During the thermal cracking of one molecule of dodecane (C12H26\text{C}_{12}\text{H}_{26}C12H26), one molecule of butane (C4H10\text{C}_4\text{H}_{10}C4H10) and two molecules of a hydrocarbon Y Y\,Y are produced.
Which option correctly identifies the molecular formula of Y Y\,Y and its homologous series?
Molecular formula: C4H8\text{C}_4\text{H}_8C4H8; Homologous series: Alkene
Molecular formula: C4H10\text{C}_4\text{H}_{10}C4H10; Homologous series: Alkane
Molecular formula: C8H16\text{C}_8\text{H}_{16}C8H16; Homologous series: Alkene
Molecular formula: C4H8\text{C}_4\text{H}_8C4H8; Homologous series: Alkane
12 exam-style questions on AQA GCSE Chemistry 7.1 Carbon compounds as fuels and feedstock, covering 7.1.1 Crude oil, hydrocarbons and alkanes, 7.1.2 Fractional distillation and petrochemicals, 7.1.3 Properties of hydrocarbons, and 7.1.4 Cracking and alkenes. Each one has a worked solution and a mark scheme showing where the marks go.