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The challenges of size

What you'll learn

  • Why larger multicellular organisms need exchange surfaces and transport systems.
  • How to calculate and use surface area : volume ratio.
  • How the heart, blood vessels, blood, xylem and phloem are adapted for transport.
  • How a potometer can investigate factors affecting water uptake in plants.

Why size creates a challenge

All cells need substances to move in and out. For example, cells need oxygen and glucose for respiration, and they must remove waste products such as carbon dioxide and urea.

Definition

Diffusion

Diffusion is the net movement of particles from an area of higher concentration to an area of lower concentration.

In very small organisms, diffusion across the cell surface can be enough because every part of the organism is close to the outside. As organisms get larger, many cells are buried deep inside the body, so diffusion alone is too slow.

Surface area : volume ratio

Definition

Surface area : volume ratio

Surface area : volume ratio compares how much outside surface an organism has with how much internal volume it has. It is often written as surface area : volume.

Surface area controls how much material can cross the outside at once. Volume is linked to how many cells need supplying. As an organism gets bigger, its volume increases faster than its surface area, so its surface area : volume ratio decreases.

Diagram comparing small and large cubes to show that volume increases faster than surface area, lowering surface area to volume ratio

Key Idea

The size problem

Large multicellular organisms need specialised exchange surfaces and transport systems because they have a low surface area : volume ratio and longer diffusion distances.

Example

Calculating surface area : volume ratio

A cube-shaped organism has sides of 2 cm. Work out its surface area : volume ratio.

  1. Find the surface area. A cube has 6 faces, each with area side ×\times× side, so:
6×22=24 cm2 6 \times 2^2 = 24\text{ cm}^2 6×22=24 cm2
  1. Find the volume. For a cube:
23=8 cm3 2^3 = 8\text{ cm}^3 23=8 cm3
  1. Compare surface area with volume:
24:8=3:1 24:8 = 3:1 24:8=3:1

So the surface area : volume ratio is 3 : 1.

Tip

Ratio sanity check

If the organism gets bigger, expect the surface area : volume ratio to get smaller, not larger.

Exchange surfaces and transport systems

An exchange surface is a specialised surface where substances move between an organism and its environment. Good exchange surfaces often have:

  • a large surface area;
  • a thin barrier, giving a short diffusion distance;
  • a good blood supply or transport link;
  • movement of air or water to maintain a steep concentration gradient.

Examples include the alveoli in the lungs, the small intestine for digested food absorption, and root hair cells in plants.

A transport system moves substances around an organism. In animals, this is mainly the circulatory system. In plants, it is mainly the xylem and phloem.

Substances transported in organisms include:

  • oxygen to cells for aerobic respiration;
  • carbon dioxide away from respiring cells, or into leaves for photosynthesis;
  • water for chemical reactions, support and photosynthesis;
  • dissolved food molecules such as glucose and amino acids;
  • mineral ions such as nitrates and magnesium ions in plants;
  • urea, a waste product made in the liver and carried to the kidneys.

The human circulatory system

The human circulatory system is a double circulatory system. This means blood passes through the heart twice for each complete circuit of the body.

  • The pulmonary circulation carries blood between the heart and lungs.
  • The systemic circulation carries blood between the heart and the rest of the body.

This is useful because blood can be pumped to the lungs at lower pressure, protecting the delicate exchange surfaces, then returned to the heart and pumped to the body at higher pressure.

Labelled schematic of the human double circulatory system showing blood flow between body, heart and lungs

Heart structure

The heart is made of cardiac muscle, a muscle tissue adapted to contract rhythmically without getting tired quickly.

The four chambers are:

  • right atrium — receives deoxygenated blood from the vena cava;
  • right ventricle — pumps deoxygenated blood to the lungs through the pulmonary artery;
  • left atrium — receives oxygenated blood from the lungs through the pulmonary vein;
  • left ventricle — pumps oxygenated blood to the body through the aorta.

The septum separates the two sides of the heart, preventing oxygenated and deoxygenated blood from mixing. The left ventricle has a thicker muscular wall because it pumps blood all around the body.

Valves

Valves prevent blood flowing backwards. The main heart valves are:

  • tricuspid valve — between the right atrium and right ventricle;
  • bicuspid valve or mitral valve — between the left atrium and left ventricle;
  • semilunar valves — at the exits of the ventricles into the pulmonary artery and aorta.

Blood vessels are adapted to their functions

Blood vesselMain jobKey adaptations
ArteriesCarry blood away from the heartThick muscular and elastic walls to withstand high pressure; relatively narrow lumen
VeinsCarry blood back to the heartWider lumen; thinner walls; valves to prevent backflow
CapillariesExchange substances with cellsWalls one cell thick; very narrow lumen; huge network close to cells
Common Mistake

Why blood is slow in capillaries

Blood is not slow in capillaries simply because each capillary is narrow. It slows because there are very many capillaries, giving a very large total cross-sectional area. Slow flow gives more time for diffusion.

Blood as a transport tissue

Blood contains plasma, red blood cells, white blood cells and platelets. For this topic, focus on plasma and red blood cells.

Plasma is the liquid part of blood. It carries dissolved substances, including carbon dioxide, urea, glucose, amino acids, hormones and mineral ions. It also transports heat around the body.

Red blood cells are adapted to carry oxygen because they:

  • contain haemoglobin, a protein that binds to oxygen;
  • have a biconcave disc shape, giving a large surface area;
  • have no nucleus, leaving more space for haemoglobin;
  • are flexible, so they can squeeze through capillaries.

Plant transport: roots, xylem and phloem

Plants also face the challenge of size. Roots take up water and mineral ions, while leaves make sugars by photosynthesis. These substances must be moved around the plant.

Schematic of plant transport showing root hair cells, xylem, phloem, stomata and a simple potometer

Root hair cells

Root hair cells are adapted to absorb water and mineral ions from the soil.

They have a long hair-like extension, which gives a large surface area. Water enters by osmosis, the movement of water from a more dilute solution to a more concentrated solution through a partially permeable membrane. Mineral ions may be taken up by active transport, which uses energy from respiration to move substances against their concentration gradient.

Xylem

Xylem carries water and mineral ions from roots to leaves. Xylem vessels are adapted because they are:

  • long hollow tubes, so water can flow through them;
  • made from dead cells with no end walls;
  • strengthened with lignin, which helps stop them collapsing.

Water movement through xylem is linked to transpiration from the leaves.

Phloem

Phloem carries dissolved sugars, mainly sucrose, from where they are made to where they are used or stored. This movement is called translocation.

Phloem is made of living cells. Sieve tube cells allow sap to flow, and companion cells provide energy for transport.

Definition

Transpiration and translocation

Transpiration is the loss of water vapour from plant leaves, mainly through stomata. Translocation is the movement of dissolved sugars through phloem from sources to sinks.

A source is a part of the plant that releases sugar, such as a leaf doing photosynthesis. A sink is a part that uses or stores sugar, such as roots, fruits or growing shoots.

Stomata

Stomata are tiny pores, usually on the underside of leaves. They allow carbon dioxide to enter for photosynthesis, but water vapour can also diffuse out. Each stoma is controlled by two guard cells, which can open or close the pore.

Factors affecting water uptake

A plant’s rate of water uptake usually increases when transpiration increases.

Important factors include:

  • Light intensity — more light usually opens stomata for photosynthesis, increasing transpiration.
  • Air movement — moving air removes moist air from around the leaf, keeping a steep diffusion gradient.
  • Temperature — higher temperature gives water molecules more kinetic energy, increasing evaporation and diffusion.
Common Mistake

Very high temperatures

At very high temperatures, a plant may close its stomata to reduce water loss. In that case, transpiration may decrease instead of continuing to rise.

Using a potometer

A potometer estimates the rate of water uptake by a leafy shoot. As the shoot takes up water, an air bubble moves along a capillary tube. You measure the distance moved in a set time.

A potometer can test factors such as light intensity, wind speed or temperature. Keep other variables controlled, such as leaf surface area, time measured and starting bubble position.

Common Mistake

What a potometer measures

A potometer measures water uptake, not transpiration directly. It is used as an estimate because most water taken up by a plant is lost by transpiration.

Example

Calculating rate of water uptake

In a potometer, an air bubble moves 48 mm in 6 minutes. Calculate the rate of water uptake in mm per minute.

  1. Choose the rate equation:
rate=distance movedtime taken \text{rate} = \frac{\text{distance moved}}{\text{time taken}} rate=time takendistance moved​
  1. Substitute the values:
rate=486 \text{rate} = \frac{48}{6} rate=648​
  1. Calculate the rate:
rate=8 mm per minute \text{rate} = 8\text{ mm per minute} rate=8 mm per minute

You may also be asked for percentage change in mass, especially if a plant shoot or leaf is weighed before and after.

percentage change=change in massoriginal mass×100\text{percentage change} = \frac{\text{change in mass}}{\text{original mass}} \times 100percentage change=original masschange in mass​×100
Exam technique

In the exam

  1. Link size to surface area : volume ratio and diffusion distance when explaining why transport systems are needed.
  2. For heart questions, state the route clearly: body → vena cava → right side → lungs → left side → aorta → body.
  3. In potometer questions, say which factor is changed, which variables are controlled, and calculate rate using change divided by time.
Self review

Check yourself

  • Why does a large organism need a transport system even if diffusion still happens?
  • How are arteries, veins and capillaries each adapted to their functions?
  • How would increasing air movement affect water uptake in a potometer?

Recap questions

Test yourself with 5 quick questions on this guide. Answer them all correctly to complete it.

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