2.2 Animal tissues, organs and organ systems

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Question 38

During a laboratory test, human lipase is breaking down lipid in a water bath at 37 °C. A fault causes the reaction mixture to reach 60 °C, and the reaction becomes much slower. Which statement explains this change?

[1]

At 60 °C, the lipase is denatured, so its active site changes shape and lipid no longer fits

At 60 °C, the lipase is used up faster, so less enzyme remains to break down lipid

At 60 °C, the lipase molecules are killed by the heat, so they can no longer digest lipid

At 60 °C, products remain in the lipase active sites, so new lipid molecules cannot bind

At 60 °C, the lipase is denatured, so its active site changes shape and lipid no longer fits

At 60 °C, the lipase is used up faster, so less enzyme remains to break down lipid

At 60 °C, the lipase molecules are killed by the heat, so they can no longer digest lipid

At 60 °C, products remain in the lipase active sites, so new lipid molecules cannot bind

2.2 Animal tissues, organs and organ systems

Question 38

Markscheme

2.2 Animal tissues, organs and organ systems

Question 38

Markscheme

2.2 Animal tissues, organs and organ systems

Question 38

2.2 Animal tissues, organs and organ systems Questions

2.2 Animal tissues, organs and organ systems

Question 38

2.2 Animal tissues, organs and organ systems Questions