Solve the equation: x2−65x+64=0x^2 - 65x + 64 = 0x2−65x+64=0
Hence, substituting x=y32\displaystyle x=y^{\frac{3}{2}}x=y23, solve the equation: y3−65y32+64=0\displaystyle y^3 - 65y^{\frac{3}{2}} + 64 = 0y3−65y23+64=0
134 exam-style questions on Edexcel AS Level Maths Algebraic Expressions, covering 1.1 Index Laws, 1.2 Expanding Brackets, 1.3 Factorising, 1.4 Negative and Fractional Indices, and 1.5 Surds. Each one has a worked solution and a mark scheme showing where the marks go.