What is a correct SI base unit for the area under a force-displacement graph?
kg m s−2\text{kg m s}^{-2}kg m s−2
kg m2s−2\text{kg m}^2 \text{s}^{-2}kg m2s−2
kg m2s−3\text{kg m}^2 \text{s}^{-3}kg m2s−3
kg m s−1\text{kg m s}^{-1}kg m s−1
