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3.1 Chemical measurements, conservation of mass and the quantitative interpretation of chemical equations

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Question 10

Relative atomic masses (ArA_rAr​): N=14\text{N} = 14N=14 O=16\text{O} = 16O=16 Fe=56\text{Fe} = 56Fe=56

A student is checking the relative formula mass (MrM_rMr​) of iron(III) nitrate, Fe(NO3)3\text{Fe(NO}_3\text{)}_3Fe(NO3​)3​.

What is the correct calculation?

[1]
A

56+[14+(3×16)]=11856 + [14 + (3 \times 16)] = 11856+[14+(3×16)]=118

B

56+3×[14+(3×16)]=24256 + 3 \times [14 + (3 \times 16)] = 24256+3×[14+(3×16)]=242

C

56+(3×14)+(3×16)=14656 + (3 \times 14) + (3 \times 16) = 14656+(3×14)+(3×16)=146

D

(3×56)+[14+(3×16)]=230(3 \times 56) + [14 + (3 \times 16)] = 230(3×56)+[14+(3×16)]=230

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3.1 Chemical measurements, conservation of mass and the quantitative interpretation of chemical equations Questions

  1. GCSE
  2. /Chemistry
  3. /3.1 Chemical measurements, conservation of mass and the quantitative interpretation of chemical equations

95 exam-style questions on AQA GCSE Chemistry 3.1 Chemical measurements, conservation of mass and the quantitative interpretation of chemical equations, covering 3.1.1 Conservation of mass and balanced chemical equations, 3.1.2 Relative formula mass, 3.1.3 Mass changes when a reactant or product is a gas, and 3.1.4 Chemical measurements. Each one has a worked solution and a mark scheme showing where the marks go.

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