An electron micrograph of a mitochondrion has an image length of 7.2 cm7.2\text{ cm}7.2 cm. The actual length of the mitochondrion is 1.8×10−6 m1.8 \times 10^{-6}\text{ m}1.8×10−6 m.
Calculate the magnification used to view the mitochondrion. Give your answer in the form a×10na \times 10^na×10n, where 1≤a<101 \le a < 101≤a<10 and nnn is an integer.
Use the formula:
magnification=size of imagesize of real object \text{magnification} = \frac{\text{size of image}}{\text{size of real object}} magnification=size of real objectsize of image163 exam-style questions on AQA GCSE Biology 1.1 Cell structure, covering 1.1.1 Eukaryotes and prokaryotes, 1.1.2 Animal and plant cells, 1.1.3 Cell specialisation, 1.1.4 Cell differentiation, 1.1.5 Microscopy, and 1.1.6 Culturing microorganisms. Each one has a worked solution and a mark scheme showing where the marks go.