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Basics of electricity

Welcome to the foundation of your A-Level electricity studies! You likely remember many of these concepts from GCSE, but at A-Level, we need to be much more precise with our language and definitions.

What you'll learn:

  • The formal definition of electric current as the rate of flow of charge.
  • How to define potential difference in terms of work done per unit charge.
  • The true definition of electrical resistance (and why it isn't quite the same as Ohm's Law).
  • How to set up basic circuits to measure these quantities.

Electric Current

At its heart, electricity is all about moving charge. In metal wires, these moving charges are electrons, but in liquids (electrolytes) or gases, they could be positive or negative ions.

We measure the "amount" of charge in a unit called the Coulomb (C). However, knowing the total charge sitting in a wire isn't very useful on its own. We usually want to know how fast that charge is moving past a specific point.

Illustration of electrons passing a checkpoint in a wire

This gives us our first formal definition:

Definition

Electric Current

Electric current is defined as the rate of flow of charge.

We can write this mathematically as:

I=ΔQΔt I = \frac{\Delta Q}{\Delta t} I=ΔtΔQ​

Where:

  • III is the current, measured in Amperes (A).
  • ΔQ\Delta QΔQ is the change in charge (or amount of charge flowing), measured in Coulombs (C).
  • Δt\Delta tΔt is the time interval, measured in seconds (s).
Tip

The Delta Symbol

You will see the Greek letter Delta (Δ\DeltaΔ) used constantly in A-Level Physics. It simply means "change in" or "amount of". So ΔQ\Delta QΔQ just means the "amount of charge" that has flowed, rather than the absolute total charge of the universe!

Because of this equation, we can also say that 1 Ampere is exactly equal to 1 Coulomb of charge passing a point every 1 second (1 A=1 C s−11 \text{ A} = 1 \text{ C s}^{-1}1 A=1 C s−1).

Example

Calculating charge from current

A mobile phone charger delivers a steady current of 2.1 A for 45 minutes. Calculate the total charge transferred to the battery.

  1. Extract the data and convert to SI units: The current I=2.1 AI = 2.1 \text{ A}I=2.1 A. The time Δt=45 minutes\Delta t = 45 \text{ minutes}Δt=45 minutes. We must convert this to seconds:
Δt=45×60=2700 s \Delta t = 45 \times 60 = 2700 \text{ s} Δt=45×60=2700 s
  1. Rearrange the formula: We know I=ΔQΔtI = \frac{\Delta Q}{\Delta t}I=ΔtΔQ​, so we multiply both sides by Δt\Delta tΔt to make ΔQ\Delta QΔQ the subject:
ΔQ=I×Δt \Delta Q = I \times \Delta t ΔQ=I×Δt
  1. Substitute and calculate:
ΔQ=2.1×2700=5670 C \Delta Q = 2.1 \times 2700 = 5670 \text{ C} ΔQ=2.1×2700=5670 C

Potential Difference

Current tells us that charge is moving, but why is it moving? And how much energy does it carry? This is where potential difference (often casually called voltage) comes in.

When a battery pushes electrons around a circuit, it transfers electrical energy to them. When those electrons pass through a component (like a bulb or a resistor), they transfer that energy to the component (which turns it into light or heat).

In physics, when energy is transferred, we say work is done.

Definition

Potential Difference

The potential difference between two points in a circuit is the work done per unit charge.

The equation for potential difference is:

V=WQ V = \frac{W}{Q} V=QW​

Where:

  • VVV is the potential difference, measured in Volts (V).
  • WWW is the work done (or energy transferred), measured in Joules (J).
  • QQQ is the charge, measured in Coulombs (C).

This means that 1 Volt is exactly equal to 1 Joule of energy being transferred by 1 Coulomb of charge (1 V=1 J C−11 \text{ V} = 1 \text{ J C}^{-1}1 V=1 J C−1). If you have a 12 V car battery, it gives exactly 12 Joules of energy to every single Coulomb of charge that passes through it.

Analogy

The Delivery Trucks

Imagine the circuit as a circular road.

  • The Charge (QQQ): The fleet of delivery trucks.
  • The Current (III): How many trucks drive past your house every second.
  • Potential Difference (VVV): How many parcels (Joules of energy) each truck is carrying and drops off at your house.
Example

Multi-step energy calculation

A 12.0 V filament lamp is switched on for 2.0 minutes. During this time, a steady current of 1.5 A flows through the lamp. Calculate the total electrical work done by the lamp.

  1. Calculate the total charge that flows: First, convert time to seconds: Δt=2.0×60=120 s\Delta t = 2.0 \times 60 = 120 \text{ s}Δt=2.0×60=120 s. Using ΔQ=I×Δt\Delta Q = I \times \Delta tΔQ=I×Δt:
ΔQ=1.5×120=180 C \Delta Q = 1.5 \times 120 = 180 \text{ C} ΔQ=1.5×120=180 C
  1. Calculate the work done: Rearrange the potential difference equation V=WQV = \frac{W}{Q}V=QW​ to make WWW the subject:
W=V×Q W = V \times Q W=V×Q
  1. Substitute the known values:
W=12.0×180=2160 J W = 12.0 \times 180 = 2160 \text{ J} W=12.0×180=2160 J

Resistance

When charge flows through a component, it doesn't usually get a free ride. The moving electrons collide with the vibrating positive ions in the metal lattice of the wire or component. These collisions transfer energy away from the electrons (generating heat) and make it harder for the current to flow.

This opposition to the flow of current is called resistance.

Definition

Resistance

The resistance of a component is defined as the ratio of the potential difference across it to the current flowing through it.

Mathematically, this is written as:

R=VI R = \frac{V}{I} R=IV​

Where:

  • RRR is the resistance, measured in Ohms (Ω\OmegaΩ).
  • VVV is the potential difference, measured in Volts (V).
  • III is the current, measured in Amperes (A).

An Ohm is defined as 1 V A−11 \text{ V A}^{-1}1 V A−1. If a component has a resistance of 5 Ω5 \text{ } \Omega5 Ω, it means it requires exactly 5 Volts of "push" to make 1 Ampere of current flow through it.

Common Mistake

Resistance vs Ohm's Law

A very common mistake is calling V=I×RV = I \times RV=I×R "Ohm's Law". It isn't! R=VIR = \frac{V}{I}R=IV​ is simply the definition of resistance, and it applies to any component at any given moment, whether the component obeys Ohm's Law or not. Ohm's Law is a specific rule stating that III is strictly proportional to VVV (meaning RRR is constant), which only applies to certain conductors under constant temperature. We will cover this in detail in the next topic!

Measuring these basics in a circuit

To calculate the resistance of a component, you need to measure both VVV and III. You are expected to know how to construct a standard circuit to do this.

Standard circuit diagram with ammeter and voltmeter

Notice the placement of the meters:

  • Ammeters measure current (flow). They must be placed in series with the component so the charge flows through them.
  • Voltmeters measure potential difference (energy drop). They must be placed in parallel across the component to compare the energy of the charge before and after it passes through.
Example

Determining resistance from raw data

In a laboratory experiment, a student measures that 45 J of work is done when a component operates for 15 seconds. An ammeter in series with the component reads 0.50 A. Calculate the resistance of the component.

  1. Calculate the charge transferred:
ΔQ=I×Δt \Delta Q = I \times \Delta t ΔQ=I×Δt ΔQ=0.50×15=7.5 C \Delta Q = 0.50 \times 15 = 7.5 \text{ C} ΔQ=0.50×15=7.5 C
  1. Calculate the potential difference:
V=WQ V = \frac{W}{Q} V=QW​ V=457.5=6.0 V V = \frac{45}{7.5} = 6.0 \text{ V} V=7.545​=6.0 V
  1. Calculate the resistance:
R=VI R = \frac{V}{I} R=IV​ R=6.00.50=12 Ω R = \frac{6.0}{0.50} = 12 \text{ } \Omega R=0.506.0​=12 Ω

Exam technique

In the exam

  1. Watch your units: AQA loves giving time in minutes or hours, or current in milliamperes (mA). Always convert to standard SI units (seconds, Amperes) before touching the formulas.
  2. Define terms accurately: If an exam question asks "Define potential difference", do not write "V=W/QV = W/QV=W/Q". You must write the phrase "Work done per unit charge". Formulas do not score marks for definitions unless the question specifically allows it.
  3. Show your intermediate steps: In multi-step calculations like the ones above, write out the intermediate values (like finding QQQ first). If you make a mistake on the final line, you can still pick up error-carried-forward (ECF) marks.
Self review

Check yourself

  • Can you state the standard SI unit for charge, current, potential difference, and resistance?
  • If a steady current of 3 A flows, how many Coulombs pass a point in 10 seconds?
  • If you have an ammeter and a voltmeter, which one goes in series and which one goes in parallel?
  • Why is R=V/IR = V/IR=V/I technically not a statement of Ohm's Law?
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