chunks/1odwrcl12kfnl.js?dpl=nogit-1790430181","/_next/static/chunks/0zkcxwtbsqliz.js?dpl=nogit-1790430181","/_next/static/chunks/2u46tugibrk1v.js?dpl=nogit-1790430181","/_next/static/chunks/3ao1re0xmmur_.js?dpl=nogit-1790430181","/_next/static/chunks/03q735zs9dbpu.js?dpl=nogit-1790430181","/_next/static/chunks/3r5hh4t0jf4es.js?dpl=nogit-1790430181","/_next/static/chunks/3ht89vb0p09bm.js?dpl=nogit-1790430181","/_next/static/chunks/3ml3vooxhiupb.js?dpl=nogit-1790430181","/_next/static/chunks/12xoy6h_w_le6.js?dpl=nogit-1790430181","/_next/static/chunks/3jpl-42mbad5n.js?dpl=nogit-1790430181","/_next/static/chunks/2os7nxouq91eq.js?dpl=nogit-1790430181","/_next/static/chunks/3ocoqwe4aht_u.js?dpl=nogit-1790430181","/_next/static/chunks/330aj5rw-3o2w.js?dpl=nogit-1790430181","/_next/static/chunks/1h4wccj42vygd.js?dpl=nogit-1790430181","/_next/static/chunks/3xa2z7fbv2riw.js?dpl=nogit-1790430181","/_next/static/chunks/14kf-an-d2n-e.js?dpl=nogit-1790430181","/_next/static/chunks/381o-754ev9ia.js?dpl=nogit-1790430181","/_next/static/chunks/2th820ily21xq.js?dpl=nogit-1790430181","/_next/static/chunks/0v4byuex1x38h.js?dpl=nogit-1790430181","/_next/static/chunks/3kom3ps_bn2q6.js?dpl=nogit-1790430181","/_next/static/chunks/1x_yxljsdq0vl.js?dpl=nogit-1790430181","/_next/static/chunks/1xkpwfqqdrdio.js?dpl=nogit-1790430181","/_next/static/chunks/0k-y_4mcfub-p.js?dpl=nogit-1790430181","/_next/static/chunks/2dx-vzwyw9a3g.js?dpl=nogit-1790430181","/_next/static/chunks/2mv9l1xl_aa4j.js?dpl=nogit-1790430181","/_next/static/chunks/3dcuhw7_p-nlv.js?dpl=nogit-1790430181","/_next/static/chunks/04zr-wqafvwoa.js?dpl=nogit-1790430181","/_next/static/chunks/1ku-vdy4ggo41.js?dpl=nogit-1790430181","/_next/static/chunks/2a4uxh-kqx1wo.js?dpl=nogit-1790430181","/_next/static/chunks/2-3hvjs177r4z.js?dpl=nogit-1790430181","/_next/static/chunks/0llqhg6-bxn_b.js?dpl=nogit-1790430181","/_next/static/chunks/1l2yee13s4kff.js?dpl=nogit-1790430181","/_next/static/chunks/1pp_uf_jx5j9r.js?dpl=nogit-1790430181","/_next/static/chunks/1s6j_7_p0ugo9.js?dpl=nogit-1790430181","/_next/static/chunks/2vg15qyptj-oc.js?dpl=nogit-1790430181","/_next/static/chunks/2b6r02yb2zswo.js?dpl=nogit-1790430181","/_next/static/chunks/12mv6p8rwcl5o.js?dpl=nogit-1790430181","/_next/static/chunks/422ba61wql3d7.js?dpl=nogit-1790430181","/_next/static/chunks/2opkuzmjw8cxb.js?dpl=nogit-1790430181","/_next/static/chunks/34ux0fo6f-rm8.js?dpl=nogit-1790430181","/_next/static/chunks/3h4suq-9gmzwh.js?dpl=nogit-1790430181","/_next/static/chunks/0rt2_go1it43r.js?dpl=nogit-1790430181","/_next/static/chunks/0v5zhouho0zlq.js?dpl=nogit-1790430181","/_next/static/chunks/1gtlwpzgzi12z.js?dpl=nogit-1790430181","/_next/static/chunks/2zwoemojbdlmi.js?dpl=nogit-1790430181","/_next/static/chunks/2y341-r8ncizo.js?dpl=nogit-1790430181","/_next/static/chunks/3jzaxe43n3e1e.js?dpl=nogit-1790430181","/_next/static/chunks/3xz_lj7nwz2k-.js?dpl=nogit-1790430181","/_next/static/chunks/0zg1om_k0m5zv.js?dpl=nogit-1790430181","/_next/static/chunks/1lsxkfxy262n-.js?dpl=nogit-1790430181","/_next/static/chunks/1ksyn9m68446d.js?dpl=nogit-1790430181","/_next/static/chunks/2tgvlfspjb-j8.js?dpl=nogit-1790430181","/_next/static/chunks/0pdzmybpnr872.js?dpl=nogit-1790430181","/_next/static/chunks/1zt4k83kx3bkw.js?dpl=nogit-1790430181","/_next/static/chunks/200x0be4hbjpj.js?dpl=nogit-1790430181","/_next/static/chunks/35bn8r0ao86_s.js?dpl=nogit-1790430181","/_next/static/chunks/3wqp-h5xnebw9.js?dpl=nogit-1790430181","/_next/static/chunks/120-bka6zq5lp.js?dpl=nogit-1790430181","/_next/static/chunks/30dopbgd1dkf9.js?dpl=nogit-1790430181","/_next/static/chunks/43ajf4ofaeu5y.js?dpl=nogit-1790430181"],"FlashcardAccessBranch"] 36:I[315438,["/_next/static/chunks/04dz0xqjvyj1r.js?dpl=nogit-1790430181","/_next/static/chunks/0p4rexedanx97.js?dpl=nogit-1790430181","/_next/static/chunks/2epfhfe5im7r6.js?dpl=nogit-1790430181","/_next/static/chunks/176p1wltq5_f6.js?dpl=nogit-1790430181","/_next/static/chunks/1f95q9c4h-8pl.js?dpl=nogit-1790430181","/_next/static/chunks/0u008gt6051u7.js?dpl=nogit-1790430181","/_next/static/chunks/1odwrcl12kfnl.js?dpl=nogit-1790430181","/_next/static/chunks/0zkcxwtbsqliz.js?dpl=nogit-1790430181","/_next/static/chunks/2u46tugibrk1v.js?dpl=nogit-1790430181","/_next/static/chunks/3ao1re0xmmur_.js?dpl=nogit-1790430181","/_next/static/chunks/03q735zs9dbpu.js?dpl=nogit-1790430181","/_next/static/chunks/3r5hh4t0jf4es.js?dpl=nogit-1790430181","/_next/static/chunks/3ht89vb0p09bm.js?dpl=nogit-1790430181","/_next/static/chunks/3ml3vooxhiupb.js?dpl=nogit-1790430181","/_next/static/chunks/12xoy6h_w_le6.js?dpl=nogit-1790430181","/_next/static/chunks/3jpl-42mbad5n.js?dpl=nogit-1790430181","/_next/static/chunks/2os7nxouq91eq.js?dpl=nogit-1790430181","/_next/static/chunks/3ocoqwe4aht_u.js?dpl=nogit-1790430181","/_next/static/chunks/330aj5rw-3o2w.js?dpl=nogit-1790430181","/_next/static/chunks/1h4wccj42vygd.js?dpl=nogit-1790430181","/_next/static/chunks/3xa2z7fbv2riw.js?dpl=nogit-1790430181","/_next/static/chunks/14kf-an-d2n-e.js?dpl=nogit-1790430181","/_next/static/chunks/381o-754ev9ia.js?dpl=nogit-1790430181","/_next/static/chunks/2th820ily21xq.js?dpl=nogit-1790430181","/_next/static/chunks/0v4byuex1x38h.js?dpl=nogit-1790430181","/_next/static/chunks/3kom3ps_bn2q6.js?dpl=nogit-1790430181","/_next/static/chunks/1x_yxljsdq0vl.js?dpl=nogit-1790430181","/_next/static/chunks/1xkpwfqqdrdio.js?dpl=nogit-1790430181","/_next/static/chunks/0k-y_4mcfub-p.js?dpl=nogit-1790430181","/_next/static/chunks/2dx-vzwyw9a3g.js?dpl=nogit-1790430181","/_next/static/chunks/2mv9l1xl_aa4j.js?dpl=nogit-1790430181","/_next/static/chunks/3dcuhw7_p-nlv.js?dpl=nogit-1790430181","/_next/static/chunks/04zr-wqafvwoa.js?dpl=nogit-1790430181","/_next/static/chunks/1ku-vdy4ggo41.js?dpl=nogit-1790430181","/_next/static/chunks/2a4uxh-kqx1wo.js?dpl=nogit-1790430181","/_next/static/chunks/2-3hvjs177r4z.js?dpl=nogit-1790430181","/_next/static/chunks/0llqhg6-bxn_b.js?dpl=nogit-1790430181","/_next/static/chunks/1l2yee13s4kff.js?dpl=nogit-1790430181","/_next/static/chunks/1pp_uf_jx5j9r.js?dpl=nogit-1790430181","/_next/static/chunks/1s6j_7_p0ugo9.js?dpl=nogit-1790430181","/_next/static/chunks/2vg15qyptj-oc.js?dpl=nogit-1790430181","/_next/static/chunks/2b6r02yb2zswo.js?dpl=nogit-1790430181","/_next/static/chunks/12mv6p8rwcl5o.js?dpl=nogit-1790430181","/_next/static/chunks/422ba61wql3d7.js?dpl=nogit-1790430181","/_next/static/chunks/2opkuzmjw8cxb.js?dpl=nogit-1790430181","/_next/static/chunks/34ux0fo6f-rm8.js?dpl=nogit-1790430181","/_next/static/chunks/3h4suq-9gmzwh.js?dpl=nogit-1790430181","/_next/static/chunks/0rt2_go1it43r.js?dpl=nogit-1790430181","/_next/static/chunks/0v5zhouho0zlq.js?dpl=nogit-1790430181","/_next/static/chunks/1gtlwpzgzi12z.js?dpl=nogit-1790430181","/_next/static/chunks/2zwoemojbdlmi.js?dpl=nogit-1790430181","/_next/static/chunks/2y341-r8ncizo.js?dpl=nogit-1790430181","/_next/static/chunks/3jzaxe43n3e1e.js?dpl=nogit-1790430181","/_next/static/chunks/3xz_lj7nwz2k-.js?dpl=nogit-1790430181","/_next/static/chunks/0zg1om_k0m5zv.js?dpl=nogit-1790430181","/_next/static/chunks/1lsxkfxy262n-.js?dpl=nogit-1790430181","/_next/static/chunks/1ksyn9m68446d.js?dpl=nogit-1790430181","/_next/static/chunks/2tgvlfspjb-j8.js?dpl=nogit-1790430181","/_next/static/chunks/0pdzmybpnr872.js?dpl=nogit-1790430181","/_next/static/chunks/1zt4k83kx3bkw.js?dpl=nogit-1790430181","/_next/static/chunks/200x0be4hbjpj.js?dpl=nogit-1790430181","/_next/static/chunks/35bn8r0ao86_s.js?dpl=nogit-1790430181","/_next/static/chunks/3wqp-h5xnebw9.js?dpl=nogit-1790430181","/_next/static/chunks/120-bka6zq5lp.js?dpl=nogit-1790430181","/_next/static/chunks/30dopbgd1dkf9.js?dpl=nogit-1790430181","/_next/static/chunks/43ajf4ofaeu5y.js?dpl=nogit-1790430181"],"TopicFlashcardRunner"] 23:[["$","$L32",null,{"feature":"flashcards"}],"$L33",["$","$L34",null,{"href":"/gcse/chemistry/aqa/conservation-of-mass-and-balanced-chemical-equations/flashcards","label":"3.1.1 Conservation of mass and balanced chemical equations","subjectCode":"gcse_chemistry__aqa","surface":"flashcards"}],["$","$L35",null,{"runner":["$","div",null,{"className":"min-h-0 flex-1 overflow-hidden bg-background","children":["$","$L36",null,{"decks":[{"id":"323036a8-6142-4dc1-bc61-052cdecaf7f0","title":"3.1.1 Conservation of mass and balanced chemical equations Flashcards","topicId":"520bc0b2-19a0-5a32-acc6-8675f179bf49","topicSlug":"conservation-of-mass-and-balanced-chemical-equations","cards":[{"id":"9f81eb57-dc1a-4fa7-877c-c7c1040fb4ce","cardType":"basic","points":1,"front":"What does the law of conservation of mass state?","back":"The total mass of the products equals the total mass of the reactants.","mcqOptions":[{"text":"The total mass of the products equals the total mass of the reactants.","correct":true,"explanation":"Conservation of mass means atoms are neither created nor destroyed, so the combined mass of all products must equal the combined mass of all reactants."},{"text":"The total mass of the reactants is greater than the total mass of the products.","correct":false,"explanation":"A chemical reaction does not destroy mass. The correct relationship is that the total mass of the products equals the total mass of the reactants."},{"text":"The total mass of the products is greater than the total mass of the reactants.","correct":false,"explanation":"Products cannot gain mass from nowhere in a closed reaction. The correct statement is that the total mass of products equals the total mass of reactants."},{"text":"The total mass of the reactants is converted completely into energy.","correct":false,"explanation":"Chemical reactions rearrange atoms rather than converting all their mass into energy. The total mass of products equals the total mass of reactants."}]},{"id":"8386cadb-bfe7-4c1f-9ea9-14004e2801f0","cardType":"basic","points":2,"front":"Why does mass stay the same during a chemical reaction?","back":"Atoms are rearranged into new substances; none are created or destroyed.","mcqOptions":[{"text":"Atoms are rearranged into new substances; none are created or destroyed.","correct":true,"explanation":"Chemical bonds break and form as atoms are rearranged into different substances. The atoms themselves remain present, so no atoms are created or destroyed."},{"text":"Atoms change into energy as new substances form; none remain.","correct":false,"explanation":"Atoms are not all converted into energy during an ordinary chemical reaction. They are rearranged into new substances, with none created or destroyed."},{"text":"Molecules disappear and are replaced by new atoms; the mass is restored.","correct":false,"explanation":"Molecules can be broken apart, but their atoms do not disappear or get newly created. Atoms are rearranged into new substances, conserving mass."},{"text":"New atoms are produced to replace those used up in the reaction.","correct":false,"explanation":"Reactants are not used up by destroying their atoms. Their existing atoms are rearranged into products, so no new atoms are produced."}]},{"id":"84f9c3f3-93f5-4364-a01b-c5df4cb7bdbd","cardType":"basic","points":1,"front":"What mass of magnesium oxide forms when 48 g magnesium burns in 32 g oxygen?","back":"80 g of magnesium oxide.","mcqOptions":[{"text":"80 g of magnesium oxide.","correct":true,"explanation":"Conservation of mass gives the product mass by adding the reactant masses: 48 g + 32 g = 80 g of magnesium oxide."},{"text":"16 g of magnesium oxide.","correct":false,"explanation":"Subtracting the oxygen mass from the magnesium mass incorrectly treats oxygen as reducing the product. Adding the reactants gives 48 g + 32 g = 80 g."},{"text":"48 g of magnesium oxide.","correct":false,"explanation":"This uses only the magnesium mass and ignores oxygen incorporated into the product. The total product mass is 48 g + 32 g = 80 g."},{"text":"96 g of magnesium oxide.","correct":false,"explanation":"Doubling the magnesium mass has no chemical basis and overcounts the reactants. Conservation of mass gives 48 g + 32 g = 80 g."}]},{"id":"3d659592-1966-4e31-b3f5-4adf13831196","cardType":"cloze","points":null,"front":"A chemical reaction shuffles atoms into new [ ] without changing their numbers.","back":"A chemical reaction shuffles atoms into new combinations without changing their numbers.","mcqOptions":[{"text":"combinations","correct":true,"explanation":"Atoms can be rearranged into new combinations, producing different substances while keeping the number of atoms of each element unchanged."},{"text":"elements","correct":false,"explanation":"A reaction does not generally turn atoms into new elements. It rearranges atoms into new combinations, while each element remains the same."},{"text":"masses","correct":false,"explanation":"Mass is conserved rather than being shuffled into new masses. The sentence refers to atoms being arranged into new combinations."},{"text":"temperatures","correct":false,"explanation":"Temperature can change during a reaction, but atoms are not rearranged into temperatures. They are rearranged into new combinations."}]},{"id":"3ada2ced-3003-428d-ae41-a70207728c41","cardType":"basic","points":1,"front":"What does a symbol equation show?","back":"It shows reactants and products using their chemical formulae.","mcqOptions":[{"text":"It shows reactants and products using their chemical formulae.","correct":true,"explanation":"A symbol equation represents each reactant and product with its chemical formula, showing the substances involved in the reaction."},{"text":"It shows only the products using their chemical formulae.","correct":false,"explanation":"A symbol equation must show both sides of the reaction. It represents the reactants and products using their chemical formulae."},{"text":"It shows reactants and products using their relative masses.","correct":false,"explanation":"Relative masses are not what symbol equations primarily display. They use chemical formulae to identify the reactants and products."},{"text":"It shows the conditions without naming the substances.","correct":false,"explanation":"Reaction conditions may sometimes be written above the arrow, but the equation must identify substances using formulae for reactants and products."}]},{"id":"ac0030cd-137b-4ce0-a5cd-c96970a748e6","cardType":"basic","points":3,"front":"Where are reactants and products placed in a symbol equation?","back":"

Reactants are on the left of the arrow.
Products are on the right.

","mcqOptions":[{"text":"

Reactants are on the left of the arrow.
Products are on the right.

","correct":true,"explanation":"The arrow shows the direction of the reaction: starting substances, called reactants, are on the left and the substances formed, called products, are on the right."},{"text":"

Reactants are on the right of the arrow.
Products are on the left.

","correct":false,"explanation":"This reverses the conventional direction of a symbol equation. Reactants are placed on the left of the arrow and products on the right."},{"text":"

Reactants are above the arrow.
Products are below.

","correct":false,"explanation":"The vertical positions around an arrow are not used to identify reactants and products. Reactants go on the left, while products go on the right."},{"text":"

Reactants are on both sides of the arrow.
Products are above.

","correct":false,"explanation":"Reactants and products occupy opposite sides of the reaction arrow. Reactants are on the left and products are on the right."}]},{"id":"d6c967e0-3651-48d7-8ade-b1fc987b2919","cardType":"cloze","points":null,"front":"An equation is balanced when each element has the same number of [ ] on both sides.","back":"An equation is balanced when each element has the same number of atoms on both sides.","mcqOptions":[{"text":"atoms","correct":true,"explanation":"A balanced equation has the same number of atoms of every element on both sides, representing conservation of each type of atom."},{"text":"molecules","correct":false,"explanation":"The numbers of molecules do not have to match on both sides. The required condition is an equal number of atoms of each element."},{"text":"bonds","correct":false,"explanation":"Chemical bonds are broken and formed during reactions, so their numbers can change. Balance requires equal numbers of each element's atoms."},{"text":"compounds","correct":false,"explanation":"The numbers of compounds can differ between reactants and products. What must match is the number of atoms of each element."}]},{"id":"133f6448-a5ca-472a-8c88-2448cad03c41","cardType":"basic","points":1,"front":"What is the balanced equation for magnesium burning?","back":"$$2\\text{Mg} + \\text{O}_2 \\rightarrow 2\\text{MgO}$","mcqOptions":[{"text":"$$2\\text{Mg} + \\text{O}_2 \\rightarrow 2\\text{MgO}$","correct":true,"explanation":"There are two magnesium atoms and two oxygen atoms on each side, so this equation is balanced while retaining the correct formulae for magnesium, oxygen and magnesium oxide."},{"text":"$$\\text{Mg} + \\text{O}_2 \\rightarrow \\text{MgO}$","correct":false,"explanation":"The oxygen atoms are unbalanced here: two occur in oxygen but only one in magnesium oxide. Adding a multiplier of 2 to Mg and MgO gives the correct equation."},{"text":"$$\\text{Mg}_2 + \\text{O}_2 \\rightarrow 2\\text{MgO}$","correct":false,"explanation":"Changing the magnesium subscript invents a different formula and substance. The correct balance changes only multipliers: $2\\text{Mg} + \\text{O}_2 \\rightarrow 2\\text{MgO}$."},{"text":"$$2\\text{Mg} + 2\\text{O}_2 \\rightarrow 2\\text{MgO}$","correct":false,"explanation":"This leaves four oxygen atoms on the left but only two on the right. One oxygen molecule is sufficient, giving $2\\text{Mg} + \\text{O}_2 \\rightarrow 2\\text{MgO}$."}]},{"id":"3eb54681-f498-4de5-8297-634f23a54fe8","cardType":"basic","points":2,"front":"What does a multiplier do in a chemical formula?","back":"It multiplies every atom in the whole formula.","mcqOptions":[{"text":"It multiplies every atom in the whole formula.","correct":true,"explanation":"A multiplier applies to the entire formula. For example, $2\\text{H}_2\\text{O}$ contains twice as many hydrogen and oxygen atoms as one water molecule."},{"text":"It multiplies only the first atom in the formula.","correct":false,"explanation":"A multiplier affects every atom represented by the formula, not just the first element. Applying it to only one atom would give incorrect atom counts."},{"text":"It multiplies only the subscript immediately after it.","correct":false,"explanation":"A multiplier is different from a subscript and applies to the whole formula. The subscript describes a local atom count, whereas the multiplier scales the complete formula."},{"text":"It multiplies the charge but not the atoms.","correct":false,"explanation":"Multipliers change the number of formula units and therefore every atom in them. They do not independently multiply a charge while leaving atom counts unchanged."}]},{"id":"dab2c143-7129-47ed-9caf-3c42a3a7064c","cardType":"basic","points":1,"front":"What does a subscript count in a chemical formula?","back":"It counts atoms of the element immediately before it.","mcqOptions":[{"text":"It counts atoms of the element immediately before it.","correct":true,"explanation":"A subscript belongs to the element symbol immediately before it. If there is no subscript, that element has an implied count of one."},{"text":"It counts atoms of the whole formula after it.","correct":false,"explanation":"A subscript does not scale an entire formula; that is the role of a multiplier. It counts the element symbol immediately before the subscript."},{"text":"It counts atoms of the next element in the equation.","correct":false,"explanation":"Subscripts are read within one chemical formula and do not refer to another element elsewhere in the equation. They apply to the preceding element symbol."},{"text":"It counts the number of molecules in the formula.","correct":false,"explanation":"A subscript gives the number of atoms of a particular element within one formula unit. The number of molecules or formula units is shown by a multiplier."}]},{"id":"165fb037-1b89-451d-a3ac-ae76a6c4a2f3","cardType":"basic","points":3,"front":"What does $3\\text{H}_2\\text{O}$ contain?","back":"Six hydrogen atoms and three oxygen atoms.","mcqOptions":[{"text":"Six hydrogen atoms and three oxygen atoms.","correct":true,"explanation":"Each water molecule contains two hydrogen atoms and one oxygen atom. The multiplier 3 triples both counts, giving six hydrogen atoms and three oxygen atoms."},{"text":"Three hydrogen atoms and three oxygen atoms.","correct":false,"explanation":"The multiplier gives three water molecules, but each contains two hydrogen atoms. The correct counts are six hydrogen atoms and three oxygen atoms."},{"text":"Six hydrogen atoms and six oxygen atoms.","correct":false,"explanation":"Only hydrogen has a subscript of 2 in the formula. Tripling the one oxygen atom per molecule gives three oxygen atoms, not six."},{"text":"Two hydrogen atoms and one oxygen atom.","correct":false,"explanation":"Those are the counts in one water molecule and ignore the multiplier 3. Three water molecules contain six hydrogen atoms and three oxygen atoms."}]},{"id":"27136edf-66df-4545-8bae-b24d0c6e1283","cardType":"cloze","points":null,"front":"Only the [ ] in front of formulae may be changed when balancing equations.","back":"Only the multipliers in front of formulae may be changed when balancing equations.","mcqOptions":[{"text":"multipliers","correct":true,"explanation":"Balancing changes the number of formula units by adding whole-number multipliers. This alters atom totals without changing the identity of any substance."},{"text":"subscripts","correct":false,"explanation":"Changing a subscript changes the chemical formula and therefore the substance represented. Balance equations by changing multipliers placed before formulae."},{"text":"element symbols","correct":false,"explanation":"Changing an element symbol replaces one element with another and changes the reaction. Only multipliers may be adjusted during balancing."},{"text":"charges","correct":false,"explanation":"Changing charges would alter the chemical species rather than balance atom numbers. The permitted changes are whole-number multipliers before formulae."}]},{"id":"d84c93a8-c982-4645-bf37-212e089398f8","cardType":"basic","points":2,"front":"Why must subscripts never be changed when balancing an equation?","back":"Changing a subscript makes a different substance.","mcqOptions":[{"text":"Changing a subscript makes a different substance.","correct":true,"explanation":"A subscript is part of a substance's formula and specifies its composition. Changing it changes the ratio of atoms and therefore represents a different substance."},{"text":"Changing a subscript makes a larger amount of the same substance.","correct":false,"explanation":"A larger amount is represented by a multiplier before the formula. Changing a subscript changes the composition and produces a different substance."},{"text":"Changing a subscript makes the reaction happen faster.","correct":false,"explanation":"Reaction speed depends on conditions such as temperature and concentration, not on altering formula subscripts. A changed subscript represents a different substance."},{"text":"Changing a subscript removes the need to conserve mass.","correct":false,"explanation":"Conservation of mass still applies to every chemical reaction. Changing a subscript does not avoid balancing; it changes the substance being represented."}]},{"id":"f66821db-3228-48af-9bb8-2d2f8ca76fde","cardType":"basic","points":1,"front":"What is the first step when balancing an equation?","back":"Write the correct formula for every reactant and product.","mcqOptions":[{"text":"Write the correct formula for every reactant and product.","correct":true,"explanation":"Balancing is meaningful only after the substances have their correct formulae. Changing formulae while balancing would change the substances rather than their amounts."},{"text":"Add multipliers before guessed formulae.","correct":false,"explanation":"Multipliers cannot correct an incorrect chemical formula. First write the correct formula for every reactant and product, then adjust multipliers to balance atoms."},{"text":"Change the subscripts in each formula.","correct":false,"explanation":"Subscripts define composition and must remain fixed. The first step is to write correct formulae, after which only multipliers are changed."},{"text":"Count the products before writing reactants.","correct":false,"explanation":"Atom counting comes after all correct formulae are written. The first step is to write the correct formula for every reactant and product."}]},{"id":"cb20617a-a3fa-4be9-8f85-11423c0c59f7","cardType":"basic","points":3,"front":"How are atom counts used to balance an equation?","back":"

Count each element on both sides.
Add whole-number multipliers until the counts match.

","mcqOptions":[{"text":"

Count each element on both sides.
Add whole-number multipliers until the counts match.

","correct":true,"explanation":"Balancing compares each element's atom count on both sides, then uses whole-number multipliers to make every corresponding count equal."},{"text":"

Count each molecule on both sides.
Add whole-number subscripts until the counts match.

","correct":false,"explanation":"Molecule totals need not match, and changing subscripts changes substances. Count atoms of each element and adjust whole-number multipliers instead."},{"text":"

Count each element only on the product side.
Add decimal multipliers until the counts match.

","correct":false,"explanation":"Both sides must be counted, and GCSE balanced equations use whole-number multipliers. Compare every element on both sides and adjust those multipliers."},{"text":"

Count the formulae on both sides.
Change the element symbols until the counts match.

","correct":false,"explanation":"Counting formulae does not establish atom conservation, and changing element symbols changes the reaction. Count each element's atoms and alter only whole-number multipliers."}]},{"id":"5da20dba-73eb-4cf7-ab1d-377af50ba903","cardType":"basic","points":2,"front":"In balancing $\\text{CH}_4 + \\text{O}_2 \\rightarrow \\text{CO}_2 + \\text{H}_2\\text{O}$, why is $\\text{H}_2\\text{O}$ given a multiplier of 2?","back":"To give four hydrogen atoms on each side.","mcqOptions":[{"text":"To give four hydrogen atoms on each side.","correct":true,"explanation":"Methane contains four hydrogen atoms, while one water molecule contains two. A multiplier of 2 gives two water molecules and therefore four hydrogen atoms."},{"text":"To give two hydrogen atoms on each side.","correct":false,"explanation":"This counts the hydrogen atoms in one water molecule but ignores methane's four hydrogen atoms. Two water molecules are needed to match the four on the left."},{"text":"To give four oxygen atoms on each side.","correct":false,"explanation":"The multiplier of 2 applies to water and gives two oxygen atoms, not four. It is chosen to match methane's four hydrogen atoms."},{"text":"To give two carbon atoms on each side.","correct":false,"explanation":"The carbon count is already one on each side because methane and carbon dioxide each contain one carbon atom. The multiplier balances hydrogen instead."}]},{"id":"780c395c-faf0-4144-abd8-96cb1083b1b7","cardType":"basic","points":2,"front":"After putting 2 before $\\text{H}_2\\text{O}$, why is 2 put before $\\text{O}_2$?","back":"To give four oxygen atoms on each side.","mcqOptions":[{"text":"To give four oxygen atoms on each side.","correct":true,"explanation":"The coefficient 2 before water creates two oxygen atoms, while 2O₂ contains four oxygen atoms. Together with the two oxygen atoms in the water molecules, both sides contain four oxygen atoms."},{"text":"To give two oxygen atoms on each side.","correct":false,"explanation":"This counts only the oxygen atoms in the two water molecules and ignores the oxygen atoms in O₂. The coefficient 2 before O₂ is needed to provide four oxygen atoms on each side."},{"text":"To give six oxygen atoms on each side.","correct":false,"explanation":"This incorrectly adds the oxygen atoms from 2O₂ and 2H₂O as though they were on the same side. Balancing requires four oxygen atoms on each side."},{"text":"To give four oxygen molecules on each side.","correct":false,"explanation":"The equation must balance atoms, not molecules. The coefficient 2 before O₂ provides four oxygen atoms, matching the four oxygen atoms present in 2H₂O."}]},{"id":"e56d2e5f-0dd3-443a-9ecd-4495575086c9","cardType":"basic","points":1,"front":"What is the balanced equation for methane burning?","back":"$$\\text{CH}_4 + 2\\text{O}_2 \\rightarrow \\text{CO}_2 + 2\\text{H}_2\\text{O}$","mcqOptions":[{"text":"$$\\text{CH}_4 + 2\\text{O}_2 \\rightarrow \\text{CO}_2 + 2\\text{H}_2\\text{O}$","correct":true,"explanation":"One methane molecule supplies one carbon atom and four hydrogen atoms, forming CO₂ and 2H₂O. The two oxygen molecules provide four oxygen atoms, so every element is conserved."},{"text":"$$\\text{CH}_4 + \\text{O}_2 \\rightarrow \\text{CO}_2 + 2\\text{H}_2\\text{O}$","correct":false,"explanation":"The hydrogen atoms are balanced, but the products contain four oxygen atoms while the reactants contain only two. A coefficient of 2 before O₂ is required to conserve oxygen atoms."},{"text":"$$2\\text{CH}_4 + 3\\text{O}_2 \\rightarrow 2\\text{CO}_2 + 4\\text{H}_2\\text{O}$","correct":false,"explanation":"Although carbon and hydrogen balance, the products contain eight oxygen atoms and the reactants contain six. Two methane molecules require four oxygen molecules, not three."},{"text":"$$\\text{CH}_4 + 2\\text{O}_2 \\rightarrow 2\\text{CO}_2 + \\text{H}_2\\text{O}$","correct":false,"explanation":"The oxygen atoms balance, but carbon and hydrogen do not: the products contain two carbon atoms and only two hydrogen atoms. The correct products are CO₂ and 2H₂O."}]},{"id":"501bee93-83df-40b2-9067-f509aedf82f2","cardType":"cloze","points":null,"front":"To find the true atom count, multiply every subscript by the [ ] in front of the formula.","back":"To find the true atom count, multiply every subscript by the multiplier in front of the formula.","mcqOptions":[{"text":"multiplier","correct":true,"explanation":"A multiplier is the large number placed before a formula. It applies to every atom in that formula, whereas a subscript applies only to the element or group immediately before it."},{"text":"subscript","correct":false,"explanation":"A subscript belongs within a formula and usually applies only to the preceding element or group. The number in front is the multiplier, which scales the entire formula."},{"text":"coefficient","correct":false,"explanation":"A coefficient is commonly used for the number in front of a chemical formula, but this card specifically calls that number the multiplier. The multiplier scales every atom in the formula."},{"text":"chemical symbol","correct":false,"explanation":"A chemical symbol identifies an element, such as H or O, rather than describing the number placed before a formula. That number is the multiplier used to find the true atom count."}]},{"id":"4b1388e5-5d8a-4630-ae99-8f87c587cfb1","cardType":"basic","points":1,"front":"What does the state symbol $(aq)$ show?","back":"The substance is dissolved in water.","mcqOptions":[{"text":"The substance is dissolved in water.","correct":true,"explanation":"The state symbol (aq) means aqueous, showing that the substance is dissolved in water. It does not merely indicate that the substance is a liquid."},{"text":"The substance is a pure liquid.","correct":false,"explanation":"A pure liquid is represented by (l), so confusing these symbols treats aqueous solution as a physical state. The symbol (aq) specifically means dissolved in water."},{"text":"The substance is dissolved in alcohol.","correct":false,"explanation":"The aqueous symbol refers specifically to water, not alcohol or another solvent. A substance dissolved in water is shown as (aq), regardless of whether the solute was originally solid or gaseous."},{"text":"The substance is a solid dissolved in water.","correct":false,"explanation":"The solute may originally be a solid, liquid, or gas, so (aq) does not specify its original state. It only shows that the substance is currently dissolved in water."}]},{"id":"f91f1a91-2f3b-42b4-abdd-7f9901adb4f9","cardType":"basic","points":3,"front":"What do the state symbols $(s)$, $(l)$ and $(g)$ represent?","back":"

$(s)$ means solid.
$(l)$ means liquid.
$(g)$ means gas.

","mcqOptions":[{"text":"

$(s)$ means solid.
$(l)$ means liquid.
$(g)$ means gas.

","correct":true,"explanation":"The symbols identify physical states in a chemical equation: (s) is solid, (l) is liquid, and (g) is gas. They describe the substances under the reaction conditions."},{"text":"

$(s)$ means solution.
$(l)$ means liquid.
$(g)$ means gas.

","correct":false,"explanation":"The first symbol is often confused with solution because of the letter s, but (s) means solid. A solution in water is indicated by (aq), while (l) and (g) retain their usual meanings."},{"text":"

$(s)$ means solid.
$(l)$ means lattice.
$(g)$ means aqueous.

","correct":false,"explanation":"The symbols describe states, not structural terms or solvents. (l) means liquid and (g) means gas; aqueous solution is written (aq), so only the solid identification is correct here."},{"text":"

$(s)$ means solvent.
$(l)$ means liquid.
$(g)$ means gas.

","correct":false,"explanation":"The letter s does not mean solvent in a state symbol. It means solid; solvent describes the substance doing the dissolving, while (l) and (g) indicate liquid and gas."}]}]}],"examCountdown":{"examDate":"2027-05-17","paperLabel":"Paper 1"},"heading":"3.1.1 Conservation of mass and balanced chemical equations","title":"3.1.1 Conservation of mass and balanced chemical equations Flashcards","topbar":{"backHref":"/gcse/chemistry/aqa/flashcards"},"topicSidebar":"$L37"}]}],"topicId":"520bc0b2-19a0-5a32-acc6-8675f179bf49","walled":"$L38"}],"$L39","$L3a"]