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interaction. They can still experience the weak, electromagnetic and gravitational interactions where applicable."},{"text":"The weak interaction.","correct":false,"explanation":"Leptons participate in the weak interaction, as shown by processes such as beta decay. They notably do not experience the strong nuclear interaction because they have no colour charge."},{"text":"The electromagnetic interaction.","correct":false,"explanation":"Charged leptons, including electrons and muons, experience the electromagnetic interaction. Leptons instead lack the colour charge required to experience the strong nuclear interaction."},{"text":"The gravitational interaction.","correct":false,"explanation":"Leptons possess energy and therefore experience gravity, although it is extremely weak at particle scales. The interaction they notably do not experience is the strong nuclear interaction."}]},{"id":"190c37d2-d8c9-4e44-b28d-a807acd77cb0","cardType":"cloze","points":null,"front":"A [ ] consists of three quarks, while a meson consists of a quark-antiquark pair.","back":"A baryon consists of three quarks, while a meson consists of a quark-antiquark pair.","mcqOptions":[{"text":"baryon","correct":true,"explanation":"A baryon is a hadron made from three quarks. Protons and neutrons are familiar examples, with respective quark compositions $uud$ and $udd$."},{"text":"meson","correct":false,"explanation":"A meson contains a quark-antiquark pair rather than three quarks. The three-quark particle described by the sentence is a baryon."},{"text":"hadron","correct":false,"explanation":"Hadron is the broader category containing both baryons and mesons, so not every hadron has three quarks. The specific three-quark particle is a baryon."},{"text":"lepton","correct":false,"explanation":"Leptons are fundamental particles and are not composed of quarks. A composite particle made from three quarks is called a baryon."}]},{"id":"b96a82a5-d4f4-46d2-b2db-a409d54952a9","cardType":"cloze","points":null,"front":"A baryon consists of three quarks, while a [ ] consists of a quark-antiquark pair.","back":"A baryon consists of three quarks, while a meson consists of a quark-antiquark pair.","mcqOptions":[{"text":"meson","correct":true,"explanation":"A meson is a hadron formed from one quark and one antiquark. This differs from a baryon, which consists of three quarks."},{"text":"baryon","correct":false,"explanation":"A baryon consists of three quarks, not a quark-antiquark pair. The hadron with one quark and one antiquark is a meson."},{"text":"lepton","correct":false,"explanation":"A lepton is a fundamental particle with no quark constituents. A particle composed of a quark-antiquark pair is instead called a meson."},{"text":"hadron","correct":false,"explanation":"Hadron is a general category that includes both baryons and mesons. The specific hadron containing a quark-antiquark pair is a meson."}]},{"id":"f1e5d482-6d7a-4458-b498-32f88a4d2d27","cardType":"basic","points":2,"front":"State the quark content of a proton and a neutron.","back":"

Proton: $uud$
Neutron: $udd$

","mcqOptions":[{"text":"

Proton: $uud$
Neutron: $udd$

","correct":true,"explanation":"Two up quarks and one down quark give the proton charge $+1$, while one up quark and two down quarks give the neutron charge $0$."},{"text":"

Proton: $udd$
Neutron: $uud$

","correct":false,"explanation":"This swaps the quark compositions: $udd$ has zero charge and describes a neutron. The proton is $uud$, while the neutron is $udd$."},{"text":"

Proton: $uuu$
Neutron: $ddd$

","correct":false,"explanation":"Using three identical quarks gives charges $+2$ and $-1$, so these cannot be the proton and neutron. Their correct compositions are $uud$ and $udd$ respectively."},{"text":"

Proton: $uu\\bar{d}$
Neutron: $dd\\bar{u}$

","correct":false,"explanation":"Introducing an antiquark incorrectly treats the nucleons as meson-like combinations and gives the wrong charges. A proton is $uud$, and a neutron is $udd$."}]},{"id":"1eeb2f8d-145a-4f47-b6c6-4fa3974a71ee","cardType":"basic","points":2,"front":"Why does a meson have a baryon number ($B$) of zero?","back":"It contains one quark ($B = +\\frac{1}{3}$) and one antiquark ($B = -\\frac{1}{3}$).","mcqOptions":[{"text":"It contains one quark ($B = +\\frac{1}{3}$) and one antiquark ($B = -\\frac{1}{3}$).","correct":true,"explanation":"The quark and antiquark baryon numbers are equal in magnitude and opposite in sign. Their sum is therefore $+\\frac{1}{3}-\\frac{1}{3}=0$."},{"text":"It contains two quarks ($B = +\\frac{1}{3}$ each) and one antiquark ($B = -\\frac{1}{3}$).","correct":false,"explanation":"This is neither a meson’s composition nor a combination with zero baryon number; the total would be $+\\frac{1}{3}$. A meson contains one quark and one antiquark."},{"text":"It contains one quark ($B = +\\frac{1}{3}$) and one antiquark ($B = +\\frac{1}{3}$).","correct":false,"explanation":"An antiquark has baryon number $-\\frac{1}{3}$, not $+\\frac{1}{3}$. Its value cancels the quark’s $+\\frac{1}{3}$, giving the meson $B=0$."},{"text":"It contains one quark ($B = -\\frac{1}{3}$) and one antiquark ($B = -\\frac{1}{3}$).","correct":false,"explanation":"This incorrectly assigns negative baryon number to the quark. A quark has $B=+\\frac{1}{3}$ and an antiquark has $B=-\\frac{1}{3}$, so the total is zero."}]},{"id":"5e61b71b-0e56-49f8-8412-f0efddd0fd6f","cardType":"cloze","points":null,"front":"The strange quark has a strangeness ($S$) of $\\text{[...]}$.","back":"The strange quark has a strangeness ($S$) of $\\boxed{-1}$.","mcqOptions":[{"text":"$$-1$","correct":true,"explanation":"By convention, a strange quark has strangeness $S=-1$. Its antiparticle, the antistrange quark, has the opposite value, $S=+1$."},{"text":"$$+1$","correct":false,"explanation":"Positive strangeness belongs to an antistrange quark, a common particle-antiparticle sign reversal. The strange quark itself has strangeness $S=-1$."},{"text":"$$0$","correct":false,"explanation":"Zero strangeness applies to particles containing no net strange-quark contribution. A strange quark carries strangeness $S=-1$ by definition."},{"text":"$$-\\frac{1}{3}$","correct":false,"explanation":"This confuses strangeness with a quark’s baryon number, which is $+\\frac{1}{3}$. The strange quark’s strangeness quantum number is $S=-1$."}]},{"id":"f38cd42c-3fc6-42dd-8199-3d121340f571","cardType":"basic","points":2,"front":"Identify the exchange particles for the electromagnetic and strong interactions.","back":"

Electromagnetic: photons
Strong: gluons

","mcqOptions":[{"text":"

Electromagnetic: photons
Strong: gluons

","correct":true,"explanation":"Photons mediate the electromagnetic interaction between charged particles, while gluons carry the strong interaction between colour-charged quarks and also interact with one another."},{"text":"

Electromagnetic: photons
Strong: pions

","correct":false,"explanation":"Pions can model the residual strong force between nucleons, but they are not the fundamental strong-interaction exchange particles. Photons mediate electromagnetism, while gluons mediate the strong interaction."},{"text":"

Electromagnetic: W bosons
Strong: gluons

","correct":false,"explanation":"W bosons mediate charged-current weak interactions, not electromagnetic interactions. The electromagnetic exchange particle is the photon, while the strong interaction is mediated by gluons."},{"text":"

Electromagnetic: gluons
Strong: photons

","correct":false,"explanation":"This reverses the two exchange particles. Photons mediate interactions between electrically charged particles, whereas gluons mediate interactions between particles carrying colour charge."}]},{"id":"1fad1900-c9b0-4256-9471-c32cb3b3fbc1","cardType":"basic","points":1,"front":"Which interaction is responsible for quark flavour change?","back":"The weak interaction.","mcqOptions":[{"text":"The weak interaction.","correct":true,"explanation":"Only the weak interaction can change one quark flavour into another, typically through the emission or absorption of a $W^+$ or $W^-$ boson."},{"text":"The strong interaction.","correct":false,"explanation":"The strong interaction acts on colour charge but conserves quark flavour. Flavour changes, such as a down quark becoming an up quark, occur through the weak interaction."},{"text":"The electromagnetic interaction.","correct":false,"explanation":"The electromagnetic interaction acts on electric charge and does not change quark flavour. Such changes are characteristic of the weak interaction and involve W bosons."},{"text":"The gravitational interaction.","correct":false,"explanation":"Gravity acts universally on energy and mass but does not transform one quark flavour into another. Quark flavour change is caused by the weak interaction."}]},{"id":"38246f41-ef36-4413-bf55-87403aca9ef5","cardType":"basic","points":2,"front":"Why is the weak interaction very short range?","back":"The exchange particles ($W$ and $Z$ bosons) have large mass.","mcqOptions":[{"text":"The exchange particles ($W$ and $Z$ bosons) have large mass.","correct":true,"explanation":"The large masses of the $W$ and $Z$ bosons limit their range through the uncertainty principle, so the weak interaction acts only over very short distances."},{"text":"The exchange particles ($W$ and $Z$ bosons) have small mass.","correct":false,"explanation":"Small-mass exchange particles would allow a longer-range interaction. The weak interaction is short range because its $W$ and $Z$ bosons have large mass."},{"text":"The exchange particles (photons) have large mass.","correct":false,"explanation":"Photons mediate the electromagnetic interaction and have zero rest mass. The weak interaction is short range because its exchange particles, the $W$ and $Z$ bosons, are very massive."},{"text":"The exchange particles ($W$ and $Z$ bosons) have zero mass.","correct":false,"explanation":"Zero-mass exchange particles would produce a long-range interaction, as photons do. The weak interaction has a short range because the $W$ and $Z$ bosons have large mass."}]},{"id":"19e6c920-291d-46b2-984d-64c115083ac2","cardType":"basic","points":2,"front":"State the special rule for strangeness conservation.","back":"Conserved in strong and electromagnetic interactions; not necessarily conserved in weak interactions.","mcqOptions":[{"text":"Conserved in strong and electromagnetic interactions; not necessarily conserved in weak interactions.","correct":true,"explanation":"Strangeness is conserved in strong and electromagnetic interactions, but weak interactions can change strangeness, so it is not necessarily conserved there."},{"text":"Conserved in strong and weak interactions; not necessarily conserved in electromagnetic interactions.","correct":false,"explanation":"The weak interaction can change strangeness, whereas electromagnetic interactions conserve it. Therefore strangeness is conserved in strong and electromagnetic interactions, but not necessarily in weak interactions."},{"text":"Conserved in weak and electromagnetic interactions; not necessarily conserved in strong interactions.","correct":false,"explanation":"Strong interactions conserve strangeness, while weak interactions may change it. The correct rule is conservation in strong and electromagnetic interactions, but not necessarily in weak interactions."},{"text":"Not necessarily conserved in strong, electromagnetic or weak interactions.","correct":false,"explanation":"Strong and electromagnetic interactions conserve strangeness; only weak interactions can violate strangeness conservation. The special rule therefore excludes strong and electromagnetic interactions from the exception."}]},{"id":"eee4ef3c-b1d1-4e71-8db2-f38fcf30f48f","cardType":"basic","points":1,"front":"What is the quark-level change during beta-minus ($̢^-$) decay?","back":"A down quark changes into an up quark ($d \\to u$).","mcqOptions":[{"text":"A down quark changes into an up quark ($d \\to u$).","correct":true,"explanation":"In beta-minus decay, a down quark changes into an up quark by emitting a $W^-$ boson, which subsequently produces an electron and an electron antineutrino."},{"text":"A up quark changes into an down quark ($u \\to d$).","correct":false,"explanation":"This is the quark-level change in beta-plus decay, not beta-minus decay. In beta-minus decay, a down quark changes into an up quark, $d \\to u$."},{"text":"A strange quark changes into an up quark ($s \\to u$).","correct":false,"explanation":"Although weak interactions can change a strange quark into another flavour, beta-minus decay specifically involves $d \\to u$. Confusing strangeness-changing decay with beta decay causes this error."},{"text":"An up quark changes into a strange quark ($u \\to s$).","correct":false,"explanation":"This is not the quark transition responsible for beta-minus decay. The required change is a down quark becoming an up quark, $d \\to u$, through the weak interaction."}]},{"id":"ca46b2ca-af87-4603-992e-4bac65e67dae","cardType":"basic","points":1,"front":"What is the quark-level change during beta-plus ($̢^+$) decay?","back":"An up quark changes into a down quark ($u \\to d$).","mcqOptions":[{"text":"An up quark changes into a down quark ($u \\to d$).","correct":true,"explanation":"In beta-plus decay, an up quark changes into a down quark by emitting a $W^+$ boson, which produces a positron and an electron neutrino."},{"text":"A down quark changes into an up quark ($d \\to u$).","correct":false,"explanation":"This is the quark-level change in beta-minus decay. Beta-plus decay involves the reverse flavour change, with an up quark becoming a down quark, $u \\to d$."},{"text":"A strange quark changes into an up quark ($s \\to u$).","correct":false,"explanation":"The transition $s \\to u$ is a possible weak flavour change, but it does not describe beta-plus decay. Beta-plus decay specifically requires $u \\to d$."},{"text":"A down quark changes into a strange quark ($d \\to s$).","correct":false,"explanation":"The transition $d \\to s$ changes strangeness and is not the standard beta-plus decay process. In beta-plus decay, an up quark changes into a down quark, $u \\to d$."}]},{"id":"424ee150-0941-4244-9142-3e45dba65c02","cardType":"cloze","points":null,"front":"In $\\beta^-$ decay, the emission of an electron ($L_e = +1$) requires the simultaneous emission of an [ ] ($L_e = -1$) to conserve lepton number.","back":"In $\\beta^-$ decay, the emission of an electron ($L_e = +1$) requires the simultaneous emission of an electron antineutrino ($L_e = -1$) to conserve lepton number.","mcqOptions":[{"text":"electron antineutrino","correct":true,"explanation":"An electron has $L_e=+1$, so beta-minus decay must also emit an electron antineutrino with $L_e=-1$. Their lepton numbers cancel, conserving total electron lepton number."},{"text":"electron neutrino","correct":false,"explanation":"An electron neutrino has $L_e=+1$, which would add to the emitted electron rather than cancel its lepton number. The required particle is an electron antineutrino with $L_e=-1$."},{"text":"muon antineutrino","correct":false,"explanation":"A muon antineutrino carries muon lepton number, not electron lepton number, so it cannot balance the electron's $L_e=+1$. Beta-minus decay emits an electron antineutrino."},{"text":"electron positron","correct":false,"explanation":"A positron has electron lepton number $L_e=-1$, but it is not the neutral particle emitted in beta-minus decay and would not give the required decay products. The particle is an electron antineutrino."}]},{"id":"71e187ea-061b-4e16-bf77-41c89c79ed3c","cardType":"basic","points":2,"front":"Compare a particle and its antiparticle in terms of mass and charge.","back":"

Same rest mass
Opposite charge

","mcqOptions":[{"text":"

Same rest mass
Opposite charge

","correct":true,"explanation":"A particle and its antiparticle have equal rest masses, but every conserved charge is reversed. Thus an antiparticle has the same mass and opposite electric charge."},{"text":"

Opposite rest mass
Opposite charge

","correct":false,"explanation":"Rest mass is a positive scalar quantity and is unchanged between a particle and its antiparticle. The charge reverses, so the correct comparison is same rest mass and opposite charge."},{"text":"

Same rest mass
Same charge

","correct":false,"explanation":"Antiparticles have the same rest mass but opposite electric charge. Keeping the charge unchanged confuses an antiparticle with another particle of the same mass."},{"text":"

Opposite rest mass
Same charge

","correct":false,"explanation":"Neither property is described correctly here: rest mass remains the same and electric charge changes sign. Antiparticles are distinguished by reversed charge, not negative or opposite mass."}]},{"id":"07284cf7-c8a9-4b26-b26d-d2bbaf2d3f3e","cardType":"cloze","points":null,"front":"The electron lepton number ($L_e$) for a positron is $\\text{[...]}$.","back":"The electron lepton number ($L_e$) for a positron is $\\boxed{-1}$.","mcqOptions":[{"text":"$$-1$","correct":true,"explanation":"A positron is the antiparticle of the electron, so its electron lepton number is the opposite of the electron's value: $L_e=-1$."},{"text":"$$+1$","correct":false,"explanation":"The value $+1$ belongs to an electron and an electron neutrino. A positron is the electron antiparticle, so it has the opposite electron lepton number, $L_e=-1$."},{"text":"$$0$","correct":false,"explanation":"Electron lepton number is zero for particles such as photons, but not for a positron. As an electron antiparticle, the positron carries $L_e=-1$."},{"text":"$$+2$","correct":false,"explanation":"Lepton number is assigned as $+1$ or $-1$ for electron-family leptons and antileptons, not $+2$. A positron specifically has $L_e=-1$."}]},{"id":"4589537c-04f9-42f2-b9d3-63f6296fd87c","cardType":"basic","points":2,"front":"Calculate the charge ($Q$) and strangeness ($S$) of a $u\\bar{s}$ meson.","back":"

Charge: $+\\frac{2}{3}e + \\frac{1}{3}e = +1e$
Strangeness: +1

","mcqOptions":[{"text":"

Charge: $+\\frac{2}{3}e + \\frac{1}{3}e = +1e$
Strangeness: +1

","correct":true,"explanation":"The $u$ quark contributes $+\\frac{2}{3}e$ and the anti-strange quark contributes $+\\frac{1}{3}e$, giving $+1e$. The anti-strange quark has strangeness $+1$."},{"text":"

Charge: $+\\frac{2}{3}e - \\frac{1}{3}e = +\\frac{1}{3}e$
Strangeness: -1

","correct":false,"explanation":"This treats the anti-strange quark as if it were a strange quark, reversing both its charge contribution and strangeness. An anti-strange quark contributes $+\\frac{1}{3}e$ and $S=+1$."},{"text":"

Charge: $-\\frac{2}{3}e + \\frac{1}{3}e = -\\frac{1}{3}e$
Strangeness: +1

","correct":false,"explanation":"The $u$ quark has charge $+\\frac{2}{3}e$, not $-\\frac{2}{3}e$; that negative value belongs to an anti-up quark. The correct total charge is $+1e$ with strangeness $+1$."},{"text":"

Charge: $+\\frac{2}{3}e + \\frac{1}{3}e = +1e$
Strangeness: -1

","correct":false,"explanation":"The charge calculation is correct, but the strangeness sign is reversed. A strange quark has $S=-1$, whereas an anti-strange quark has $S=+1$, so the meson has strangeness $+1$."}]},{"id":"e563c3b7-3b28-4eae-b0ef-e377791a9d24","cardType":"basic","points":2,"front":"Why can a free proton not undergo $\\beta^+$ decay?","back":"Energy is not conserved (the mass of a neutron is greater than a proton).","mcqOptions":[{"text":"Energy is not conserved (the mass of a neutron is greater than a proton).","correct":true,"explanation":"In free proton $\\beta^+$ decay, the proton would have to become a heavier neutron while also creating a positron and neutrino. The initial rest energy is insufficient, so energy cannot be conserved."},{"text":"Charge is not conserved (a neutron has no charge).","correct":false,"explanation":"The positron carries charge $+1$, balancing the neutral neutron, so charge is conserved. The decay cannot occur because the heavier products require more energy than a free proton provides."},{"text":"Baryon number is not conserved (a neutron is a different baryon).","correct":false,"explanation":"The proton and neutron both have baryon number $+1$, while the leptons have baryon number zero. The actual obstacle is insufficient energy to create the heavier final state."},{"text":"Lepton number is not conserved (a positron is produced).","correct":false,"explanation":"The positron has lepton number $-1$ and the neutrino has $+1$, giving zero overall. The decay is forbidden because the products have greater total rest energy."}]},{"id":"7b0c4e04-bab8-4d5a-9a2a-71ef0f51090a","cardType":"basic","points":2,"front":"List three quantum numbers that must be conserved in all particle interactions.","back":"

Charge ($Q$)
Baryon number ($B$)
Lepton number ($L$)

","mcqOptions":[{"text":"

Charge ($Q$)
Baryon number ($B$)
Lepton number ($L$)

","correct":true,"explanation":"Charge, baryon number and lepton number are conserved in every particle interaction considered in the A-level model, although particle species and other quantum numbers may change."},{"text":"

Charge ($Q$)
Strangeness ($S$)
Lepton number ($L$)

","correct":false,"explanation":"Strangeness can change in weak interactions, so it is not universally conserved. The three required quantum numbers are charge, baryon number and lepton number."},{"text":"

Charge ($Q$)
Mass ($m$)
Lepton number ($L$)

","correct":false,"explanation":"Rest mass may be converted into kinetic energy or new particles, so mass is not a conserved quantum number. Charge, baryon number and lepton number must instead be conserved."},{"text":"

Charge ($Q$)
Baryon number ($B$)
Strangeness ($S$)

","correct":false,"explanation":"Strangeness is conserved in strong interactions but may change through the weak interaction. Lepton number must replace strangeness in the universally conserved set."}]},{"id":"078d2660-05ab-4bca-adc7-4c06b57c7fa1","cardType":"basic","points":1,"front":"What process occurs when a particle and its antiparticle meet?","back":"Annihilation (conversion into photons).","mcqOptions":[{"text":"Annihilation (conversion into photons).","correct":true,"explanation":"A particle and its antiparticle have opposite conserved quantum numbers, allowing both to disappear in annihilation and transfer their energy and momentum to photons."},{"text":"Pair production (conversion of photons into particles).","correct":false,"explanation":"Pair production is the reverse process, in which photon energy creates a particle-antiparticle pair. When an existing particle and antiparticle meet, they undergo annihilation into photons."},{"text":"Scattering (deflection without particle destruction).","correct":false,"explanation":"Scattering changes particles’ directions or momenta without necessarily destroying them. A particle meeting its antiparticle instead undergoes annihilation, converting their energy into photons."},{"text":"Ionisation (removal of electrons from atoms).","correct":false,"explanation":"Ionisation removes an electron from an atom and does not describe a particle-antiparticle encounter. Such a pair undergoes annihilation, with its energy converted into photons."}]},{"id":"5cb3f2f7-bd2d-46c6-b022-ea47389d480a","cardType":"cloze","points":null,"front":"In the Standard Model, gluons act between quarks because quarks carry [ ].","back":"In the Standard Model, gluons act between quarks because quarks carry colour charge.","mcqOptions":[{"text":"colour charge","correct":true,"explanation":"Quarks possess colour charge, and gluons mediate the strong interaction by coupling to this charge. Their colour-charge interaction binds quarks together inside hadrons."},{"text":"electric charge","correct":false,"explanation":"Quarks do carry electric charge, but electric interactions are mediated by photons rather than gluons. Gluons couple to the quarks’ colour charge."},{"text":"weak isospin","correct":false,"explanation":"Weak isospin is associated with the weak interaction, whose force carriers are the $W$ and $Z$ bosons. Gluons act on quarks because they carry colour charge."},{"text":"baryon number","correct":false,"explanation":"Baryon number classifies quarks and baryons but is not the charge to which gluons couple. The strong interaction mediated by gluons acts on colour charge."}]},{"id":"2b8e38f6-e082-4b4b-9678-f66fa5eda219","cardType":"basic","points":1,"front":"State the lepton number of a $\\pi^0$ meson.","back":"Zero (mesons are hadrons, not leptons).","mcqOptions":[{"text":"Zero (mesons are hadrons, not leptons).","correct":true,"explanation":"A $\\pi^0$ consists of quark-antiquark combinations, and both quarks and antiquarks have lepton number zero. The meson therefore has total lepton number zero."},{"text":"One (a meson contains one quark).","correct":false,"explanation":"Counting the quark as a lepton-number contribution confuses baryon and lepton classification. Quarks have lepton number zero, so a $\\pi^0$ has lepton number zero."},{"text":"Minus one (a meson contains one antiquark).","correct":false,"explanation":"An antiquark does not have lepton number $-1$; that value belongs to antileptons. Both constituents of a $\\pi^0$ have lepton number zero."},{"text":"Two (a meson contains two constituent particles).","correct":false,"explanation":"Lepton number is not obtained by counting constituent particles. A $\\pi^0$ contains a quark and antiquark, each with lepton number zero, so its total is zero."}]}]}],"examCountdown":{"examDate":"2027-05-12","paperLabel":"Paper 1"},"heading":"Quark-lepton model and particle interactions","title":"Quark-lepton model and particle interactions Flashcards","topbar":{"backHref":"/as-level/physics/edexcel/flashcards"},"topicSidebar":"$L38"}]}],"topicId":"83d17a2a-1cf4-5fc2-9e5d-719212b3d9b6","walled":"$L39"}],"$L3a","$L3b"]